Tutorials in Introductory Physics
Tutorials in Introductory Physics
1st Edition
ISBN: 9780130970695
Author: Peter S. Shaffer, Lillian C. McDermott
Publisher: Addison Wesley
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Chapter 6.1, Problem 4bT

Show that a simple application of the model for current that we have developed thus far is inadequate for determining how the brightness of bulb B changes when the switch is opened.

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The figure below shows a simplified model of a cardiac defibrillator, a device used to resuscitate patients in ventricular fibrillation. S R Rorso + The capacitor C charge through the resistor R (when the switch S is toggled to left) and discharge current through the patient's torso which is of resistance (when the switch S is toggled to right). This phenomenon allows the heart's normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 7.0 µF; ɛ = 1240 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 800 V in 2.1 s. (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1200 Q, calculate the voltage (in V) across the capacitor after 4.0 ms.
The capacitor in the circuit shown below is initially uncharged. The switch is closed at t=0 s. AVbattery = 30 V, C = 3.0 F, and R = 2.0 Q. At sometime after the switch is closed, the current in the circuit is measured to be 5.9 A. What is the charge on the capacitor at this time, in Coulomb? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. CH
When a steady current, I, is flowing through a conductor (e.g. the carbon paper here) with a non-negligible resistance, R, it will be possible to maintain a potential difference, ∆V = IR, between parts of the conductor along the direction of the current. Explain why in this situation there should be an electric field in the direction of the current but not in the direction perpendicular to the current.

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Tutorials in Introductory Physics

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