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Chapter 2 Solutions
Power System Analysis and Design (MindTap Course List)
- A single-phase, 120V(rms),60Hz source supplies power to a series R-L circuit consisting of R=10 and L=40mH. (a) Determine the power factor of the circuit and state whether it is lagging or leading. (b) Determine the real and reactive power absorbed by the load. (c) Calculate the peak magnetic energy Wint stored in the inductor by using the expression Wint=L(Irms)2 and check whether the reactive power Q=Wint is satisfied. (Note: The instantaneous magnetic energy storage fluctuates between zero and the peak energy. This energy must be sent twice each cycle to the load from the source by means of reactive power flows.)arrow_forwardA capacitor drawing 4 kvar is placed in parallel with the electro-magnet that draws 3 kW of active power and 4 kvar of reactive power.. a. Calculate the new value of apparent power b. What is the new value of reactive power? c. What is the value of active power? d. What is the new power factor?arrow_forward5) Find the reactance the inductance and impedance of the circuit. Calculate the current of this circuit and the sketch waveform of current and voltage. V1 10 V 60 Hz R1 m 100kQ 12 Vrms 1000 Hz 0° 6) Find the reactance the inductance and impedance of the circuit. Calculate the currents of this circuit R www 502 L L1 106mH eee 10 mHarrow_forward
- a) Calculate the power factor of the load shown in the figure without the capacitor. b) Determine the capacitance that will improve the power factor to unity (1.0). Function Generator 1 KHz 5 V rms OV DC offset Ground C 5 mH 30 Ωarrow_forward9.) Assume the frequency to be 60 Hz. Calculate the inductance or capacitance in series for the impedance 352 70° ohms. Express in four decimal places.arrow_forwardAn inductor L is connected in parallel to the series combination of capacitor C and resistor R. If L = 0.02122 H, C = 0.000421 F and R = 5 Ω, the impressed voltage E = 120 volts AC. Find the following: a. Circuit Diagram, total impedance, total current. b. Determine the frequency at which the inductive reactance is equal to capacitive reactance. c. Determine the voltage drop across the capacitor and the Quality Factor Q.arrow_forward
- Increasing the capacitance of an AC circuit causes the capacitive reactance to: O a) decrease. Ob vary directly proportional to the frequency. I c) increase. KO) stay the same. ac IIarrow_forwardAn inductor of value 5.6 H is connected across 240 V, 109 Hz supply. Then the value of inductive reactance is ohms. 7666.62 1220.80 1916.66 3836.80arrow_forwardAnswer the following: a. A capacitance is connected to a 115 V, 25 Hz mains and takes a current of 5 A. find the current when both the capacitance and frequency are doubled. b. A 220 V, 60 Hz circuit draws a current of 11 A with a power factor of 0.8 lagging. Find the resistance of the circuit.arrow_forward
- A 5 ohm resistor in series with an inductor having an inductance of L = 15.92 mH is connected to a voltage sourceof 110 volts 60 Hz. Determine the true power consumed by the load.arrow_forwardAn inductive impedance of 40 + j40 ohms is connected in parallel with a pure capacitor. What must be the reactance of the capacitor in ohms so that the total current is in phase with the supply voltage of 230V?arrow_forward3. A 3-phase, 50 Hz, 3000 V motor develops 600 H.P. (447-6 kW), the power factor being 0-75 lagging and the efficiency 0-93. A bank of capacitors is connected in delta across the supply terminals and power factor raised to 0-95 lagging. Each of the capacitance units is built of five similar 600-V capacitors. Determine the capacitance of each capacitor. [156 μF]arrow_forward
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning