Tutorials in Introductory Physics
1st Edition
ISBN: 9780130970695
Author: Peter S. Shaffer, Lillian C. McDermott
Publisher: Addison Wesley
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Chapter 10.4, Problem 1bT
To determine
To Explain: The distance of the bottom of the pencil closer to, farther from or the same distance from the observer.
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Students have asked these similar questions
An air bubble inside a plastic ball with a diameter of 20.0 cm is 7.0 cm from the surface. When you look at the ball in the configuration in the figure below (observer, center of the ball, and bubble are on the same straight line), at what distance from the center of the ball will the image form? Consider nₚₗₐₛₜ=1.6 and nₐᵣ = 1
a)5.85 cm to the right of the center of the ball
b)5.85 cm left of center of ball
c)4.85 cm right from center of ball
d)4.85 cm left from center of ball
e)3.85 cm right from center of ball
f)3.85 cm left from center of ball
g)6.85 cm right from center of ball
h)6.85 cm left from center of ball
i)7.85 cm right from center of ball
j)7.85 cm left from center of ball
Please refer to part (b) of Figure 1
Here, theta (the angle the incident ray makes with respect to the vertical) is 24.2
degrees. What is d (the distance between the ray emerging from the bottom of the glass and where the ray would have been if it had
continued straight on with no glass to refract it)?
0.54 m
0.16 m
0.76 m
0.86 m
E
F
D
В
Here, we're looking down on a room with 6 people. The bottom wall
(including point X) and the left wall are mirrored. Person F fires a
laser beam at point X. Who gets hit by the laser? In your answer
below, include your reasoning and reflected angles for full credit. If
more than one person is in the possible path, indicate that as well
(the first person might duck out of the way!).
Chapter 10 Solutions
Tutorials in Introductory Physics
Ch. 10.1 - Prob. 1aTCh. 10.1 - Predict how each of the following changes would...Ch. 10.1 - A mask with a circular hole is placed between a...Ch. 10.1 - What do your observations suggest about the path...Ch. 10.1 - Imagine that you held a string of closely spaced...Ch. 10.1 - The mask used in parts C-E is replaced by one that...Ch. 10.1 - Prob. 1gTCh. 10.1 - Predict what you would see on the screen when an...Ch. 10.1 - Predict the size of the lit region on the screen...Ch. 10.1 - Suppose that the bulb were replaced by a long...
Ch. 10.1 - Prob. 2cTCh. 10.1 - Predict what you would see on the screen at the...Ch. 10.1 - Suppose that the light from the top bulb in the...Ch. 10.1 - Predict what you would see on the screen in the...Ch. 10.2 - Close one eye and lean down so that your open eye...Ch. 10.2 - Suppose that you placed your finger behind the...Ch. 10.2 - Prob. 1cTCh. 10.2 - Prob. 1dTCh. 10.2 - Place your head so that you can see the image of...Ch. 10.2 - Move the nail off w the right side of the mirror...Ch. 10.2 - Prob. 3aTCh. 10.2 - Turn the large sheet of paper over (or obtain a...Ch. 10.2 - Remove the mirror and the object nail. For each...Ch. 10.2 - On the diagram at right, draw one ray from the pin...Ch. 10.2 - Prob. 4bTCh. 10.2 - Determine the image location using the method of...Ch. 10.3 - A pin is placed In front of a cylindrical mirror...Ch. 10.3 - Could you use any two rays (even those that do not...Ch. 10.3 - Observers at M and N arc looking at an image of...Ch. 10.3 - Stick a pin into a piece of cardboard and place...Ch. 10.3 - Gradually decrease the angle between the mirrors...Ch. 10.4 - Prob. 1bTCh. 10.4 - Three students are discussing their results from...Ch. 10.4 - For each case shown below, determine and label the...Ch. 10.4 - In each of the previous cases, predict what would...Ch. 10.4 - Prob. 2cTCh. 10.4 - Explain how you can use a screen to determine the...Ch. 10.5 - Look at very distant object through a convex lens....Ch. 10.5 - Consider a point on the distant object that is...Ch. 10.5 - Suppose that you placed a very small bulb at the...Ch. 10.5 - Consider the ray chai is parallel to the principal...Ch. 10.5 - Consider the ray that goes through the focal point...Ch. 10.5 - How can you use these two rays to determine the...Ch. 10.5 - Consider the ray from the easer that strikes the...Ch. 10.5 - Draw the continuation of the two remaining rays...Ch. 10.5 - Prob. 2fTCh. 10.5 - The diagram below shows a small object placed near...Ch. 10.5 - A lens, a bulb, and a screen are arranged as shown...Ch. 10.5 - Obtain the necessary equipment and check your...Ch. 10.5 - Prob. 3cTCh. 10.6 - The diagram at right illustrates what an observer...Ch. 10.6 - Obtain two soda cans and a cardboard tube that has...Ch. 10.6 - Could an observer at each of the labeled points...Ch. 10.6 - Use the above diagram to answer the following...Ch. 10.6 - Obtain convex lens. Use the lens as a magnifying...Ch. 10.6 - Draw a ray diagram that shows how to determine the...Ch. 10.6 - The lateral magnification, m1 , is defined as...Ch. 10.6 - The angular magnification, m , is defined as m= ,...
Knowledge Booster
Similar questions
- Consider this word problem (diagram below): "Light in air (shown in blue) is incident at a 53 degree angle on a dense transparent material B (shown in green). After refraction, the light takes a path inside material B that forms a 37 degree angle with the normal line. Find "n", the index of refraction, of this material." In the diagram below, after the light passes from air (blue) into material B (green), it bends the normal line. [choose "toward" or "away from"] air n=1 53⁰ 1 B Your answer 37°arrow_forwardThe diagram at the right shows light refracting from material A into material B. The index of refraction of material A is 2.24. Use your protractor to measure angles and determine the index of refraction of material B. (HINT: The angle measures are multiples of 15 degrees.)arrow_forwardCould you please show the correct steps to solving this problem? The answer is shown in red, I'm just not sure what steps to take to solve this.arrow_forward
- Please refer to part (b) of Figure 1 included with this quiz. Here, theta (the angle the incident ray makes with respect to the vertical) is 40.2 degrees. What is d (the distance between the ray emerging from the bottom of the glass and where the ray would have been if it had continued straight on with no glass to refract it)? 0.34 m 1.57 m 1.79 m 1.12 marrow_forwardIn some of the images there appears to be a secondary source of light that is coming from the same light source. Considering that water was used to view and photograph the path of light beam explain the existence of the apparent second light source. See image below for an example.arrow_forwardThe two mirrors illustrated in the figure below meet at a right angle. The beam of light in the vertical plane indicated by the dashed lines strikes mirror 1 as shown. (Let d = 1.05 m and 0 = 35.0°.) Mirror 2 d Mirror (a) Determine the distance the reflected light beam travels before striking mirror 2. (b) In what direction does the light beam travel after being reflected from mirror 2? o above the horizontal Need Help? Watch It Read Itarrow_forward
- A concave lens refracts parallel rays in such a way that they are bent away from the axis of the lens. For this reason, a concave lens is referred to as a diverging lens. Part A: Consider the following diagrams, where F represents the focal point of a concave lens. In these diagrams, the image formed by the lens is obtained using the ray tracing technique. Which diagrams are accurate?(Figure 1) *Type A if you think that only diagram A is correct, type AB if you think that only diagrams A and B are correct, and so on. Part B: If the focal length of the concave lens is -7.50 cm , at what distance d_o from the lens should an object be placed so that its image is formed 3.70 cm from the lens?arrow_forwardIn the figure below, a light ray travels from point P in medium 1 to point Q in medium 2. The two points are, respectively, at perpendicular distances a and b from the interface. The displacement from P to Q has the component d parallel to the interface, and we let x represent the coordinate of the point where the ray enters the second medium. Let t = 0 be the instant the light starts from P.a) Show that the time at which the light arrives at Q is: b) To obtain the value of x for which t has its minimum value, differentiate t with respect to x and set the derivative equal to zero. Show that the result implies c)Show that this expression in turn gives Snell's law,arrow_forwardin step 1 why is the image distance -4 cm?arrow_forward
- One well-known image of a prism is the following picture a. Given the pattern of light on the far side of the prism, is the index of refraction inside the prism higher or lower than the index of refraction outside the prism? b. List at least one thing that is wrong with this diagram given what we expect the dependence of n on the wavelength of light to be (and assuming the prism is made of a uniform material). c. List at least one thing that is right with this diagram given what we expect the dependence of n on the wavelength of light to be (and assuming the prism is made of a uniform material).arrow_forwardPreliminary Questions 1. Is the image projected on a movie screen real or virtual? What about the image of yourself seen in a bathroom mirror? 2. Hold a shiny spoon in front of you. What differences do you notice about the image of your face seen in the convex and concave sides? 3. Where are the images formed by each side of the spoon? In front or behind the spoon? (Try the parallax method. Look at the image of an overhead light. Hold the tip of a pencil where think the image is. Move your head from side to side. If the image and pencil tip appear to you move relative to each other, adjust the position of the pencil back and forth until they appear to move as one.)arrow_forwardLook at the central transparent area of someone’s eye, the pupil, in normal room light. Estimate the diameter of the pupil. Now turn off the lights and darken the room. After a few minutes turn on the lights and promptly estimate the diameter of the pupil. What happens to the pupil as the eye adjusts to the room light? Explain your observations.arrow_forward
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