Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 1, Problem 16P
Interpretation Introduction
Interpretation:
The
Concept introduction:
The
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Peptides.
1. Draw the peptide Ala-Glu-Gly-Lys, as it would occur at physiological pH = 7.4.
The R groups of Ala and Gly are not acidic or basic, therefore do not have a pka and the charge
on these R groups is therefore independent of pH. Glu is acidic and Lys is basic, therefore the
charge on these amino acids is pH dependent. The pKas are shown below.
pKa
N-term = 9.0
C-term = 3.5
Glu4.1
Lys = 10.5
2. Draw a circle around the peptide bonds.
3. Label the C-terminus and the N-terminus.
4. What is the overall charge on the peptide at pH 7.4?
I. Buffer Preparation
A researcher in Biochemistry is isolating α-glucosidase enzyme from malted wheat flour. The protocol requires the use of 2.00L of 0.225 M of lactate buffer with pH of 4.25. How will he/she prepare this buffer from 2.00 M lactic acid solution and solid sodium lactate (NaC3H5O3) The Ka of lactic acid is 1.38 x 10-4. [ Na=23.0, C=12.0, H=1.01, O=16.0 g/mol]
Choice and Preparation of a Buffer System1. Choosing the proper buffer solution
In Protein Precipitation, two liters of 5mM buffer solution with pH 5.2 is needed in the isolation of albumin. Which among the following buffer solution is best fitted for said purpose? Justify your answer.Buffer solutions pKa Acetate buffer 4.73Tris- (hydroxymethy) aminomethane 8.08Phosphate buffer 7.20
2. Preparation of the chosen buffer system
Calculate and measure the amounts (in grams if solid and in mL if liquid) of weak acid and conjugate base needed to be able to prepare the chosen buffer system in part A above. Express your answer in useful units (that is, prepare it from practical amounts or concentrations of starting materials).
Chapter 1 Solutions
Biochemistry
Ch. 1 - Prob. 1PCh. 1 - Prob. 2PCh. 1 - Prob. 3PCh. 1 - Prob. 4PCh. 1 - Prob. 5PCh. 1 - Prob. 6PCh. 1 - Prob. 7PCh. 1 - Prob. 8PCh. 1 - Prob. 9PCh. 1 - Prob. 10P
Ch. 1 - Prob. 11PCh. 1 - Prob. 12PCh. 1 - Prob. 13PCh. 1 - Prob. 14PCh. 1 - Prob. 15PCh. 1 - Prob. 16PCh. 1 - Prob. 17PCh. 1 - Prob. 18PCh. 1 - Prob. 19PCh. 1 - Prob. 20PCh. 1 - Prob. 21PCh. 1 - Prob. 22PCh. 1 - Prob. 23PCh. 1 - Prob. 24PCh. 1 - Prob. 25PCh. 1 - Prob. 26PCh. 1 - Prob. 27PCh. 1 - Prob. 28PCh. 1 - Prob. 29PCh. 1 - Prob. 30PCh. 1 - Prob. 31PCh. 1 - Prob. 32PCh. 1 - Prob. 33PCh. 1 - Prob. 34PCh. 1 - Prob. 35PCh. 1 - Prob. 36P
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- Ions in the human body. What will happen to our body if there is an imbalance of any ions or certain trace ions in the body? Explain well.arrow_forwardatoms. 12 hydrogens, 6 oxuger Click or tap here to enter text.C atoms. 12) Back to the person who ate 300 grams of glucose, how many moles of glucose is this? Click or tap here to enter text. There are 2 moles. 13) If a person were to eat this much glucose all at once (that is a lot of sugar) and all this sugar enters the blood then the person's blood sugar concentration would rise. Imagine that all this glucose is released into the 5 liters of blood that circulate in this person. What would be the molarity of glucose in the blood? Click or tap here to enter text. 14) After each of these glucose molecules enter the blood they are uptaken through cell membranes to enter cells. Within these cells glucose is broken down in a series of steps releasing carbon dioxide along the way. For every molecule of glucose broken down how many molecules of carbon dioxide are created? Refer to the cellular respiration equation: Equation for Cellular Respiration: How to break down a carb C6H12O6 + 60₂ ➜…arrow_forwardQuantitative Estimation of Amino Acids by Ninhydrin http://vlab.amrita.edu/?sub=3&brch=63&sim=156&cnt=2 can u help me with question 2 of the assignment questions Based on the experimental data provided, estimate the amount of amino acid in the given unknown solution by Ninhydrin method. SI No. Volume of standard amino acid solution (ml) Amount of amino acid (µg) OD at 570nm 1 Blank 0 2 0.2 0.12 3 0.4 0.25 4 0.6 0.45 5 0.8 0.55 6 1.0 100 0.68 7 Unknown (0.5ml) 0.41arrow_forward
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