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- The proton NMR spectrum in Figure 19-40 is for a compound having an empirical formula C4H7BrO2. Identify the compound.7) The correct structure that corresponds to the spectroscopic data given below is [IR 2720, 1710 1 point cm*1. 1H NMR 9.80(s, 1H), 7.50(dd, J = 8,0Hz, 2Hz, 1H), 7.40(d, J = 2.0Hz, 1H), 6.90(d, J = 8.0Hz, 1H), 3.90(s, 3H), 3.80(s, 3H)] COOH OMe Me CHO OMe OMe CHO OMe OMe COOH OMe MeLike hydrogen, fluorine-19 (abundance 100%) has a nuclear spin quantum number, I = 1/2. Therefore, 19F spin couples with 1H nuclei and split 1H NMR signals by following n + 1 rule in a fluorine containing compound. However, the 1H-19F coupling constants are much larger than the 1H-1H coupling constants. For example, 2JH-F is about 45-50 Hz whereas 3JH-F is about 20-22 Hz. A compound with the formula C2H4BrF has the following NMR spectrum. Draw the structure for this compound. Using the Hertz values on the expansions, calculate the coupling constants and completely explain the spectrum by drawing splitting diagrams for each equivalent hydrogen.
- In a 300 MHz NMR spectrometer, A) what is the Larmor frequency in MHz of a 15N nucleus? g H = N 26.752; g = 2.7126; B) Using the same NMR instrument, suppose that a 13C nucleus from a sample generates a signal which has a frequency of 11,250 Hz higher than that from the carbons in TMS. What is the chemical shift of that carbon atom from the sample? A) 30 MHz; B) 0.15 ppm OA) 25 MHz; B) 0.35 ppm A) 35 MHz; B) 0.30 ppm OA) 25 MHz; B) 0.55 ppm9 Shown below is the ¹⁹F nmr of XeF5¹. Given the isotopic abundance of ¹⁹F is 100%, with nuclear spin of ½2, and 12⁹Xe is 26.4% abundant with nuclear spin of ½, explain the spectrum. 40.0 JXeF = 3400 Hz 35.0 dWhat would be the ratio N(-1/2)/N(+1/2) of the number of protons in spin state (-1/2) over (+1/2) state at a very low temperature of 3K (liquid He boiling pt) and in a 800 MHz NMR spectrometer?
- Which nucleus in the structure below will give rise to the splitting pattern shown? Ha Hb Но Coupling constants: 2Jab = 2 Hz; 3Jac = 18 Hz; 3Jbc = 10 Hz; 3JaF = 20 Hz; 3JbF = 50 Hz; 2JcF = 84 Hz. Select one alternative: Ha HcTrue or False : The difference in energy, ΔE, between alfa (+1/2) and beta (–1/2) spin states of a proton is independent of the strength of the applied magnetic field. Could you explain detail?The volatile organic compounds (VOCs) produced by decomposing tissue and organs were studied in an effort to identify possib human-specific markers (PLoS ONE 2015 10(9): e0137341.). Of 452 VOCs isolated, six were found to be unique to humans, so th prove to be a useful tool for forensic chemists trying to determine the source of unidentified remains. There are two doublets in expected ¹H NMR spectrum of the following human-specific VOC. Identify the protons giving rise to each doublet. 1 2 H3C H3C- оооооооо 238 H 8 HH HH 3 HH CH3 5 7 Identify the two groups of protons that give rise to the doublets in the spectrum. CH3 8
- What is the structure from the formula C9H12O and the spectra?4. A compound having the molecular formula CsH10O2 exhibits the following 'H-NMR-Figure 4a Figure 4a Figure 4b Multiplet @ 1.46 ppm Multiplet @ 1.22 ppm Triplet @ 2.20 ppm Triplet @ 0.78 ppm PPM and 13C-NMR-Figure 4b spectra. Identify the compound. The spin multiplicities are indicated below. 'H-NMR (400 MHz, CDCI3 at 300K) 8: 11.8 (s), 2.20 (t), 1.46 (m), 1.22 (m), 0.78 (t). 13C-NMR (400 MHz, CDCI3 at 300K) 8: 180.8 (s), 33.8 (t), 26.8 (t), 22.4 (t), 3.58 (q).How many peaks woudl be observed in the 1H and 13C NMR specutrms of the following compounds?