9Shown below is the ¹⁹F nmr of XeF5¹. Given the isotopic abundance of ¹⁹F is 100%, withnuclear spin of ½2, and 12⁹Xe is 26.4% abundant with nuclear spin of ½, explain thespectrum.40.0JXeF= 3400 Hz35.0d

Given a 19F NMR spectra of [XeF5]–. Isotopic abundance of 19F is 100% and isotopic abundance of…

Shown below is the ¹9F nmr of XeF5¹. Given the isotopic abundance of 1⁹F is 100%, with nuclear spin of ½, and 129Xe is 26.4% abundant with nuclear spin of ½, explain the spectrum. 40.0 XeF == 3400 Hz 35.0 d

Shown below is the ¹9F nmr of XeF5¹. Given the isotopic abundance of 1⁹F is 100%, with nuclear spin of ½, and 129Xe is 26.4% abundant with nuclear spin of ½, explain the spectrum. 40.0 XeF == 3400 Hz 35.0 d

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter19: Nuclear Magnetic Resonance Spectroscopy

Section: Chapter Questions

Problem 19.20QAP

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Question

9
Shown below is the ¹⁹F nmr of XeF5¹. Given the isotopic abundance of ¹⁹F is 100%, with
nuclear spin of ½2, and 12⁹Xe is 26.4% abundant with nuclear spin of ½, explain the
spectrum.
40.0
JXeF
= 3400 Hz
35.0
d

Expert Solution

Step 1

Given a ¹⁹F NMR spectra of [XeF₅]^–. Isotopic abundance of ¹⁹F is 100% and isotopic abundance of 26.4% with nuclear spin of 1/2 .

We have to explain the given spectrum.

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