Concept explainers
Interpretation:
The table is to be completed.
Concept introduction:
Answer to Problem 38E
The table is completed as shown below.
Gas | Molecules | Mass | STP Volume |
ozone, |
|||
carbon dioxide, |
|||
carbon monoxide, |
Explanation of Solution
The table to be completed is given below.
Gas | Molecules | Mass | STP Volume |
ozone, |
|||
carbon dioxide, |
|||
carbon monoxide, |
The number of molecules of ozone,
The formula to determine the number of moles is given below.
The Avogadro’s number is
Substitute the number of molecules of
At STP,
The unit factors are given below.
Therefore, the volume occupied by
Therefore, the volume occupied at STP is
The molar mass of
The unit factor to calculate grams of
The formula to determine the mass of
Substitute the volume of
Therefore, the mass of
The mass of carbon dioxide,
The molar mass of carbon dioxide,
The formula to determine the number of moles is shown below.
Substitute the mass and molar mass of
At STP,
The unit factors are given below.
Therefore, the volume occupied by
Therefore, the volume occupied by
The number of molecules in
The number of molecules in
Therefore, the number of molecules of
The volume of carbon monoxide,
At STP,
The number of moles of
At STP,
Therefore, the number of molecules in
Therefore, the number of molecules in
The molar mass of
Substitute the moles and molar mass of
Therefore, the mass of
The table is therefore completed as shown below.
Gas | Molecules | Mass | STP Volume |
ozone, |
|||
carbon dioxide, |
|||
carbon monoxide, |
The table is completed has been rightfully completed.
Want to see more full solutions like this?
Chapter 8 Solutions
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
- Two general chemistry students working together in the lab weigh out 0.832 g of CaCl2 2 H2O into a crucible. After heating the sample for a short time and allowing the crucible to cool, the students determine that the sample has a mass of 0.739 g. They then do a quick calculation. On the basis of this calculation, what should they do next? (a) Congratulate themselves on a job well done. (b) Assume the bottle of CaCl2 2 H2O was mislabeled; it actually contained something different. (c) Heat the crucible again, and then reweigh it.arrow_forwardA 12.1-g sample of Na2SO3 is mixed with a 14.6-g sample of MgSO4. What is the total mass of oxygen present in the mixture?arrow_forward3.83 For the reaction of nitrogen, N2, and hydrogen, H2, to form ammonia, NH3, a student is attempting to draw a particulate diagram, as shown below. Did the student draw a correct representation of the reaction? If not, what was the error the student made?arrow_forward
- 1. Which of the following hydrocarbons has the highest mass percentage of carbon? methane, CH4 ethane, C2H6 propane, C3H8 butane, C4H10arrow_forwardOn average the body is 60% water by mass. How many water molecules are present in a 68 kg person (about 150 lb) assuming they are 60% water by mass?arrow_forwardConvert 1.43 x 10^23 molecules/formula units of X5Z3 into grams of the same compound. (Assume that the molar mass of X is 24 grams per mole and the molar mass of Z is 52.75 grams per mole.) Assume that Avogadro's number is 6.022 x 1023. Report your answer to three decimal places.arrow_forward
- assuming a person breathes 900 grams of oxygen per day 2. Using the proper chemical equation, how much KCIO3 in grams would you need to provide enough oxygen to meet the needs of 1 person for one week?arrow_forwardA sample of a compound has a mass of 42.66 g with 1.06 x 10-1 mol. What is the molecular mass of the compound? DO NOT ENTER the UNIT, and do NOT USE scientific notation. Aarrow_forwardThe compound phthalic acid consists of carbon, hydrogen and oxygen. When a 1.969 g sample of phthalic acid undergoes combustion analysis, 4.172 g CO₂ and 0.641 g H₂O are produced. From this information to determine the empirical formula of phthalic acid. Use the drop-down menus to select the correct subscript for each element. The empirical formula for phthalic acid is: C H Oarrow_forward
- The density of water is 1.00 g/mL at 4°C.How many water molecules are present in 2.36 mL of water at this temperature? 5.59 X 10 22 molecules 8.56 X 10 22 molecules 7.89 X 10 22 molecules 6.56 X 10 22 moleculesarrow_forwardA sample of gas mixture from a neon sign contains 3.48 x 10-4 mol Ne and 1.12 x 10- mol Kr. What are the mass percentages of Ne and Kr in the gas mixture? Mass percentages of Ne = % Mass percentages of Kr = %3Darrow_forwardHow many molecules are there in 62.3 g of water? You will need to divide your answer by 1.0x10^23.arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781285199030Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning