Concept explainers
If the vector components of the position of a particle moving in the xy plane as a function of time are
Trending nowThis is a popular solution!
Chapter 5 Solutions
Physics for Scientists and Engineers: Foundations and Connections
- For t 0, an object of mass m experiences no force and moves in the positive x direction with a constant speed vi. Beginning at t = 0, when the object passes position x = 0, it experiences a net resistive force proportional to the square of its speed: Fnet=mkv2i, where k is a constant. The speed of the object after t = 0 is given by v = vi/(1 + kvit). (a) Find the position x of the object as a function of time. (b) Find the objects velocity as a function of position.arrow_forwardExpress the force F as a vector in terms of the unit vectors i, j, and k. Determine the angles 0x, 0y, and 0, which F makes with the positive x-, y, and z-axes. 2, mm | В (-25, 50, 40) F = 750 N y, mm А (15, -20, -25) X, mmarrow_forwardIn the figure, a force P acts on a block weighing 45.0 N. The block is initially at rest on a plane inclined at angle = 18.0° to the horizontal. The positive direction of the x axis is up the plane. The coefficients of friction between block and plane are μ = 0.540 and Uk = 0.340. In unit-vector notation, what is the frictional force on the block from the plane when Pis (a) (-5.30 N)î, (b) (-8.10 N)î, and (c) (-15.1 N)? (a) Number i (b) Number i (c) Number i i+ i+ i i i+ i j Units j Units j Unitsarrow_forward
- A 3.5 kg particle moves along an x axis according to x(t) = −12 + 5t2 − 4t3, with xin meters and t in seconds. In unit-vector notation, what is the net force acting on theparticle at t = 6 s?arrow_forwardThree force vectors act on a free body at the origin as shown. F1= 4 N F2=2.0 i + 3.1 J N F3= 6.3 N at 35° relative to positive x axis. a) Report the unit vector in the direction of F3 (in unit vector or i,j,k notation to 4 sig figs) b)Calculate the resultant force R, which is the sum of the three forces F1,F2, and F3 (in unit vector or i,j,k notation to 4 sig figs)arrow_forwardChapter 05, Problem 010 GO A 0.180 kg particle moves along an x axis according to x(t) = - 14.0 + 2.00 t + 4.00 2- 5.00 t, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.30 s ? Give an expression for the (a) x, (b) y and (c) z components. (a) Number Units (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER powered by MapleNet ere to search 1:51 PM ENG 4/4/2021 ASUS 19home prt sc pause break delete f10 end f1Pgup f12Pgdn insert & 21 4. 8 backspo-arrow_forward
- : A particle of mass m has the following position vector as a function of time t r(t) = At3ˆi + Bt2ˆj + Ctˆk where A, B, and C are constants. At t = τ , two external forces −→F1 =αˆi+βˆj+γ ˆk and −→F2 act on the particle where α, β, and γ are constants. Find −→F2 at that instant.arrow_forwardA horizontal line PQRS is 12 m long, where PQ = QR = RS = 4 m. Forces of 1000 N, 1500 N, 1000 N and 500 N act at P, Q, R and S respectively with downward direction. The lines of action of these forces make angles of 90°, 60°, 45° and 30° respectively with PS. Find the magnitude, direction, and position of the resultant force.arrow_forwardA block of mass M2 = 8.45 kg on a frictionless plane inclined moving down at angleθ2 = 50° is connected by a cord over a massless, frictionless pulley to a second block of mass M1= 5.36 kg on a horizontal surface. The coefficient of kinetic friction between M1 and the surfaceis μk = 0.15, and the Force F = 11.3 N is acting on M1 at angle θ1 = 30° to the horizontal. (a)draw a free body diagram for each block in the system. (b) What is the acceleration for M1? (c)What is the tension in the cord? (d) After M2moves 10 cm, what is the velocity of M1? (Thesystem was initially at rest)arrow_forward
- A particle moving in the xy plane follows a path described as a function of time by i(t) = (3.4 m/s)tî - (2.8 m/s?)tj. A constant force given by F = (5.0î - 2.0j) N acts on the particle (note that other forces must act on the particle as well if it follows the path given above). (a) Determine the displacement of the particle during the interval t = 1.0 s to t = 4.0 s. AT = îm - m (b) Calculate the work done by F during this interval. W =arrow_forwardA particle is moving in one dimension along the x-axis starting from the initial position xo at t = 0. If a constant force is acting on the particle, the trajectory of x(f) will be, (a) ê (c) (d) x(1) x(1) x(1) x(1)arrow_forwardThe figure shows an overhead view of a 0.027 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F 1 has a magnitude of 8 N and is at 01 = 32°. Force F 2 has a magnitude of 9 N and is at 62 = 33°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (10î – 13j) m/s, and (c) has the (12tî – 11í) m/s?, where t is time? (a) Number i i+ i jUnits (b) Number i i+ i j Units (c) Number i i+ i j Unitsarrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning