Concept explainers
What is the output of the following code segment?
else
- Purple
- Gold
- PurpleGold
- nothing
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Microsoft Visual C#
- int a = 4, b;b = a-- + 2;What is the value of b in the above code? a. 7 b. 6 c. Error d. 5arrow_forwardAnalyze the following code: int x = 0;int y = ((x < 100) && (x > 0)) ? 1: -1; The code has syntax error. y becomes 1 after the code is executed. y becomes -1 after the code is executed. The code has run time error.arrow_forwardAssign Barbecue's data member numberOfCalories with a value read from input. Then, assign Ham and Cheese's data member numberOfCalories with another value read from input. Input will contain two integer numbers. Only the *your code goes here can be affected, the rest of the program cannot be changed. Program below: ----------------------------#include <iostream>#include <vector>#include <string>using namespace std; struct PizzaInfo {string pizzaName;int numberOfCalories;}; int main() {vector<PizzaInfo> availablePizzas(2); availablePizzas.at(0).pizzaName = "Barbecue";availablePizzas.at(1).pizzaName = "Ham and Cheese"; /* Your code goes here */ cout << "A " << availablePizzas.at(0).pizzaName << " slice contains " << availablePizzas.at(0).numberOfCalories << " calories." << endl;cout << "A " << availablePizzas.at(1).pizzaName << " slice contains " << availablePizzas.at(1).numberOfCalories << "…arrow_forward
- What is the value of num3 after the following code is executed: int num1 = 5; int num2 = num1 * 3; int num3; if ((num1 >= 5) && (num2 5) && (num2 < 10)) {num3 = 50;} else {num3 = 6;} System.out.println(num3);arrow_forwardchar letter1; char letter2; letter1 = 'y'; while (letter1 <= 'z') { letter2 = 'a'; while (letter2 <= 'c'){ System.out.print("" + letter1 + letter2 + " "); ++letter2; } ++letter1; } For this code why did we use "" before and after in this line? System.out.print("" + letter1 + letter2 + " "); ++letter2; What if we don't use the blank quotation would the output be same? because I don't see the reason for putting those quotation mark.arrow_forwardWhat does the following code segment display? for(f=0; f<3; ++f); write ("{0} ", f); a. 0 b. nothing c. 3 d. 0 1 2arrow_forward
- English (e what is the output of the following program? #include int test (int &, int); main () { int a=10, b=15; test (b, a); test (a,b); cout<arrow_forwardnum1 = int(input("Enter first value:"))num2 = int(input("Enter second value:"))num3 = int(input("Enter third value:")) # Type your code after this line. if (num1 >= num2) and (num1 >= num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num1 )elif (num2 >= num1) and (num2 >= num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num2 )elif (num3 >= num1) and (num3 >= num2):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num3 ) What is wrong with thisarrow_forwardnum1 = int(input("Enter first value:"))num2 = int(input("Enter second value:"))num3 = int(input("Enter third value:")) # Type your code after this line. if (num1>=num2)and(num1>=num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num1)elif (num2>=num1) and (num2>=num3):print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num2) else:print("Enter first value:" "Enter second value:" "Enter third value:" 'Largest value is:' , num3) When i run it, it states enter first value, enter second value, and enter third value, twicearrow_forwardWhat is the value of x after the following code executes? int x=10; if(x++ >10) { x =13; } a. 10 b.9 c.13 d.11arrow_forwardThe value of x at the end.int x = 1;x = x + 1;x++;arrow_forwardX3: inlTo10 Write a function in Java that implements the following logic: Given a number n, return true if n is in the range 1..10, inclusive. Unless "outsideMode" is true, in which case return true if the number is less or equal to 1, or greater or equal to 10.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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