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What is the output of the following?
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- int a = 10, b =7; System.out.println(a>b?a:b); Will always print what?arrow_forward#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…arrow_forward#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…arrow_forward
- #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…arrow_forward#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…arrow_forwardWhat is the value of num3 after the following code is executed: int num1 = 5; int num2 = num1 * 3; int num3; if ((num1 >= 5) && (num2 5) && (num2 < 10)) {num3 = 50;} else {num3 = 6;} System.out.println(num3);arrow_forward
- Void Do1 (int: &, a. int &b) { a = 5; a = a + b; b = a + 2; } Int main() { Int x = 10; Do1 (x,x); Cout << x << endl; } The output of this program isarrow_forwardThe value of x at the end.int x = 1;x = x + 1;x++;arrow_forwardFinancial Application:• Write a program that computes future investment value at a given interest rate for aspecified number of months and prints the report shown in the sample output. • Given the annual interest rate, the interest amount earned each month is computedusing the formula: Interest earned = investment amount * annual interest rate /1200 (=months * 100) • Write a method, computeFutureValue, which receives the investment amount, annualinterest rate and number of months as parameters and does the following: o Prints the interest amount earned each month and the new value of theinvestment (hint: use a loop). o Returns the total interest amount earned after the number of months specified bythe user. The main method will:o Ask the user for all input needed to call the computeFutureValue method.o Call computeFutureValueo Print the total interest amount earned by the investment at the end of thenumber of months entered by the user. Sample Program runningEnter the investment…arrow_forward
- Guessing game: Read a number until it's equal to a chosen number (first it can be a hard-coded constant or #define, or you can check rand() later). In case of wrong guessing help the user by printing whether the guessed number is to small or too big. ( in C language)arrow_forwardint main(){ if(var1>50) { num = 20.0 } else { if(var1>35) ---- Line 7 { num= 35.0; } else if (var1<80) { num=60.0; } else { num=40.0; }} What should be the outcome of the condition in line 7 in order for the value of num to be equal to 60.0?arrow_forwardAnalyze the following code: int x = 0;int y = ((x < 100) && (x > 0)) ? 1: -1; The code has syntax error. y becomes 1 after the code is executed. y becomes -1 after the code is executed. The code has run time error.arrow_forward
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