Concept explainers
(a)
The distance between the object and the screen.
(a)
Answer to Problem 66P
The distance between the object and the screen is
Explanation of Solution
Given info: The focal length of the left and right lenses are
Write the expression of thin lens equation for lens 1.
Here,
Substitute
Write the expression for magnification.
Substitute
Write the expression of magnification for a combination of two lenses.
Substitute
Write the expression to calculate the magnification for lens 2.
Substitute
Write the expression of thin lens equation for lens 2.
Here,
Substitute
Substitute
The distance between the object and the screen is,
Substitute
Thus, the distance between the object and the screen is
Conclusion:
Therefore, the distance between the object and the screen is
(b)
The displacement of each lens from its initial position.
(b)
Answer to Problem 66P
The displacement of each lens from its initial position is
Explanation of Solution
Given info: The focal length of the left and right lenses are
Write the expression of thin lens equation for lens 1.
Here,
Substitute
Write the expression of magnification for lens 1.
Substitute
Write the expression of magnification for the combination of lenses.
Substitute
Write the expression to calculate the magnification of lens 2.
Substitute
Write the expression of lens equation for lens 2.
Substitute
Substitute
The distance between the object and the screen is,
Substitute
Solve the above quadratic equation to find the value of
When the value of
The displacement of object is,
Substitute
The displacement of the image is,
When the value of
The displacement of object is,
Substitute
The displacement of the image is,
Thus, the displacement of each lens from its initial position is
Conclusion:
Therefore, the displacement of each lens from its initial position is
(c)
Whether the lens can be displaced by more than one way.
(c)
Answer to Problem 66P
It is possible to displace the lens in more than one way.
Explanation of Solution
Given info: The focal length of the left and right lenses are
Yes the lens can be displaced in more than one way.
The first lens can be displaced
Another way is, the first lens can be moved
Thus, it is possible to displace the lens in more than one way.
Conclusion:
Therefore, it is possible to displace the lens in more than one way.
Want to see more full solutions like this?
Chapter 26 Solutions
Principles of Physics: A Calculus-Based Text
- A converging lens made of crown glass has a focal length of 15.0 cm when used in air. If the lens is immersed in water, what is its focal length? (a) negative (b) less than 15.0 cm (c) equal to 15.0 cm (d) greater than 15.0 cm (e) none of those answersarrow_forwardIn Figure P35.30, a thin converging lens of focal length 14.0 cm forms an image of the square abed, which is he = hb = 10.0 cm high and lies between distances of pd = 20.0 cm and pa = 30.0 cm from the lens. Let a, b, c. and d represent the respective corners of the image. Let qa represent the image distance for points a and b, qd represent the image distance for points c and d, hb, represent the distance from point b to the axis, and hc represent the height of c. (a) Find qa, qd, hb, and hc. (b) Make a sketch of the image. (c) The area of the object is 100 cm2. By carrying out the following steps, you will evaluate the area of the image. Let q represent the image distance of any point between a and d, for which the object distance is p. Let h represent the distance from the axis to the point at the edge of the image between b and c at image distance q. Demonstrate that h=10.0q(114.01q) where h and q are in centimeters. (d) Explain why the geometric area of the image is given by qaqdhdq (e) Carry out the integration to find the area of the image. Figure P35.30arrow_forwardAn observer to the right of the mirror-lens combination shown in Figure P36.89 (not to scale) sees two real images that are the same size and in the same location. One image is upright, and the other is inverted. Both images are 1.50 times larger than the object. The lens has a focal length of 10.0 cm. The lens and mirror are separated by 40.0 cm. Determine the focal length of the mirror.arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill