Chemical Principles in the Laboratory
Chemical Principles in the Laboratory
11th Edition
ISBN: 9781305264434
Author: Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher: Brooks Cole
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Chapter 24, Problem 2ASA

In an acid-base titration, 21.16 mL of an NaOH solution are needed to neutralize 20.04 mL of a 0.0997 M HCl solution. To find the molarity of the NaOH solution, we can use the following procedure:

  1. First note the value of MH+ in the HCl solution. ____________M
  2. Find MOH- in the NaOH solution. (Use Eq.3.) ____________M
  3. Obtain MNaOH from MOH. ____________M

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The next 11 questions are related to the titration of 40.00 mL of a 0.0900 M acetic acid solution with 0.0950 M KOH. Assume that the temperature is 25 oC. What is the pH when 23.00 mL of the KOH solution have been added? What is the pH when 46.00 mL of the KOH solution have been added?
A 19.7 mL solution of 0.100 mol L-¹ CH3COOH is titrated using 0.150 mol L-1 NaOH. What is the pH of the solution after 5.11 mL of the NaOH solution is added? Express your answer to 2 decimal places. Remember you can find KA and/or KB values in your textbook in chapter 15. They are also posted on eClass. Answer:
When 25 .00 mL of 0.1098 M HCl in 40 mL of DI water is titrated against 0.09998 M NaOH, the pH increases. What is the volume (in mL) of NaOH required to reach the equivalence point and a pH of 7.00? Find the pH when the volume of NaOH added is 0.05 mL less than the volume required to reach the equivalence point. Find the pH when the volume of NaOH added is 0.025 mL less than the volume required to reach the equivalence point.
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Acid-Base Titration | Acids, Bases & Alkalis | Chemistry | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=yFqx6_Y6c2M;License: Standard YouTube License, CC-BY