Describe the behavior of the bulb in the two situations below. i. The switch is first moved to position 1 . Describe the behavior of the bulb from just after the switch is closed until a long time later . Explain. ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later . Explain your reasoning.

Question

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Answer 1

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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01:11

Students have asked these similar questions

1.in picture left why is PEi equal to 0？why is KEf is also equal zero？why Ri is too far away from Rf？？？ 2. The picture on the right，why PEf is equal to 0 instead of letting PEi equal to 0？？？？ 3. what is the main words in the question helps us to decide which PE （PEf or PEi）equal to 0？？？

The rectangular block below has front-face dimensions of 10 cm by 4 cm, with a depth of 3 cm.(Figure 1) You will be asked to treat this object as an electrical resistor. Rank the block based on its electrical resistance along the three illustrated coordinate directions (x, y, and z). If all of the dimensions of the block double (to become 20 cm wide, 8 cm tall, and 6 cm deep), what happens to the resistance along each axis? The resistance quadruples. The resistance doubles. The resistance stays the same. The resistance is halved. The resistance is quartered.

Consider the following. (a) A rectangular block has the dimensions ℓ ✕ w ✕ h. When a battery with a voltage V is connected across the end faces as shown in the left figure above, a current I1 flows through the circuit. If the same battery is connected across the top and bottom faces of the block as shown in the right figure, what is the current I2 that flows through the circuit? Give your answer in terms of I1. (Use the following as necessary: ℓ, w, h, I1) I2 = ? (b) Suppose ℓ = 4.20 cm, w = 2.2 cm, and h = 1.80 cm; the battery voltage is 1.5 V and I1 = 2.50 A, determine the value of I2. (A)

Answer 2

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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01:11

Answer 3

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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01:11

Answer 4

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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01:11

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 8

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 9

(i)

Expert Solution

Answer 10

(i)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Answer 13

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 14

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 15

(ii)

Expert Solution

Answer 16

(ii)

Expert Solution

Answer 17

Expert Solution

Answer 18

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Answer 19

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.