Interpretation:
Partial columns has to be filled in the table given in problem statement.
Concept Introduction:
Each and every element present in the Periodic table has a unique name. Some of the elements are named considering their
Chemical names are represented as atomic symbols. In the symbols, the mass number and atomic number are shown. The complete
Atomic number is the total number of protons present in the atom of an element. Mass number is the total number of protons and neutrons present in nucleus of an atom.
Explanation of Solution
For entry 1:
Number of protons is given as 31. This means that the atomic number of the species is 31. The element with atomic number 31 is found to be gallium with the symbol of
Mass number is the sum of number of protons and number of neutrons. From the mass number given as 70, the number of neutrons can be calculated as shown below.
Number of electrons is given as 28. The charge on the species can be calculated as shown below.
The symbol for the species is given as
For entry 2:
Number of electrons is given as 42. Charge on the species is given as
Number of protons is found as 45. This means that the atomic number of the species is 45. The element with atomic number 45 is found to be rhodium with the symbol of
Mass number is the sum of number of protons and number of neutrons. From the mass number given as 103, the number of neutrons can be calculated as shown below.
The symbol for the species is given as
For entry 3:
Atomic number is given as 49. This means that the number of protons in the species is 49. The element with atomic number 49 is found to be indium with the symbol of
The charge on the species is given as
Mass number is the sum of number of protons and number of neutrons. Number of neutrons is given as 65. From this mass number can be calculated as shown below.
The symbol for the species is given as
For entry 4:
Symbol is given as
Mass number is the sum of number of protons and number of neutrons. From the mass number given as 40 in the symbol, the number of neutrons can be calculated as shown below.
Charge is given as
Complete table can be given as shown below.
Symbol | ||||
Atomic number | ||||
Mass number | ||||
Charge | ||||
Number of protons | ||||
Number of electrons | ||||
Number of neutrons |
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Chapter 2 Solutions
Chemistry: Principles and Practice
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- Two samples of different compounds of nitrogen and oxygen have the following compositions. Show that the compounds follow the law of multiple proportions. What is the ratio of oxygen in the two compounds for a fixed amount of nitrogen? Amount N Amount O Compound A 1.206 g 2.755 g Compound B 1.651 g 4.714 garrow_forwardTwo samples of different compounds of sulfur and oxygen have the following compositions. Show that the compounds follow the law of multiple proportions. What is the ratio of oxygen in the two compounds for a fixed amount of sulfur? Amount S Amount O Compound A l.210g 1.811 g Compound B 1.783 g 1.779 garrow_forwardTwo basic laws of chemistry are the law of conservation of mass and the law of constant composition. Which of these laws (if any) do the following statements illustrate? (a) The mass of phosphorus, P, combined with one gram of hydrogen, H, in the highly toxic gas phosphene, PH3, is a little more than twice the mass of nitrogen, N, combined with one gram of hydrogen in ammonia gas, NH3. (b) A cold pack has the same mass before and after the seal between two reactants is broken to allow reaction to occur. (c) It is highly improbable that carbon monoxide gas found in Los Angeles is C1.2O1.1.arrow_forward
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