Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 19, Problem 19.19SP
Rework Problem 19.12 assuming that the angle is an
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Problem 14.3.A
A 4 × 4 x 2-in. angle of A36 steel is to be welded to a plate with E 70
XX electrodes to develop the full tensile strength of the angle. Using
%-in. fillet welds, compute the design lengths for the welds on the two
sides of the angle, assuming development of tension on the full cross sec-
tion of the angle.
A=3.75 inch2
L1= 10.94"
L2 = 5.09"
IF only connected leg, L=7.7";
4.75 each side
Determine the length of the weld run for a plate of size 120 mm wide and 15 mm
thick to be welded to another plate by means of
1. A single transverse weld; and
2. Double parallel fillet welds when the joint is subjected to variable loads. (hint:
From Table 10.6, we find that the stress concentration factor for transverse weld
is 1.5 and for parallel fillet welds is 2.7).
A
B
Question No. 11: (a) Illustrate flatness, straightness and circularity with symbol.
(b) A circular shaft, 80 mm in diameter is welded to support by means of a circumferential fillet weld. It is
subjected to a torsion moment of 3000 N-m. Determine the size of weld, if the maximum shear stress in the weld
is not to exceed 70 N/mm2
.
(c) Analyze different stresses during design of screw and nut
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
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- Can a tee weld be strong if the welds on both sides do not have deep penetration? Why or why not?arrow_forwardCompute for the total length of weld required with the given tension load, T. Tension member is 50x50x6mm angle bar. Fexx = 414 MPa and weld size of 5mm. Gusset Plate 105 kN Angle Bar c.g.arrow_forwarda. Show how the extent of the surfacing weld is indicated between the vertical centerlines in the following illustration.arrow_forward
- 7. Determine the size of fillet welds required for the weld group shown in fig. 10.21. Fig. 10.21 127 190 x 150 kN [10 mm] Could you please show the full working for this question. Thank you!arrow_forwardE70XX 1/4 V2 1/4 For the welding information shown, calculate the design capacity of the weld Rweld = karrow_forwardA continuous fillet wild is used to weld two pieces of 7.0-mm-thick austenitic stainless steel plate in an arc-welding operation. The plates are joined at a 90° angle using an inside fillet corner joint. The velocity of the welding head is 6 mm/sec. Assume the cross section of the weld bead approximates a right angle isosceles triangle (a right triangle with the two legs and their corresponding angles equal) with a leg length of 4.5 mm. The length of the weld = 230 mm. The melting factor of the setup = 0.65, the heat transfer factor = 0.90, and the Tm for austenitic stainless steel = 1670°K. Determine (a) The amount of heat (in joules) required to melt the volume of metal in (b) The heat that , (c) The rate of heat generation required at the welding source to accomplish the weld this weld (filler metal plus base metal) must be generated at the heat sourcearrow_forward
- Determine the fillet weld size required if #70 electrodes are used.arrow_forward5. A steel cylindrical air receiver with 5 feet diameter and pressure load of 180 psi, design stress of 9500 psi maximum. The pressure vessel is to be provided with a 1.5 in diameter drain valve installed at the bottom of the vessel and a safety pressure relief valve is installed either at the topmost or at the side with a pop-out rating of 200 psi. Assume a 100% weld joint efficiency. The lap welding tensile strength is 65,000 psi. Determine the bursting pressure of this air receiver. psiarrow_forward11.16 Two 20-mm steel plates are butt-welded together. Both the plate and the welding electrode materials correspond to strength properties of Su = 500 MPa and S, = 400 MPa. The imposed loading fluctuates rapidly between -20 and +60 kN. Estimate the length of weld required in order to provide a safety factor of 2.5: (a) If the weld reinforcement is not removed. (b) If the excess weld material is carefully ground off to provide smooth, continu- ous surfaces.arrow_forward
- 02: Two plates, 20 mm thick, are welded together by means of transverse-fillet welds. The ultimate tensile strength of a weld metal is 415 MPa. The surface finish factor of the weld surface is 0.5, and the size factor is 0.85. The reliability is 90%. Determine the length of the weld if the factor of safety is 2.5. The transverse force on the welds is 80 kN, which is completely reversed under fatigue loading. Take: A=13mm. 25 A, Toe Good luckarrow_forwardA steel cylindrical air receiver with 5 ft. diameter and pressure load of 180 psi, design stress of 9500 psimaximum. The pressure vessel is to be provided with 1 ½ in. diameter drain valve installed at the bottomof the vessel and safety pressure relief valve installed either at the topmost or at the side with pop-outrating of 200 psi. Assume a 100% weld joint efficiency. The lap welding tensile strength is 65,000 psi.Determine the bursting pressure of this air receiverarrow_forwardExample 27.2. A 100 mm x 10 mm plate is to be 150 mm x 10 mm by the fillet welding on three sides. The size of the weld is 6 mm. Find out the necessary over lap of the plate, for full strength of the joint. Take allowable tensile stress in plate equal to 150 N/mm and allowable stress in weld as 110 N/mm. welded to another platearrow_forward
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