Concept explainers
(a)
The potential energy of the given system of charges.
Answer to Problem 36QAP
The potential energy of the given system of charges is
Explanation of Solution
Given info:
Charge
Charge
Position of charge
Position of charge
Formula used:
Formula to calculate the potential energy of two charges is given as,
Calculation:
Substituting the given values in the above equation, we get
Conclusion:
Thus, the potential energy of the given system of charges is
(b)
The speed of particle with charge
Answer to Problem 36QAP
The speed of particle with charge
Explanation of Solution
Given info:
Initial position of charge
Final position of charge
Initial velocity of charge
Mass of charge
Formula used:
Formula for the force experienced by the charged particle is,
Formula for the third equation of motion is,
Calculation:
The repulsive force experienced by particle with charge
The acceleration of particle with charge
The velocity of particle with charge
Substituting the given values in the above equation, we get
Conclusion:
Thus, the speed of particle with charge
Want to see more full solutions like this?
Chapter 17 Solutions
COLLEGE PHYSICS
- Consider two conducting spheres with radii R1 and R2 separated by a distance much greater than cither radius. A total charge Q is shared between the spheres. We wish to show that when the electric potential energy of the system has a minimum value, the potential difference between the spheres is zero. The total charge Q is equal to q1 + q2, where q1 represents the charge on the first sphere and q2 the charge on the second. Because the spheres are very far apart, you can assume the charge of each is uniformly distributed over its surface. (a) Show that the energy associated with a single conducting sphere of radius R and charge q surrounded by a vacuum is UE = keq2/2R. (b) Find the total energy of the system of two spheres in terms of the total charge Q, and the radii and R1 and R2. (c) To minimize the energy, differentiate the result to part (b) with respect to q1 and set the derivative equal to zero. Solve for q1 in terms of Q and the radii. (d) From the result to part (c), find the charge q2. (e) Find the potential of each sphere. (f) What is the potential difference between the spheres?arrow_forwardA glass ring of radius 5.0 cm is painted with a charged paint such that the charge density around the ring varies continuously given by the following function of die polar angle ,=(3.0106C/m)cos2 . Find the potential at a point 15 cm above the center.arrow_forwardCan a particle move in a direction of increasing electric potential, yet have its electric potential energy decrease? Explainarrow_forward
- Four point charges each having charge Q are located at the corners of a square having sides of length a. Find expressions for (a) the total electric potential at the center of the square due to the four charges and (b) the work required to bring a fifth charge q from infinity to the center of the square.arrow_forwardIf a negatively charged particle is placed at rest in an electric potential field that increases in the positive x-direction, will the panicle (a) accelerate in the positive x-direction, (b) accelerate in the negative x-direction, or (c) remain at rest?arrow_forwardAn electron is released from rest in a uniform electric field. Determine whether the following quantities increase, decrease, or remain unchanged as the electron moves. Indicate your answers with I (increase), D (decrease), or U (unchanged), respectively. (a) The electric potential at the electrons location (b) The electrons associated electric potential energy (c) Its kinetic energy (d) Its total energy.arrow_forward
- A long thin wire is used in laser printers to charge the photoreceptor before exposure to light. This is done by applying a large potential difference between the wire and the photoreceptor. a. Use Equation 26.23, V(r)=20lnRr to determine a relationship between the electric potential V and the magnitude of the electric field E at a distance r from the center of the wire of radius R (r R). b. Determine the electric potential at a distance of 2.0 mm from the surface of a wire of radius R = 0.80 mm that will produce an electric field of 1.8 106 V/m at that point.arrow_forwardA uniform electric field of magnitude 325 V/m is directed in the negative y direction in Figure P25.5. The coordinates of point are (-0.200, -0.300) m, and those of point are (0.400. 0.500) m. Calculate the electric potential difference V - V using the dashed-line path.arrow_forwardWhat is the potential 0.5301010 m from a proton (the average distance between the proton and electron in a hydrogen atom)?arrow_forward
- Two particles each with charge +2.00 C are located on the x axis. One is at x = 1.00 m, and the other is at x = 1.00 m. (a) Determine the electric potential on the y axis at y = 0.500 m. (b) Calculate the change in electric potential energy of the system as a third charged particle of 3.00 C is brought from infinitely far away to a position on the y axis at y = 0.500 m.arrow_forwardIt is shown in Example 24.7 that the potential at a point P a distance a above one end of a uniformly charged rod of length lying along the x axis is V=keQlln(l+a2+l2a) Use this result to derive an expression for the y component of the electric field at P.arrow_forwardBecause the charges on the plates of a parallel-plate capacitor are opposite in sign, they attract each other. Hence, it would take positive work to increase the plate separation. What type of energy in the system changes due to the external work done in this process?arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning