Concept explainers
To review:
The start codon and the amino acids sequences translated from mRNA sequence 5'- GGCGAUGGGCAAUAAACCGGGCCAGUAAGC-3'.
Introduction:
Codons are the three
Explanation of Solution
The start codon is the AUG acts as a signal codon, which helps in the initiation of translation. It is the first codon of messenger RNA. It is present in both eukaryotes and prokaryotes. In eukaryotes, it starts from 5'untranslated region. However, in prokaryotes it includes ribosomal binding sites.
The codon which is known as start codon is AUG, which codes for methionine. There are some codons which are known as stop codons, which terminate the translation of amino acids. The stop codons are UAA, UAG, and UGA. The amino acids, which will be obtained from given mRNA sequences are mentioned below:-
Therefore, it can be concluded that the codon which starts from 5th nucleotide is AUG. The amino acid sequences are Met, Gly, Asn, Lys, Pro, Gly, Gln, and STOP.
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Chapter 13 Solutions
Genetics: Analysis and Principles
- Using the genetic code table provided below, identify the open reading frame in this mRNA sequence, and write out the encoded 9 amino acid long peptide sequence: 5'- CGACAUGCCUAAAAUCAUGCCAUGGAGGGGGUAACCUUUU C A G U UUU Phe UCU Ser UUC Phe UCC Ser UAC UCA Ser UAA UCG Ser UAG UUA Leu Leu G C CUU Leu CUC Leu CCC CUA Leu CUG Leu AUU lle AUC lle AUA lle AUG Met ACG ACU Thr ACC Thr ACA Thr Thr A UAU Tyr UGU Cys Tyr UGC Cys CCU Pro CAU His CGU Arg Pro CAC His Pro CAA Gln CGC Arg CGA Arg CCA CCG Pro CAG Gln CGG Arg GUU Val GCU Ala GAU GUC Val GCC Ala GAC GUA Val GCA Ala GAA GUG Val GCG Ala GAG Stop UGA Stop UGG AAU Asn AAC AAA AAG AGU Asn AGC G Lys Lys Asp Asp Glu Glu Stop A Trp Ser Ser AGA Arg AGG Arg GGU Gly GGC Gly UCAG GGA Gly GGG Gly с U C A G U C A G U C A Garrow_forwardFor the following mRNA sequence (reading from left to right) what will be the amino acid sequence following translation? (Use chart provided) AUGCCAGUUGAAUAA First position U C A UUU UUC UUA UUG CUU CUC CUA CUG U >Phe GUU GUC GUA GUG >Leu >Leu AUU ACU AUC lle ACC AUA ACA AUG Met/start ACG >Val UCU UCC UCA UCG ©2019 Pearson Education, Inc. CCU CCC CCA CCG GCU GCC GCA GCG Second position A >Ser >Pro Thr >Ala UAU UGU U UAC UGC C UAA Stop UGA Stop A UAG Stop UGG Trp G CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG Tyr >His >Gin >Asn >Lys >Asp >Glu CGU CGC CGA CGG AGU AGC AGA AGG G GGU GGC GGA GGG >Cys Arg >Ser >Arg >Gly DOAG SCAG U с А UCA с А G Third position Correct answer not given Met-Val-Tyr-Pro Met-His-Phe-Ala-Arg Pro-Val-Met-Leu-His Met-Pro-Val-Gluarrow_forwardAn mRNA transcript is listed below and contains both start and termination codons. Assume that the initial methionine will stay on the polypeptide in this case. What amino acid sequence will be specified during translation? List the amino acids. The start codon is highlighted. 5’ – CAGCCAAGCAUGCUCGCAAAUGGACGUUGAUAUUUUGUC – 3’arrow_forward
- Translate the following mRNA nucleotide sequence into an amino acid sequence, starting at the first base: 5’ - UGUCAUGCUCGUCUUGAAUCUUGUGAUGCUCGUUGGAUUAAUUGU - 3’arrow_forwardAn mRNA has the following sequence: 5′–GGCGAUGGGCAAUAAACCGGGCCAGUAAGC–3′ Identify the start codon, and determine the complete amino acid sequence that would be translated from this mRNA.arrow_forwardTranslate the following mRNA nucleotide sequence into an amino acid sequence, starting at the second base: 5’ - UGUCAUGCUCGUCUUGAAUCUUGUGAUGCUCGUUGGAUUAAUUGU - 3’arrow_forward
- Assume the following portion of an mRNA. Find a start signal, and write the amino acid sequence that is coded for. 5'-GCCAUGUUUCCGAGUUAUCCCAAAGAUAAAAAAGAG 3'arrow_forwardGiven the following mRNA sequence: 5-AUCCCGUAUGCCCGGGAGCUAGCCCAGC-3 a) Label the first condon, the stop codon, the untranslated regions and predict the amino acid sequence of the polypeptidarrow_forwarddraw mRNA sequence for the following sequence ATGGCCCTGTGGATGCGCCTCCTGCCCCTGCTGGCGCTGCTGGCCCTCTGGGGACCTGACCCAGCCGCAGCCTTTGTGAACCAACACCTGTGCGGCTCACACCTGGTGGAAGCTCTCTACCTAGTGTGCGGGGAACGAGGCTTCTTCTACACACCCAAGACCCGCCGGGAGGCAGAGGACCTGCAGGTGGGGCAGGTGGAGCTGGGCGGGGGCCCTGGTGCAGGCAGCCTGCAGCCCTTGGCCCTGGAGGGGTCCCTGCAGAAGCGTGGCATTGTGGAACAATGCTGTACCAGCATCTGCTCCCTCTACCAGCTGGAGAACTACTGCAACTAGarrow_forward
- Translate the following mRNA into protein, starting from the first initiation codon: 5'-CCGAUGCCAUGGCAGCUCGGUGUUAC AAGGCUUGCAUCAGUACCAGUUUGAAUCC-3'arrow_forwardTranslation is the process by which the sets of 3 bases (codons) of the mRNA are read to specify the sequence of amino acids for the protein to be produced. Using the genetic code data provided, find the sequence of amino acids that would correspond to the MRNA codons shown. Codons 1 3 MRNA A UGUGGAUC CGAG UCACG Amino acid SECOND LETTER A U UUU Phenylalanine UCU UCC Serine (S) UAU Tyrosine (Y) UAC TAA stop codon UAG stop codon UGU Cysteine (C) UGC TỮA Leucine (L) TGA stop codon UGG Tryptophan (W) F UCA UUG UCG I H CUU CCU CAU Histidine (H) R CGU CỨC Leucine (L) CỦA CCC Proline (P) ССА CCG CGC Arginine (R) CGA CAC "CAA Glutamine CAG (Q CUG CGG G D A AUU L AUC Isoleucine (1) AAU Asparagine AAC (N) ÄÄÄ Lysine (K) AGU Senine (S) ACU ACC Threonine ACA (T) AGC E AUA AGA Arginine (R) E ACG T AUG stat codon (M) AAG AGG TG GƯỮ GAU Apartic acid GAC (D) "GAÄ Glutamic acid GCU GGU GUC Valine (V) GUA GGC Glycine (0) GCC Alanine (A) CE GCA GGA R GUG GCG GGG GAG (E) The start codonencodes the amino…arrow_forwardThe genetic code consists of a series of three-base wordsthat each code for a given amino acid.(a) Using the selections from the genetic code shown below, de-termine the amino acid sequence coded by the following seg-ment of RNA: UCCACAGCCUAUAUGGCAAACUUGAAG AUG= methionine ;CCU= proline; CAU= histidine ;UGG= tryptophan AAG= lysine ; UAU= tyrosine ;GCC= alanine ;UUG= leucine ;CGG= arginine ;UGU= cysteine ;AAC =asparagine ;ACA=threonine ;UCC= serine ;GCA=alanine ;UCA=serine(b) What is the complementary DNA sequence from which this RNA sequence was made? (c) If you were sequencing the DNA fragment in part (b), how many complementary chain pieces would you obtain in the tube containing ddATP?arrow_forward
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