Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Chapter 12, Problem 30CTQ
Use the probability method to calculate the genotypes and genotypic proportions of a cross between AABBCc and Aabbcc parents.
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Use the forkline method to derive the gametic ratio of cross AabbDD x AABbDd. The cross are segregated independently.
Using a Punnet square complete the cross AABBCC and AaBbCc. Provide the genotypic and phenotypic ratio.
Using forked line method, figure out the phenotype and genotype of the offspring between two individuals with genes: AaBbCC x AabbCc
Chapter 12 Solutions
Biology 2e
Ch. 12 - Figure 12.5 In pea plants, round peas (R) are...Ch. 12 - Figure 12.6 What are the genotypes of the...Ch. 12 - Figure 12.12 What ratio of offspring would result...Ch. 12 - Figure 12.16 In pea plants, purple flowers (P) are...Ch. 12 - Mendel performed hybridizations by transferring...Ch. 12 - Which is one of the seven characteristics that...Ch. 12 - Imagine you are performing a cross involving seed...Ch. 12 - Consider a cross to investigate the pea pod...Ch. 12 - A scientist pollinates a true-breeding pea plant...Ch. 12 - The observable traits expressed by an organism are...
Ch. 12 - A recessive trait will be observed in individuals...Ch. 12 - If black and white true-breeding mice are mated...Ch. 12 - The ABO blood groups in humans are expressed as...Ch. 12 - In a mating between two individuals that are...Ch. 12 - If the allele encoding polydactyly (six fingers)...Ch. 12 - A farmer raises black and white chickens. To his...Ch. 12 - Assuming no gene linkage, in a dihybrid cross of...Ch. 12 - The forked line and probability methods make use...Ch. 12 - How many different offspring genotypes are...Ch. 12 - Labrador retriever's fur color is controlled by...Ch. 12 - Which of the following situations does not follow...Ch. 12 - Describe one of the reasons why the garden pea was...Ch. 12 - How would you perform a reciprocal cross for the...Ch. 12 - Mendel performs a cross using a true-breeding pea...Ch. 12 - Calculate the probability of selecting a heart or...Ch. 12 - The gene for flower position in pea plants exists...Ch. 12 - Use a Punnett square to predict the offspring in a...Ch. 12 - Can a human male be a carrier of red-green color...Ch. 12 - Why is it more efficient to perform a test cross...Ch. 12 - Use the probability method to calculate the...Ch. 12 - Explain epistatis in terms of its Greek-language...Ch. 12 - In Section 12.3, ''Laws of Inheritance," an...Ch. 12 - People with trisomy 21 develop Down’s syndrome....Ch. 12 - A heterozygous pea plant produces violet flowers...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Consider these two crosses and assume that independent segregation is exhibited by all gene pairs: RrmmTT x RRMmTtFfGg x FfGg Derive the gametic ratio of the second parent in each cross using the branching method. What proportion of the offspring in each cross will be heterozygous for all gene pairs? Derive the genotypic ratio for the offspring from each cross using the branching method. Show complete solutions.arrow_forwardGiven the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forwardGive typing answer with explanation and conclusion Directions: For the following problem, calculate the probability of the offspring between the cross using the sum and product rule. The parent generation has genotypes of Aa Bb Cc and AA Bb CC. What is the probability the F1 generation would be AA bb cc?arrow_forward
- give the possible genotypes and phenotypes and their ratios from the following cross between two strains of chicken:Rose comp (Rrpp) x Walnut (RrPp)arrow_forwardNotation: D = disease allele at gene d = wild-type allele at gene Let’s provide some information about each MOI. AD: Each of the F1 parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an F1 cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother’s genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 Disease, Female 267 WT, Male 285 WT, Female 301 Total 1157 DF p-value In Table 2, provide expected proportions for two different MOIs: AD and SLR. The values in this table are computed using information from the Punnett Square and the specified MOI. Once the proportions are determined, we can fill in the values in Table 3, E(xpected)…arrow_forwardConsider these two crosses and assume that independent segregation is exhibited by all gene pairs. Derive the gametic ratio of the second parent in each cross using the branching method. What proportion of the offspring in each cross will be heterozygous for all gene pairs? Derive the genotypic ratio for the offspring from each cross using the branching method. Show complete solutions. a. RrmmTT x RRMmTtb. FfGg x FfGgarrow_forward
- Solve the problem using punnett square. What is the probability that each of the following pairs of parents will produce the indicated offspring? AAbbCc X AaBBCc --> AaBbCc = AaBBCcDd X AaBbCcDD --> AaBBccDD =arrow_forwardPerform a chi-square test of independence on the data provided to determine if the genes for flower color and pollen shape in sweet peas are assorting independently. Give the chi-square value, degrees of freedom, and associated probability. What conclusion would you draw about the independent assortment of these genes? Hint: the expected phenotype ratios are 9:3:3:1 instead of 1:1:1:1 due to the type of cross that was performed.arrow_forwardGive typing answer with explanation and conclusion "B"-yellow "b"-green. When 2 heterozygous parents for both traits are crossed it's called a dihybrid cross- AaBb × AaBb. Fill in the Punnett Square with the genotypes of this cross.arrow_forward
- In a cross AABbCc × aabbCc, what is the probability of producing the genotype AabbCC? (show work)arrow_forwardComplete the table below to determine the Non-Mendelian patterns ofinheritance involved in the formation of the given phenotype of the offspringproduced in a cross between a homozygous black fur rabbit and white fur rabbit.arrow_forwardConsider the pedigree below. Which of the individuals MUST be heterozygous carriers of the diseasse? I II III IV OQ 3 11-2 III-1 III-2 UI-3 III-4 III-5 IV-1 IV-2 IV-3 IV-4 IV-5arrow_forward
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