The current in a series RCL circuit is given by: I = V R 2 ( ω L − 1 ω C ) 2 Where ω =2 π f. Calculate I for the circuit shown if the supply voltage is 80 V, f= 50Hz, R= 6 Ω , L=400 × 10-3 H, and C = 40 × 10 − 6 F.
The current in a series RCL circuit is given by: I = V R 2 ( ω L − 1 ω C ) 2 Where ω =2 π f. Calculate I for the circuit shown if the supply voltage is 80 V, f= 50Hz, R= 6 Ω , L=400 × 10-3 H, and C = 40 × 10 − 6 F.
The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit
and Ris the resistance (in ohms). If we place two circuits, with resistance R1 and R2, in parallel, then their combined resistance, R, is
1
1
1
given by -
R
Suppose the current is 6 amps and increasing at 10-2 amp/sec and R1 is 6 ohms and increasing at 0.6
+
R1
R2
ohm/sec, while R2 is 7 ohms and decreasing at 0.1 ohm/sec. Calculate the rate at which the voltage is changing.
Round your answer to three decimal places.
volts/sec
The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit
and R is the resistance (in ohms). If we place two circuits, with resistance R1 and R2, in parallel, then their combined resistance, R, is
1 1
1
given by -
R
Suppose the current is 6 amps and increasing at 10-2 amp/sec and Ri is 8 ohms and increasing at 0.9
R2
R1
ohm/sec, while R2 is 7 ohms and decreasing at 0.7 ohm/sec. Calculate the rate at which the voltage is changing.
Round your answer to three decimal places.
volts/sec
The voltage, V (in volts), across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit and R is the resistance (in
ohms). If we place two circuits, with resistance R₁ and R₂, in parallel, then their combined resistance, R, is given by
1
1
+
R R₁
volts/sec
=
1
R₂
Suppose the current is 5 amps and increasing at 0.02 amps/sec and R₁ is 3 ohms and increasing at 0.4 ohms/sec, while R₂ is 4 ohms and decreasing at 0.3
ohms/sec. Calculate the rate at which the voltage is changing.
HINT. Using the Chain Rule, you have to find the partial derivatives of R with respect to R₁ and R₂, and before that you have to express R in terms of R₁ and
R₂ using the given relation between them.
Alternatively, you can use this trick, which introduces new, auxiliary variables and, therefore, makes the dependence tree bigger, but, on the other hand, makes
the calculations very simple.
Namely, introduce the conductivities C = 1/R, C₁ = 1/R₁ and C₂ = 1/R₂. Then the…
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