Oracle 12c: SQL
3rd Edition
ISBN: 9781305251038
Author: Joan Casteel
Publisher: Cengage Learning
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Textbook Question
Chapter 1, Problem 14MC
A unique identifier for a data row that consists of more than one field is commonly called a:
- a. primary plus key
- b. composite primary key
- c. foreign key
- d. none of the above
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Assume that a database has a table named Stock, with the following columns:Column Name TypeTrading_Symbol nchar(10)Company_Name nchar(25)Num_Shares intPurchase_Price moneySelling_Price money
Write a Select statement that returns the Trading_Symbol column and the Num_Shares column only from the rows where Selling_Price is greater than Purchase_Price and Num_Shares is greater than 100. The results should be sorted by the Num_Shares column in ascending order.
assume that a database has a table named Stock, with thefollowing columns:Column Name TypeTrading_Symbol nchar(10)Company_Name nchar(25)Num_Shares intPurchase_Price moneySelling_Price money Write a Select statement that returns the Trading_Symbol column and the Num_ Shares column only from the rows where Selling_Price is greater than Purchase_ Price and Num_Shares is greater than 100. The results should be sorted by the Num_Shares column in ascending order.
Write Mysql code
The database has three tables for tracking horse-riding lessons:
Horse with columns:
ID - primary key
RegisteredName
Breed
Height
BirthDate
Student with columns:
ID - primary key
FirstName
LastName
Street
City
State
Zip
Phone
EmailAddress
LessonSchedule with columns:
HorseID - partial primary key, foreign key references Horse(ID)
StudentID - foreign key references Student(ID)
LessonDateTime - partial primary key
Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule.
Hint: Perform a join on the Student and LessonSchedule tables, matching the student IDs.
Chapter 1 Solutions
Oracle 12c: SQL
Ch. 1 - Prob. 1RQCh. 1 - Prob. 2RQCh. 1 - Prob. 3RQCh. 1 - Prob. 4RQCh. 1 - Discuss the problems that can be caused by data...Ch. 1 - Explain the role of a primary key.Ch. 1 - Prob. 7RQCh. 1 - Prob. 8RQCh. 1 - What type of relationship can’t be stored in a...Ch. 1 - Identify at least three reasons an organization...
Ch. 1 - Prob. 1MCCh. 1 - Prob. 2MCCh. 1 - Prob. 3MCCh. 1 - Prob. 4MCCh. 1 - Prob. 5MCCh. 1 - Prob. 6MCCh. 1 - Prob. 7MCCh. 1 - Which of the following has no partial or...Ch. 1 - Prob. 9MCCh. 1 - Which of the following has no partial dependencies...Ch. 1 - Which of the following has no repeating groups but...Ch. 1 - Prob. 12MCCh. 1 - Prob. 13MCCh. 1 - A unique identifier for a data row that consists...Ch. 1 - Which of the following symbols represents an...Ch. 1 - Prob. 16MCCh. 1 - Which of the following represents a field in a...Ch. 1 - Which of the following defines a relationship in...Ch. 1 - When part of the data in a table depends on a...Ch. 1 - Which of the following is used to join data...Ch. 1 - Which tables and fields would you access to...Ch. 1 - Prob. 2HOACh. 1 - Prob. 3HOACh. 1 - Prob. 4HOACh. 1 - Access path A database table is composed of...Ch. 1 - Prob. 6HOACh. 1 - Prob. 7HOACh. 1 - Prob. 8HOACh. 1 - Prob. 9HOACh. 1 - Prob. 10HOA
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- Delete the index named ITEM_INDEX3.arrow_forwardA(n) _____ is a request for specific information from a database.arrow_forwardThe database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule. Hint: Perform a join on the Student and LessonSchedule tables, matching the student IDsarrow_forward
- The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule.arrow_forwardAlternate keys: Identify at least five keys (not already listed as PK or FK) needed by end users. These indexes would be considered Alternate or Secondary keys and are mostly used for queries and quick reporting. They may contain multiple columns.arrow_forwardUse Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.arrow_forward
- Assume that the Authors table is already built in the database with the following specifications: Authors: Column Name Data Type constrains Authors ID Author Name Varchar2(10) |Varchar2(30) Primary key Unique You Need to Create the Books table with the following specifications Column Name Data Type Constrains ISBN Book Title Book Price Author id Number (10) Varchar2(40) Number (4,2) Varchar2(10) Primary key Not Null referencing the Author_ID in the Author Table Complete the create statement by drag and drop the correct word: Create Table lblank (ISBN Number (10) plank, Book Title Varchar2blank ) Not Null, Book Price Number(4, 2), Auther IR blank (10) references Jolank (blank ); Author ID Books Number||Authors Not Nul Varchar2| Primary Key 40 h (United States)arrow_forward1-Write the syntax to insert into a relational table called students the address column references an object table called addresses that was created using an address_type. Other columns exist in the students table, but you are only inserting into the ones below. Aliases used should be the first letter of the table name, eg students would be s, addresses would be a Relational Table Name students attribute student_id attribute surname attribute addressarrow_forward
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