Run 1 [1]。 Sample Calculation M1V1 = M2V2 0.200M 20.00mL = M2 20.00mL M2 = 0.2000 M Run 1 [S₂O] Sample Calculation M1V1M2V2 0.00500M *10.00mL = M2*50.00mL M2 = 0.001000 M Run 1 [S2O2] Sample Calculation M1V1 = M2V2 0.100M 20.00mL = M2 20.00mL M2 = 0.100 M Run 1 rate =-d[S₂O,1/2dt [S20,2]=0.001000 M = rate [0.001000 M]/2t rate = 0.0005000 M/t To Find the order of reactants and to find the overall order of reacation: Run 1 Run 2 Run 1 Run 2 m n rate= k [1] [S₂O,²]," 3.571E-06=k(0.2000)0^m(0.0500)0^n 2.488E-06 k(0.2000) o^m (0.1000)o^n Run 5 Run 4 m rate = k [1] [S₂O,²]," 2.825-06=k(0.06680)0^m(0.10000)0^n 4.589E-06 = k(0.1000)0^m(0.1000)0^n Run 5 = 2.825-06 k(0.06680)0^m Run 4 4.589E-06 = k(0.1000)0^m 3.571E-06 (0.0500)0^n 2.488E-06 (0.1000)o^n 1.44 0.157068 = 2^n =n* 0.301029996 n = 0.521769 = 1 OVERALL Order Of Rx = 2 rate [][S2O-2]0 0.615819 = .6680^m -0.210547 =m* -0.17522 m = 1.20159 =1 RUN Time T T S °C K rate--d[S20, 1/2dt mol/Ls ⚫k 1 In (k) T(K) 12345 140 20.0 293.0 3.571E-06 0.0017857 0.003413 -6.328 201 20.0 293.0 2.488E-06 0.0012438 0.003413 -6.690 310 20.0 293.0 1.613E-06 0.0008065 0.003413 -7.123 109.00 20.0 293.0 4.587E-06 0.0022936 0.003413 -6.078 177 20.0 293.0 2.825E-06 0.0014124 0.003413 -6.562 average k 0.0015084 Uncatalyzed Reaction. R=8.3145 J/Kmol RUN Time T T rate--d[S,O,1/2dt *k 1 In (k) Ea/R=3337.9 S °C K mol/Ls T(K) Runs 1-5 20.0 293.0 average k 0.0003017 0.003413 -6.556 Ea-3337.9x8.1345J/Kmol 6 78 30 303.0 6.410E-06 0.0032051 0.003300 -5.743 7 69 40.0 313.0 7.246E-06 0.0036232 0.003195 -5.620 Ea= 27.15215 kJ 8 195 11.9 9 239 4.5 284.9 277.5 2.564E-06 2.092E-06 0.0012821 0.003510 0.0010460 -6.659 0.003604 -6.863 Activation Energy Catalyzed Reaction R=8.3145 J/Kmol RUN Time T T rate--d[S,O,1/2dt "k 1 In (k) Ea/R=4597.2 S °C K mol/Ls T(K) 10 84 20.0 293.0 5.952E-06 0.0029762 0.003413 -5.817 Ea 4597.2x8.1345J/Kmol 11 46 30.0 303.0 1.087E-05 0.0054348 0.003300 -5.215 12 31 31.0 304.0 1.613E-05 0.0080645 0.003289 -4.820 Ea= 37.39592 kJ 13 47 17.0 290.0 1.064E-05 0.0053191 0.003448 -5.236 14 153 6.5 279.5 3.268E-06 0.0016340 0.003578 -6.417 Activation Energy
Run 1 [1]。 Sample Calculation M1V1 = M2V2 0.200M 20.00mL = M2 20.00mL M2 = 0.2000 M Run 1 [S₂O] Sample Calculation M1V1M2V2 0.00500M *10.00mL = M2*50.00mL M2 = 0.001000 M Run 1 [S2O2] Sample Calculation M1V1 = M2V2 0.100M 20.00mL = M2 20.00mL M2 = 0.100 M Run 1 rate =-d[S₂O,1/2dt [S20,2]=0.001000 M = rate [0.001000 M]/2t rate = 0.0005000 M/t To Find the order of reactants and to find the overall order of reacation: Run 1 Run 2 Run 1 Run 2 m n rate= k [1] [S₂O,²]," 3.571E-06=k(0.2000)0^m(0.0500)0^n 2.488E-06 k(0.2000) o^m (0.1000)o^n Run 5 Run 4 m rate = k [1] [S₂O,²]," 2.825-06=k(0.06680)0^m(0.10000)0^n 4.589E-06 = k(0.1000)0^m(0.1000)0^n Run 5 = 2.825-06 k(0.06680)0^m Run 4 4.589E-06 = k(0.1000)0^m 3.571E-06 (0.0500)0^n 2.488E-06 (0.1000)o^n 1.44 0.157068 = 2^n =n* 0.301029996 n = 0.521769 = 1 OVERALL Order Of Rx = 2 rate [][S2O-2]0 0.615819 = .6680^m -0.210547 =m* -0.17522 m = 1.20159 =1 RUN Time T T S °C K rate--d[S20, 1/2dt mol/Ls ⚫k 1 In (k) T(K) 12345 140 20.0 293.0 3.571E-06 0.0017857 0.003413 -6.328 201 20.0 293.0 2.488E-06 0.0012438 0.003413 -6.690 310 20.0 293.0 1.613E-06 0.0008065 0.003413 -7.123 109.00 20.0 293.0 4.587E-06 0.0022936 0.003413 -6.078 177 20.0 293.0 2.825E-06 0.0014124 0.003413 -6.562 average k 0.0015084 Uncatalyzed Reaction. R=8.3145 J/Kmol RUN Time T T rate--d[S,O,1/2dt *k 1 In (k) Ea/R=3337.9 S °C K mol/Ls T(K) Runs 1-5 20.0 293.0 average k 0.0003017 0.003413 -6.556 Ea-3337.9x8.1345J/Kmol 6 78 30 303.0 6.410E-06 0.0032051 0.003300 -5.743 7 69 40.0 313.0 7.246E-06 0.0036232 0.003195 -5.620 Ea= 27.15215 kJ 8 195 11.9 9 239 4.5 284.9 277.5 2.564E-06 2.092E-06 0.0012821 0.003510 0.0010460 -6.659 0.003604 -6.863 Activation Energy Catalyzed Reaction R=8.3145 J/Kmol RUN Time T T rate--d[S,O,1/2dt "k 1 In (k) Ea/R=4597.2 S °C K mol/Ls T(K) 10 84 20.0 293.0 5.952E-06 0.0029762 0.003413 -5.817 Ea 4597.2x8.1345J/Kmol 11 46 30.0 303.0 1.087E-05 0.0054348 0.003300 -5.215 12 31 31.0 304.0 1.613E-05 0.0080645 0.003289 -4.820 Ea= 37.39592 kJ 13 47 17.0 290.0 1.064E-05 0.0053191 0.003448 -5.236 14 153 6.5 279.5 3.268E-06 0.0016340 0.003578 -6.417 Activation Energy
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter1: Getting Started
Section: Chapter Questions
Problem 9PQ: The distance to the Sun is 93 miIlion miles. What is the distance to the Sun in the appropriate SI...
Related questions
Question
For the Results & Conclusions
• Summarize results
• Provide sources of error discussed offer explanations for anomalous results
Please se both images provided please
![Run 1
[1]。
Sample Calculation
M1V1 = M2V2
0.200M 20.00mL = M2 20.00mL
M2 =
0.2000 M
Run 1
[S₂O] Sample Calculation
M1V1M2V2
0.00500M *10.00mL = M2*50.00mL
M2 =
0.001000 M
Run 1
[S2O2] Sample Calculation
M1V1 = M2V2
0.100M 20.00mL = M2 20.00mL
M2 =
0.100 M
Run 1
rate =-d[S₂O,1/2dt
[S20,2]=0.001000 M
=
rate [0.001000 M]/2t
rate
=
0.0005000 M/t
To Find the order of reactants and to find the overall order of reacation:
Run 1
Run 2
Run 1
Run 2
m
n
rate= k [1] [S₂O,²],"
3.571E-06=k(0.2000)0^m(0.0500)0^n
2.488E-06 k(0.2000) o^m (0.1000)o^n
Run 5
Run 4
m
rate = k [1] [S₂O,²],"
2.825-06=k(0.06680)0^m(0.10000)0^n
4.589E-06 = k(0.1000)0^m(0.1000)0^n
Run 5
=
2.825-06 k(0.06680)0^m
Run 4
4.589E-06 = k(0.1000)0^m
3.571E-06 (0.0500)0^n
2.488E-06 (0.1000)o^n
1.44
0.157068
= 2^n
=n* 0.301029996
n =
0.521769 = 1
OVERALL Order Of Rx = 2
rate [][S2O-2]0
0.615819 = .6680^m
-0.210547
=m* -0.17522
m =
1.20159 =1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdab67aeb-c4d9-43f7-88d0-dfd6e7af2d5d%2F3ddcd546-2766-4b91-9c1b-d6a5d87516bf%2F1ghgzc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Run 1
[1]。
Sample Calculation
M1V1 = M2V2
0.200M 20.00mL = M2 20.00mL
M2 =
0.2000 M
Run 1
[S₂O] Sample Calculation
M1V1M2V2
0.00500M *10.00mL = M2*50.00mL
M2 =
0.001000 M
Run 1
[S2O2] Sample Calculation
M1V1 = M2V2
0.100M 20.00mL = M2 20.00mL
M2 =
0.100 M
Run 1
rate =-d[S₂O,1/2dt
[S20,2]=0.001000 M
=
rate [0.001000 M]/2t
rate
=
0.0005000 M/t
To Find the order of reactants and to find the overall order of reacation:
Run 1
Run 2
Run 1
Run 2
m
n
rate= k [1] [S₂O,²],"
3.571E-06=k(0.2000)0^m(0.0500)0^n
2.488E-06 k(0.2000) o^m (0.1000)o^n
Run 5
Run 4
m
rate = k [1] [S₂O,²],"
2.825-06=k(0.06680)0^m(0.10000)0^n
4.589E-06 = k(0.1000)0^m(0.1000)0^n
Run 5
=
2.825-06 k(0.06680)0^m
Run 4
4.589E-06 = k(0.1000)0^m
3.571E-06 (0.0500)0^n
2.488E-06 (0.1000)o^n
1.44
0.157068
= 2^n
=n* 0.301029996
n =
0.521769 = 1
OVERALL Order Of Rx = 2
rate [][S2O-2]0
0.615819 = .6680^m
-0.210547
=m* -0.17522
m =
1.20159 =1
Transcribed Image Text:RUN Time
T
T
S
°C
K
rate--d[S20, 1/2dt
mol/Ls
⚫k
1
In (k)
T(K)
12345
140
20.0
293.0
3.571E-06
0.0017857 0.003413
-6.328
201
20.0
293.0
2.488E-06
0.0012438
0.003413
-6.690
310
20.0
293.0
1.613E-06
0.0008065
0.003413
-7.123
109.00
20.0
293.0
4.587E-06
0.0022936
0.003413
-6.078
177
20.0
293.0
2.825E-06
0.0014124
0.003413
-6.562
average k
0.0015084
Uncatalyzed Reaction.
R=8.3145 J/Kmol
RUN Time
T
T
rate--d[S,O,1/2dt
*k
1
In (k)
Ea/R=3337.9
S
°C
K
mol/Ls
T(K)
Runs 1-5
20.0
293.0
average k
0.0003017
0.003413
-6.556
Ea-3337.9x8.1345J/Kmol
6
78
30
303.0
6.410E-06
0.0032051
0.003300
-5.743
7
69
40.0
313.0
7.246E-06
0.0036232 0.003195
-5.620
Ea=
27.15215 kJ
8
195
11.9
9
239
4.5
284.9
277.5
2.564E-06
2.092E-06
0.0012821 0.003510
0.0010460
-6.659
0.003604
-6.863
Activation Energy
Catalyzed Reaction
R=8.3145 J/Kmol
RUN Time
T
T
rate--d[S,O,1/2dt
"k
1
In (k)
Ea/R=4597.2
S
°C
K
mol/Ls
T(K)
10
84
20.0
293.0
5.952E-06
0.0029762
0.003413
-5.817
Ea 4597.2x8.1345J/Kmol
11
46
30.0
303.0
1.087E-05
0.0054348
0.003300
-5.215
12
31
31.0
304.0
1.613E-05
0.0080645
0.003289
-4.820
Ea=
37.39592 kJ
13
47
17.0
290.0
1.064E-05
0.0053191
0.003448
-5.236
14
153
6.5
279.5
3.268E-06
0.0016340 0.003578
-6.417
Activation Energy
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