Question#03: Justify: why electrical isolation and theft prevention are the advantages of non-conductive cable? Justify: why low attenuation and immunity to electromagnetic interference are the disadvantages of a conductive cable?

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A: The maximum power will be delivered to the load if the Ro is same as load resistance.

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A: We need to find out overall noise figure .

Q: 21. Referring to problem 18, determine 14. O 1.299 A O 1.216 A 1.259 A O 1.265 A

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Q: R2Ž volt) Fig. 2. An AC circuit with a non-sinusoidal wave. (1) Analytical part: (i) Derive the resp...

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Q: 9. Solve for maximum power transfer. * 2 A 4Ω ww ww 2Ω RL. 4 A b 20 V 33.33 W 23.33 W 36.67 W 40.14 ...

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Q: If a power lost a ratio of 0.01 represents -20 dB and a power gain ratio of 2 represents 3 dB. Solve...

A: power in dB = 10 log(power gain).    

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Q: RC1 1.5k2 SR1 $4.7k2 Q2 Rs R2 1k2 RE2 1502 RL 1k2 RE1 330Ω Zin Zo Assume hfe=ß=100 and Vbe=0.7V for ...

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Q: Get the sum of two signals. V1 = a sin (120π t + b) V2 = c sin (120π t + d) Given: a = 38 b = -15...

A: Given that  V1 = a sin (120π t + b)V2 = c cos (120π t + d)Given:a = 38b = -15°c = 20d = 5°

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Q: Item 9 A point charge of 3.24 microcoulomb is running at a speed of 3 = 2 j+ 3 k. meters per second....

A: This question belongs to electro magnetic field theory . It is about calculation of electro magnetic...

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Q: Solve for the Vrms (magnitude only) across the capacitive reactance if R2 = 1024 ohms and Xc = 2144 ...

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Q: 1. Solve for the (a) total resistance and (b) total current of a 40 V AC voltage, with 100 Hz freque...

A: We are authorized to answer three subparts at a time, since you have not mentioned which part you ar...

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Q: R1=R3=2k R2=R4=20k RI R2 R5=R6=R7=10k Vi R8=50k R6 R8 Vol ww ww- V2 Vo R3 R4 + R5 V3 Vo2 ww R7 V4 ww...

A: Op-Amp: This is an integrated circuit and amplifies the gain of the circuit.  

Q: Determine the time constant for an RL circuit having an effective resistance of 1.15 ✕ 104 Ω and an ...

A: Given an RL circuit having, Effective resistance, R = 1.15 ✕ 104 Ω Inductance, L = 2.09 ✕ 10−2 H  

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