Q: Q5: Methanoic acid (HMeth) has a Ka of 1.78 * 106, so what is the pOH of a 0.23 M NaMeth solution?
A: Methanoic acid (HMeth) ka= 1.78×10-6NaMeth = 0.23 MCalculate the pOH of solution
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Q: Methanoic acid (HMeth) has a Ka of 1.78 * 10-6, so what is the pOH of a 0.23 M NaMethsolution?
A: The objective of this question is to calculate the pOH of a 0.23 M NaMeth solution, given that the…
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