In the fruit fly Drosophila, a rudimentary wing called vestigial and the dark body color called ebony are inherited at independent loci and are recessive to their dominant wild type counterparts, full wing and gray body color. Dihybrid males and females displaying both wild type phenotypes are crossed, and 3200 progeny are produced. How many progeny flies are expected in each of the phenotypic classes produced?
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- estion 2 of 15 Ⓒ Macmillan Learning > Match each phenotype description to its corresponding sex chromosome genotype in humans. XX with SRY on X phenotypically female but karyotype indicates presence of both sex chromosomes XY with SRY deleted phenotypically male but karyotype indicates presence of only X chromosomes hp XXXX phenotypically female with some abnormalities and overexpression of X chromosome genes Answer Bank A 0 XXY phenotypically male with sterility and hypogonadism € US ES ☐ Attempt 2 Apr 1 XYY phenotypically male with an increase in average stature 3:52 STAYThe gene for flower position in pea plants exists as axial or terminal alleles. Given that axial is dominant to terminal, list all of the possible F1 and F2 genotypes and phenotypes from a cross involving parents that are homozygous for each trait. Express genotypes with conventional genetic abbreviations.Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?
- dd-ons Help в I U A Calibri 12 三 三1 |:三 6. Consider a guinea pig with a homozygous genotype and a white fur color phenotype. a. What is the probability this parent will produce a gamete with the dominant allele? b. What is the probability this parent will produce a gamete with the recessive allele? C. If 31 sperm cells are collected from this guinea pig, how many would you expect to have the recessive allele (as determined by sequencing the gene)? !!!Homozyogous wild type male Drosophila PPQQRRSSTTUUVV (all linked) are irradiated to induce the formation of chromosomal deletions and then mated with homozygous recessive females. In several of these matings a unique pattern of pseudodominance could be correlated with the loss of specific polytene chromosome bands, as shown in the table... Cross Chromosomal Bands Deleted Pattern of Pseudodominance PqRs TuV 1 2 3 4 5 5-6 1-2 3-5 6-8 1-3 PQRSTUV PqrSTUV PQRSTUV pQrSTUV In which chromosomal band is gene R located? A. 3 OB. 4 OC. 2 D.8 O E. none of these answers are correctMale Drosophila expressing the autosomal recessivemutations sc (scute), ec (echinus), cv (crossveinless),and b (black) were crossed to phenotypically wildtype females, and the 3288 progeny listed wereobtained. (Only mutant traits are noted.)653 black, scute, echinus, crossveinless670 scute, echinus, crossveinless675 wild type655 black71 black, scute73 scute73 black, echinus, crossveinless74 echinus, crossveinless87 black, scute, echinus84 scute, echinus86 black, crossveinless83 crossveinless1 black, scute, crossveinless1 scute, crossveinless1 black, echinus1 echinusa. Diagram the genotype of the female parent.b. Map these loci.c. Do the data provide evidence of interference?Justify your answer with numbers.
- 8-9. White eyes (w) is sex-linked and recessive in Drosophila. Cruved wings(cu) and black body (b) are autosomal recessive alleles on the same chromosome, separated by 20 map units. If one breeds a homozygous white, curved winged female fly to a homozygous black male fly to produce an F1, and inbreeds the F1 males and females, at what frequency is a phenotypically wild-type male expected? (note: male flies do not cross over) A. 0.25 es B.0.05 C.0.10 D. 0.20 E.0.125Drosophila females heterozygous for each of three recessive autosomal mutations with independent phenotypic effects [thread antennae (th), hairy body (h), andscarlet eyes (st)] were testcrossed to males showingall three mutant phenotypes. The 1000 progeny of thistestcross werethread, hairy, scarlet 432wild type 429thread, hairy 37thread, scarlet 35hairy 34scarlet 33a. Show the arrangement of alleles on the relevantchromosomes in the triply heterozygous females.b. Draw the best genetic map that explains these data.c. Calculate any relevant interference valuesselect whcih ic correct When 2 wildtype alleles are on the same parental chromosome, this is known as [Combined or Coupling or dispersed or heterozygous or Repulsion] . In sharp contrast [Combined or Coupling or dispersed or heterozygous or Repulsion] is when 1 wildtype allele and 1 mutant allele are on the same parental chromosome
- uh ec CV + + 10.5 SC 9.1 scute bristles echinus eyes 9.2 ct + crossveinless wings Table 1: phenotype wild-type tapdance feet crossveinless wings tapdance & crossveinless cut wings 15.9 vermilion eyes V + + 66.8 Drosophila X chromosome Use the map provided above for problems 1 & 2. Problem 1: 11.2 10.9 garnet eyes M A new gene is being investigated in fruit flies. The recessive allele of this gene (t) causes the flies' feet to grow tiny tapdance shoes, while the dominant allele (t*) permits wild-type feet to develop. Preliminary studies indicate that this new gene is located on the X-chromosome. You decided to perform a two-point testcross to determine its position relative to the well-established crossveinless wings gene (cv). You cross a female heterozygous for both genes with a testcross male fly and obtain the male offspring results shown in table 1, below. Using this information, answer the following questions: # male offspring 13 405 401 11 forked bristles a) is the original…16 - The phenotype of vestigial (short) wings (vg) in Drosophila melanogaster is caused by a recessive mutant gene that independently assorts with a recessive gene for hairy (h) body. Assume that a cross is made between a fly the is homozygous for normal wings with a hairy body and a fly with vestigial wings that is homozygous for normal body hair. The wild-type F1 flies were crossed among each other to produce 1024 offspring. Which phenotypes would you expect among the 1024 offspring, and how many of each phenotype would you expect? a) Phenotypes: wild, vestigial, hairy, and vestigial hairy; Numbers expected: wild (256), vestigial (256), hairy (256), and vestigial hairy (256). b) O Phenotypes: wild, vestigial, hairy, and vestigial hairy; Numbers expected: wild (576), vestigial (192), hairy (192), and vestigial hairy (64). C) O Phenotypes: wild, vestigial, hairy, and vestigial hairy; Numbers expected: wild (192), vestigial (256), hairy (64), and vestigial hairy (192). d) All vestigial…A Drosophila male is heterozygous for a reciprocaltranslocation between an autosome and the Y chromosome. The part of the autosome now present onthe Y chromosome contains the dominant mutationLyra (shortened wings); the other (normal) copyof the same autosome is Lyra+. This male is nowmated with a true-breeding, wild-type female. Whatkinds of progeny would be obtained, and in whatproportions?