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Fe²+ + O2(eq) + H+ (eq) eq AG°f=(Fe²+eq = -78.87),( 02(eq) = 16.32),( H+ Will the forward rxn occur? Step 1: balance the reaction. Step 2 calculate AG° = -RT ln k {C}{D}d {A}{B}b. Step 3 calculate k = Step 4 calculate Q mg If there is 0.001 M of Fe2+, 0.002M of Fe³+,8- of 02. And 10-7M of H+. L = = (eq) {C} c{D}d {A}a{B}b Step. 5 compare K and Q. using AG -RT ln k. Alternative: step 3: Calculate AG using AG = AG° + RT ln Q → Fe³+ eq + H₂0 (1) eq = -4.60), (H₂0 (1) = -237.18) 0),( Fe³+

Fe²+ + O2(eq) + H+ (eq) eq AG°f=(Fe²+eq = -78.87),( 02(eq) = 16.32),( H+ Will the forward rxn occur? Step 1: balance the reaction. Step 2 calculate AG° = -RT ln k {C}{D}d {A}{B}b. Step 3 calculate k = Step 4 calculate Q mg If there is 0.001 M of Fe2+, 0.002M of Fe³+,8- of 02. And 10-7M of H+. L = = (eq) {C} c{D}d {A}a{B}b Step. 5 compare K and Q. using AG -RT ln k. Alternative: step 3: Calculate AG using AG = AG° + RT ln Q → Fe³+ eq + H₂0 (1) eq = -4.60), (H₂0 (1) = -237.18) 0),( Fe³+

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Fe²+ + O2(eq) + H+ eq AG°f=(Fe2+ eq = -78.87),(02(eq) If there is 0.001 M of Fe²+, 0.002M of Fe³+,8- Will the forward rxn occur? Step 1: balance the reaction. Step 2 calculate AG° = -RT ln k {C}c{D}a {A}a {B}b Step 3 calculate k Step 4 calculate Q = = {C} c{D}d {A} a{B}b Step. 5 compare K and Q. using AG° = -RT ln k. = (eq) 16.32), (H+ = (eq) Alternative: step 3: Calculate AG using AG = AG° + RT In Q mg L → Fe³+ eq + H₂O (1) = 0),( Fe³+ eq = -4.60), (H₂0 (1) = -237.18) of 0₂. And 10-7M of H+.
Transcribed Image Text:Fe²+ + O2(eq) + H+ eq AG°f=(Fe2+ eq = -78.87),(02(eq) If there is 0.001 M of Fe²+, 0.002M of Fe³+,8- Will the forward rxn occur? Step 1: balance the reaction. Step 2 calculate AG° = -RT ln k {C}c{D}a {A}a {B}b Step 3 calculate k Step 4 calculate Q = = {C} c{D}d {A} a{B}b Step. 5 compare K and Q. using AG° = -RT ln k. = (eq) 16.32), (H+ = (eq) Alternative: step 3: Calculate AG using AG = AG° + RT In Q mg L → Fe³+ eq + H₂O (1) = 0),( Fe³+ eq = -4.60), (H₂0 (1) = -237.18) of 0₂. And 10-7M of H+.
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