Homework Help is Here – Start Your Trial Now!
Engineering
Chemical Engineering
calculate the Ergun parameter, ?. using the following parameters,  you will need to do some unit conversion, i think i did it correctly i have added the eqautions that need to be used,

calculate the Ergun parameter, ?. using the following parameters,  you will need to do some unit conversion, i think i did it correctly i have added the eqautions that need to be used,

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
See similar textbooks
icon
Related questions
Question
100%

calculate the Ergun parameter, ?. using the following parameters, 

you will need to do some unit conversion, i think i did it correctly i have added the eqautions that need to be used, 

α - m = 104.4 lbm/hour Air Operating conditions: Feed (air): Catalyst properties: Reactor dimensions: a = T = 260 °C (isothermal) Mo = 0.0673 lbm/ (ft * hr) Pcat = 72 lbm/ft³ p = 0.36 1.5 inch SCH 40 pipe (13) * 2* G * (1¹17) & b Po*Po*9c*Dp*Pcat* Ac Ac 2*G Po Po 9c*Dp*Pcat* Ac G = p*um * Ac P₁ = 21162.266 lbf ft² & gc = Catalyst particles 150*(1-0)*μ Dp 104.4 lbm hr Dpart = = 4.17 x 108. = + 1.75* Gor 150*(1-φ)*μ Dp 1 0.01414 ft² lbm*ft lbf*hr2 P = 10 atm Po = 0.413 lbm/ft³ Dpart = 0.64inches Ac = 0.01414 ft² 0.64 | 1 ft 0.641/7 12 in = +1.75 G → a= a*b G] = 7383.310 0.053 ft lbm ft² * hr
Transcribed Image Text:α - m = 104.4 lbm/hour Air Operating conditions: Feed (air): Catalyst properties: Reactor dimensions: a = T = 260 °C (isothermal) Mo = 0.0673 lbm/ (ft * hr) Pcat = 72 lbm/ft³ p = 0.36 1.5 inch SCH 40 pipe (13) * 2* G * (1¹17) & b Po*Po*9c*Dp*Pcat* Ac Ac 2*G Po Po 9c*Dp*Pcat* Ac G = p*um * Ac P₁ = 21162.266 lbf ft² & gc = Catalyst particles 150*(1-0)*μ Dp 104.4 lbm hr Dpart = = 4.17 x 108. = + 1.75* Gor 150*(1-φ)*μ Dp 1 0.01414 ft² lbm*ft lbf*hr2 P = 10 atm Po = 0.413 lbm/ft³ Dpart = 0.64inches Ac = 0.01414 ft² 0.64 | 1 ft 0.641/7 12 in = +1.75 G → a= a*b G] = 7383.310 0.053 ft lbm ft² * hr
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Introduction to Chemical Engineering Thermodynami…
Introduction to Chemical Engineering Thermodynami…
Chemical Engineering
ISBN:
9781259696527
Author:
J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:
McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemical Engineering
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
Elements of Chemical Reaction Engineering (5th Ed…
Elements of Chemical Reaction Engineering (5th Ed…
Chemical Engineering
ISBN:
9780133887518
Author:
H. Scott Fogler
Publisher:
Prentice Hall
Process Dynamics and Control, 4e
Process Dynamics and Control, 4e
Chemical Engineering
ISBN:
9781119285915
Author:
Seborg
Publisher:
WILEY
Industrial Plastics: Theory and Applications
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:
9781285061238
Author:
Lokensgard, Erik
Publisher:
Delmar Cengage Learning
Unit Operations of Chemical Engineering
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:
9780072848236
Author:
Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:
McGraw-Hill Companies, The
SEE MORE TEXTBOOKS