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- A heterozygous individual has a _______ for a trait being studied. a. pair of identical alleles b. pair of nonidentical alleles c. haploid condition, in genetic termsThe following pedigree shows the pattern of inheritance of red green color blindness in a family. Females are shown as circles and males as squares; the squares or circles of individuals affected by the trait are filled in red. What is the chance that a son of the third-generation female indicated by the arrow will be color-blind if the father is a normal man? If the father is color-blind?In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
- 1. Red-green colorblindness is caused by a recessive allele (x) at an X-linked gene, and albinism is caused by a recessive allele (a) at an autosomal gene. A phenotypically normal woman (Sara) has a father who is colorblind, and she knows that she is a carrier for albinism. She plans to have a child with a colorblind man (Abdul) who is also a carrier for albinism. What is the probability that Sara and Abdul's child will have one of the conditions, but not both? (C. Follow the steps below to answer this question. a) What is the cross? b) What are the target genotypes? Note: it might be useful to come back to this one and double- check it after you have completed step c, below. Break this down to the single gene level by answering the following questions: a. What is the proportion of normal to albino offspring? Show the Punnett square: b. What is the proportion of normal to colorblind offspring? Show the Punnett square: d) What is the probability that Sara and Abdul's child will have one…5. A woman who is a carrier for colorblindness marries a colorblind man. The woman nas 5 nngers on each hand and the man, whose father had father had 5 fingers, has 6 fingers. (Polydactyly-have 6 fingers on each hand-is inherited as an autosomal dominant trait. What percent of their children do you expect to be colorblind with 5 fingers? man with type AB blood is married to a woman with type O blood. They have 2 natural children 01one adopted child. 'One child has type A blood, one has type B blood and the other has type O blood. Whi s adopted?9. Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
- 1. Two normal visioned parents have a color-blind son. Give the genotype of both parents and the son. 2. In cats, the allele (B) produces black color but (b) produces a yellow color. These alleles are incompletely dominant to each other. A heterozygote produces a tortoise shell color. The alleles (B) and (b) are sex-linked as well. Cross a tortoise shell female with a yellow male. a. What percent of their offspring will be yellow? b. What percent of their offspring will be black? c. What percent of their offspring will be tortoise shell? d. Why is it impossible to have a tortoise shell male offspring?5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? Horned: r: Roan Coat: a. Possible genotypes for Polled condition Coat:_ ossible geno c. Male genotype: d. Female genotype: Male possible gametes Female possible gametes e. f. Genotypic Ratio: g. Phenotypic Ratio 5B, Breed two of the F1 generation to determine the possibilities in the F2 generation. Horned: a. Possible genotypes for Polled condition b. Possible genotypes for Red coat: White Coat:_ Roan Coat: c. Male genotype: d. Female genotype Male possible gametes Female possible gametes: f. Genotypic Ratio: g. Phenotypic Ratio5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? a. Possible genotypes for Polled condition: Horned: b. Possible genotypes for Red coat:White Coat: Roan Coat: c. Male genotype Male possible gametes: Female genotypeFemale possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio:
- 2. Can a color-blind female have a son that has normal vision? Color blindness is caused by a sex-linked recessive allele. Explain. Do the Punnett square. *use N = normal vision and n = color blind over X and Y chromosomes. 3. Muscular dystrophy is a sex-linked trait. What parental genotypes could produce a female with=muscular dystrophy? Do the Punnett square. *use M = normal muscles, and m = muscles missing dystrophin protein over X and Y chromosomes. 4. In humans, red-green color-blindness is due to a recessive gene X^c. Normal vision results from the dominant gene X^c. If a homozygous woman of normal vision marries a color-blind man, what type of vision will be expected in their children?1. Assume Mendelian inheritance laws apply, and a trait is either completely dominant or recessive. Eye color: Br - dominant brown blE -recessive blue Hair color Br" -- dominant brown bl" - recessive blonde A male with brown eyes and brown hair (genotype Br"Br"Br"bl") is planning on having a child with a fen who has blue eyes and brown hair (genotype bl"bl"Br"bl"). A) Fill in all blanks (8 total) to complete the two-trait Punnett Square Possible allelic combinations in male gametes 1) bl°Br" 2) bl*bl* 3)_bl* BrM 6) BrʻL* 5) 7) B, Br" 8) Bríbl' B) What are the three unique genotypic combinations of hair and eye color possible in the child? C) What is the expected phenotypic ratio? D) What is the probability that the couple will have a child with blonde hair? Possible allelic combinations in female gametes6. A person is simultaneously heterozygous for two autosomal genetic traits. One is a recessive condition foralbinism (alleles A and a); this albinism gene is foundnear the centromere on the long arm of an acrocentricautosome. The other trait is the dominantly inheritedHuntington disease (alleles HD and HD+). TheHuntington gene is located near the telomere of oneof the arms of a metacentric autosome. Draw all copies of the two relevant chromosomes in this person asthey would appear during metaphase of (a) mitosis,(b) meiosis I, and (c) meiosis II. In each figure, labelthe location on every chromatid of the alleles forthese two genes, assuming that no recombinationtakes place.