4.8 In this exercise, we examine how pipelining affects the clock cycle time of theprocessor. Problems in this exercise assume that individual stages of the datapathhave the following latencies:IFIDEXMEMWB250ps350ps150ps300ps200psAlso, assume that instructions executed by the processor are broken down asfollows:alubeqIwSW45%20%20%15%4.8.1 [5] <$4.5> What is the clock cycle time in a pipelined and non-pipelinedprocessor?4.8.2 [10] <$4.5> What is the total latency of an LW instruction in a pipelinedand non-pipelined processor?4.17 Exercises3614.8.3 [10] <$4.5> If we can split one stage of the pipelined datapath into two newstages, each with half the latency of the original stage, which stage would you splitand what is the new clock cycle time of the processor?

4.8 4.8.1 Pipelining: All the stages take a single clock cycle in pipelining, so the clock cycle…

Answered: 4.8 In this exercise, we examine how…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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6. What is the address of executing the following instruction: MOV CX, [FEH] if you know that DS= DC00H? OCL: DCOFEH, CH: DCOFFH OCL: DCFEH, CH: DCFFH CL: DCFFH, CH: DCFFH CL: DCOFFH, CH: DCOFFH
Consider a hypothetical computer having instruction length 32 bit and Byte addressable memory. You need to run a program P having 10 Q.4 CO4 instructions 11,12,13...10. All the instructions are stored in consecutive memory locations started from 1000. To run an instruction li, you have to complete four operations: Fetch, Decode, Execute, and Store. The content of Program Counter will be after the completion of fetch operation of instruction 12. There are no jump or branch instruction in program P
Question 5: What is the role of the Command Line Interpreter?
Q2. Refer to datapath design on slide no. 26 with added blocks for jump instructions as shown inslide 33 in Chapter 4 (part 1). Let’s assume a program has 500 instructions. These instructions aredistributed as follows:R-Type Immediatearithmetic(addi)Load Store Branch Jump25% 5% 20% 20% 10% 20%Answer the following questions (show calculations):a) How many instructions will use instruction memory?b) How many instructions will use data memory?c) How many instructions will use the sign extend block?d) In the clock cycles, where the sign extend block is not required, does it remain idle? If yes,how? If not, what happens to the output of the block in that cycle? chapter 4, slide 33 is added as an image needed to solve the question
Assignment-04. A non-pipelined CPU has 12 general purpose registers (RO, R1, R2, . Following operation are supported: R12), .... ADD Ra, Rb, Rr Add Ra to Rb and store the result in Rr MUL Ra, Rb, Rr Multiply Ra to Rb and store the result in Rr MUL operations takes two dlock cycles, ADD takes one clock cycle. Calculate minimum number of clock cycles required to compute the value of the expression XY +XYZ + YZ The variables X,Y, Z are initially available in registers RO, R1 and R2 and contents of these registers must not be modified,
Q2/ The following program have been executed by an 8085 Microprocessor. Write down the sequence of the process with explain of each step. Address (Hex) 8085 Instruction LXI H, FFFE H -ds EH= FF L-FE H=Ff,L=Ff A-5 A-5 6010 6011 MVI M, 10 6012 LXI H, FFFF- 6013 MVI A, 5- 6014 MVI M, 5. 6015 LXIH,6.1 ADD M 6016 6017 ADD M 6018 A+FFFF +cy 6019 6020 6021 LHLD FFFE MOV A, H MOV B,L SUB B >LHLD, 6013 -13, STA FFFF LAD FFFF A MVI H
Rspected Sir, please chek my qustioin 1. Calculate the sum of series of even numbers from the list of numbers. The length of the list is in ML 2200H and series itself begins from ML 2201H. Assume the sum to be greater than FFH. Store the results in ML 2300H and 2301H. 2. Discuss the working of CALL instruction in 8085 microprocessor by taking the suitable example. Also, mention various conditional CALL instructions of 8085 microprocessor.
Computer Science Please use the RISC V instruction format. Implement a function that attempts to obtain a ticket a concert. The function will run on hundreds of sites, so the function must atomically decrement a shared global variable representing the number of seats still available using the load reserved, store conditional instructions. The address of the memory location storing the current number of available seats is passed into the routine and you will have to put it into a register. A Boolean value 1 is returned in X18 if a seat is available. A Boolean 0 is returned if no more seats are available. result = get_tickets(int *seats_available) { }.
In this case, every instruction receives its own data, independent of how the data for other instructions is obtained. We make advantage of a: A Multiple Data/Instruction B Multiple Iterations of Data or Instruction C Singular Data Single Inst D Singe Inst Multiple
Exercise 37. Give an example of an execution that is valid for a quiescently-consistent execution on atomic registers but not not valid a linearizable execution on regular registers.
Q1- Write a program in assembly language for the 8085 microprocessor to send 10 bytes of data located at the memory address (3000H to 3009H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending each of the required bytes, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes. The solution must be integrated and include the calculation of the baudrate delay time Transmit No Set up Character Bit Counter Send Start Bit Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes Add Parity if Necessary • Send Two Stop Bits Return (a)
10 Execute the following instruction. What will be the new value of the lowest byte of memory content after execution? Assume: DS= 9406H, BX=FDFAH, AX=F401H, SS= A300H, BP = OE61H, SI = 77A2H, SP= E60H PUSH SI * O 77 H 27 H None 7AH A7 H A2 H 72 H

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