3.) Logic Function F(x,y,z,w) =∑ m(0,2,4,6,8,13) + ∑ k(10,12) is given as the sum of miniterms. (Note: There are terms that are ignored.) a. Obtain the Truth Table. b. Simplify with the Karnough Map approach. NS. Implement the simplified Logic circuit with only two-input AND-NOT (NAND) gates.
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- 4. A combinational logic circuit that compares between two 2-bit numbers A (AI A0) and B (B1 B0) is designed. Output F is high when A > B and low when A < B. a. Are there any conditions which cause none of the outputs to be asserted? If the conditions exist, what are the inputs? b. Derive the truth table and obtain the maxterm notation for the output. c. Obtain the minimized POS expression of the logic circuit. d. Draw the logic circuit using basic gates.Sub:Digtial Logic Design5) You want to design an arithmetic comparison combined logic circuit.a. Write your design purpose of the 4-bit comparison (big-equal-small) circuit.b. List the process steps that you will apply in the design approach. Design a 4-bit comparison (large-equal-small) circuit. Explain each step. Realize with AND, OR, NOT gates.c. Compare the decimal numbers in the last two digits of your student number in the circuit you designed and discuss the result. last two digits of student number : 0 4 . Not : I want the solution to contain tables and equations, and the electrical circuit resulting from tables and equations, as in the picture that I attached,And if possible, Because it is normal when solving a question to have tables and equations. I want an integrated solution, please look at the question carefully before starting the solution because I have sent a question a lot
- Logic Function F (x, y, z, w) = ∑ m (0,2,4,6,10,13) + ∑ k (8,12) as sum of minimers are given. (Note: There are terms that are not taken into account.) a. Obtain the Truth Table. b. Simplify with the Karnough Map approach. c. Draw the simplified Logic circuit with two input AND-NOT (NAND) gates. How many elements you realized, what is your gain? Comment.A digital circuit for adding two binary digits has two inputs: the two digits to be added; and two outputs: the units bit and the twos bit of the answer. (a circuit of this kind is called half adder.) By treating this as two circuits, each with a single output, use Karnaugh maps to obtain a Boolean expression for each circuit, and draw the corresponding circuit diagrams.Q (A, B, C) = A̅ .B̅. C +A̅ .B. C + A .B. C̅ + A.B.C Karnaugh function given in the form Using the mapping method, you can use the simplified function separately in terms of minterms and maxters. obtain. Output functions with AND NOT for minterms and OR for maxters. Install separately with logic doors.
- Construct a circuit diagram that checks whether the two numbers A and B are in the ratio of 2:3. Also, derive the final Boolean equation for the function. F = 1 if A: B = 2: 3,0 otherwise Here, A and B both are 3 bit binary numbers. NB: You cannot use the IC of comparator, meaning for the comparison part, you need to draw the gate level diagram. You can use block level diagrams for the rest of the parts.a) Create a 4 Variable Karnaugh Map in paper by mapping 1’s for given standard SOP Boolean expression. After mapping , make relevant groups within Karnaugh Map by considering rules for making groups for 4 variable Karnaugh Map. After making relevant grouping , extract the minimum SOP expression by considering rules for extracting minimum SOP using Karnaugh Map. * Standard SOP: *Create Circuit Diagram using logic gates and logic converter in Multisim for given standard SOP and minimum SOP which you have solved. Do make sure that truth table for both expressions should evaluate same result.5. Simplify the following function using K-Map and draw logic diagram for that. E(A, B,CD)=Em(0,1,2,3,4,5,7,8,10,11,12,13,14,15)
- 2. Design a combinational logic circuit for 4-input majority circuit. A majority circuit is one which produces a HIGH (1) output when three or more inputs are HIGH (1). i. Construct the truth table and simplify the Boolean expression into SOP and POS forms using К-mаp. ii. Construct the logic diagram using AND-OR gate network with simplified SOP expression. iii. Construct the logic diagram using OR-AND gate network with simplified POS expression. iv. Construct the logic diagram using only NAND gates with simplified SOP expression. v. Construct the logic diagram using only NOR gates with simplified POS expression.- The proportional distribution of A, B, C, D signals is given in the table as a percentage. It “logic 1” when the signals are accepted as active, “logic 0” when they are accepted as passive. takes. - When the proportional sum of active signals is over 50%, its output is "logic1", When we accept "logic 0" when it is below 50%, the output in the table Find the values. - Create an X function based on the logic values you find. Simplify the created X function. - Design the simplified function with NAND and NOR gates.- The proportional distribution of A, B, C, D signals is given in the table as a percentage. It “logic 1” when the signals are accepted as active, “logic 0” when they are accepted as passive. takes. - When the proportional sum of active signals is over 50%, its output is "logic1", When we accept "logic 0" when it is below 50%, the output in the table Find the values. - Create an X function based on the logic values you find. Simplify the created X function. - Design the simplified function with NAND and NOR gates. - Set up the circuits you designed with NAND and NOR gates and observe the outputs. Show the output values by drawing a table, applying all possibilities to the input values.