3.DNA (3'-5')MRNATRNAGCUCCUUACCACССCGUAUGGCUGGGAUCAmino Acid4.DNA (3'-5')AAGGTCGACMRNACCAAGGUGGUAGTRNAUACCGCGCGAmino Acid5.DNA (3'-5')GAATCGGGCСТАMRNAAUCUACUAGTRNAAAAUCUAUCAmino Acidmet For each of the following items, fill in either the DNA strand, the MRNA codons, the tRNA anticodons, or theamino acid sequence that have been left blank. If several sequences might work, choose only one.Furthermore, circle the start and the stop codons of each mRNA sequence.1.DNA (3'-5')ACGTACGGCCGGTTAAAGCATACTTTCTTGMRNATRNAAmino Acid2.DNA (3'-5')MRNAAUGACUAGCUGGGGGUAUUACUUUUAGAAATRNAAmino Acid3.DNA (3'-5')MRNATRNAGCUCCUUACCACСССCGUAUGGCUGGGAUCActivateGo to SettAmino Acid

Name: 3.DNA (3'-5')MRNATRNAGCUCCUUACCACССCGUAUGGCUGGGAUCAmino Acid4.DNA (3'
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Description: 3.DNA (3'-5')MRNATRNAGCUCCUUACCACССCGUAUGGCUGGGAUCAmino Acid4.DNA (3'-5')AAGGTCGACMRNACCAAGGUGGUAGTRNAUACCGCGCGAmino Acid5.DNA (3'-5')GAATCGGGCСТАMRNAAUCUACUAGTRNAAAAUCUAUCAmino Acidmet For each of the following items, fill in either the DNA strand,

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3. DNA (3'-5') MRNA TRNA GCU CCU UAC CAC ССС CGU AUG GCU GGG AUC Amino Acid 4. DNA (3'-5') AAG GTC GAC MRNA CCA AGG UGG UAG TRNA UAC CGC GCG Amino Acid 5. DNA (3'-5') GAA TCG СТА GGC MRNA AUC UAC UAG TRNA AAA UCU AUC Amino Acid met

3. DNA (3'-5') MRNA TRNA GCU CCU UAC CAC ССС CGU AUG GCU GGG AUC Amino Acid 4. DNA (3'-5') AAG GTC GAC MRNA CCA AGG UGG UAG TRNA UAC CGC GCG Amino Acid 5. DNA (3'-5') GAA TCG СТА GGC MRNA AUC UAC UAG TRNA AAA UCU AUC Amino Acid met

Biology Today and Tomorrow without Physiology (MindTap Course List)

5th Edition

ISBN:9781305117396

Author:Cecie Starr, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Christine Evers, Lisa Starr

Chapter7: Gene Expression And Control

Section: Chapter Questions

Problem 1VQ

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Given the following DNA sequence: 3'-TACTTNGTNCTNTCN-5' where N stands for any nucleotide, give the complementary mRNA sequence. Indicate direction of strand as 3'--> 5' or 5'--> 3' as in the given sequence above. Give the amino acid sequence of your mRNA sequencelin No. 1. Indicate direction of strand as above. Use all lowercase letters, 3-letter name of amino acid separated by a hyphen (-), no spaces in-between.
A strand of DNA contains this nucleotide sequence: TACTGCCTCCCCATAAGAATT. The corresponding nucleotide sequence of the mRNA strand from this DNA template is as follows: AUGACGGAGGGGUAUUCUUAA. Q: What is the amino acid sequence of the polypeptide that is produced form the mRNA strand? As well, draw a labelled diagram of the mRNA molecule being transcribed from this strand of DNA.
A segment of a polypeptide chain is Arg-Gly-Ser-Phe-Val-Asp-Arg. It is encoded by the following segment of DNA: GGCTAGCTGCTTCCTTGGGGA CCGATCGACGAAGGAACCCCT Note out the mRNA sequence generated by the template strant to produce that polypeptide chain Label each stran with its correct polarity (5' and 3' ends on each strand)
Consider the following DNA sequence, which codes for a short polypeptide: 5'-ATGGGCTTAGCGTAGGTTAGT-3' Determine the mRNA transcript of this sequence. You have to write these sequences from the 5' end to the 3' end and indicate those ends as shown in the original sequence in order to get the full mark. How many amino acids will make up this polypeptide? Determine the first four anticodons that will be used in order to translate this sequence.
If DNA segments changes from GCATAG to GCATA, this is a: MRNA Codon/Amino Acid Chart First Base Second Base Third Base U A G 0001 Phenylalanine UCU UAU1 Tyrosine (Tyr) UAC UGUT FCcysteine (Cys) UGCJ U UUCJ (Phe) UCC Serine (Ser) UCA U UUA1 UAAT UGA - Stop A FLeucine (Leu) UUG- FStop UAG- UCG- UGG - Tryptophan (Trp) G CU- CCU CGUT CAU1 Histidine (His) CAC U CUC FLeucine (Leu) CUA CC Proline (Pro) CCA CGC FArginine (Arg) CGA CAA1 Glutamine A CAGI (Glu) CGG- CUG- CCG- G AUU AAU1 Asparagine ACU1 AGUT FSerine (Ser) AGC- AUC FIsoleucine (le) ACC Threonir AACJ (Asn) A AUA- ACA (Thr) AAA1 FLysine (Lys) AAG- AGA, FArginine (Arg) AGG- A Start Methionine (Met) ACG- AUG - GUU- GCU GAU- GGU | Aspartic Acid GAÇJ(Asp) U GỤC Valine (Val) GUA GCC FAlanine (Ala) GGC Glycine (Gly) GGA G GAA1 Glutamic Acid A GCA GCG- GAGJ (Glu) GGG- GUG- G
Complete the protein synthesis for the partial DNA sequence for a normal FGFR3 gene (TOP) and mutated FGFR3 gene (BOTTOM). Remember, when filling in mRNA, use capital letters only. When filling in amino acids, use three letters, with the first letter capitalized. If you do not use this format, your answer may be marked wrong. DNA CCG TTC GGG GAA ССС MRNA Amino Acid DNA CCG TTC GGG GAA TCC MRNA Amino Acid
Using the codon charts in your text (section 6.1), fill in the chart below. [ /8] Original DNA sequence TAC GGA CAC GTT CGC AAC mRNA sequence tRNA anticodons Amino acid sequence Mutated DNA sequence TAC GGA CAC ATT CGC AAC mRNA sequence tRNA anticodons Amino acid sequence Type of mutation (highlight all that apply) Frameshift Nonsense Missense Silent Insertion Deletion Substitution
The sequence below is a template strand sequence for a gene (a very short one!). Identify the start codon and the amino acid sequence of this gene. Write your answer in 3 letter amino acid code. Put a hyphen between each amino acid. You should also include a description of any working or steps you have taken to determine your answer. 5' AGTCAGCAAGAAGACATCAGTGTTCCCATCTGT 3' Paragraph V B I U A = 8⁰ + v 11.
If DNA segments changes from GCATAG to GCATGG, this is a: MRNA Codon/Amino Acid Chart First Base Second Base Third Base A G UUU1 Phenylalanine UCUT UAUT FTyrosine (Tyr) UAC UGU, U FCysteine (Cys) UGCJ UUCJ (Phe) UCC Serine (Ser) UCA U UGA - Stop A UUA1 FLeucine (Leu) UUG- UAA1 FStop UAGJ UCG- UGG - Tryptophan (Trp) G CUU CAU1 CCU1 CGUT Histidine (His) CAC- CUC CCC Proline (Pro) CCA CGC FLeucine (Leu) CUA FArginine (Arg) CGA CAA1 Glutamine A CAGJ (Glu) CGG- CUG- CCG- ACU AAUJ Asparagine AUUT AGUT FSerine (Ser) AGC- U AUC FIsoleucine (lle) ACC AACJ(Asn) Threonine A AUA- (Thr) AAA1 FLysine (Lys) AAG- АСА AGA, FArginine (Arg) AGG- A Start Methionine AUG- (Met) ACG- G GUU GCU, GAU1 Aspartic Acid GGU U GAÇJ(Asp) GUC Fvaline (Val) GUA GCC GGC G Alanine (Ala) GCA Glycine (Gly) A GAAJ Glutamic Acid GGA GAG- (Glu) GUG- GCG- GGG- G
What amino acid sequence will be generated, based on the following DNA codon sequence? Did you read this question carefully also? Are you certain? (You may list the three letter abbreviations for the amino acids listed below) DNA Sequence: TAC AAG CCC TAG GCG ATA АТС [a] Table 1. MRNA codons & associated amino acids Second base C G UUU Phe UUC UCU UAU UGU U Тyr UAC Cys UGC UCC Ser UCA UAA Stop UGA Stop A UUA Leu UUG UCG UAG Stop UGG Trp G CUU CCU CAU] His CAC CGU CUC C CUA CGC Leu Pro CCA Arg CGA CAA Gin CUG CCG CAG CGG AUU ACU AAU Asn AAC Thr AAA Lys AAG AGU Ser AGC AUC Ile ACC AUA AGA Arg AGG ACA AUG Met or start ACG GUU GCU GAU GGU Asp GAC U GÚC GCC Ala GCA GGC Val GUA Gly GAA GGA Glu GAG GUG GCG GGG G Cooriaht O Pearson Education. Inc Dublishina as Beniamin Cumminas First base (5' end) Third base (3' end)
Below is a double-stranded DNA: ATATGTGGTCTCGGTCCGTTAGGCAAT TATACACCAGAGCCAGGCAATCCGTTA Which strand functions as the transcription template, the top one or the bottom one? Explain your reasoning What is the mRNA transcript and polypeptide from this strand? In the space below, copy the DNA strand that is transcribed, and write the mRNA transcript. Identify the polypeptide chain below it. Align the mRNA and polypeptide so that it is clear which DNA bases they came from.
The DNA in the coding strand below contains a short imaginary sequence for a short protein in Squibillus notables (imaginary bacterial organism). Indicate the mRNA and amino acid sequences. Label the 5' and 3' ends, the amino (N-terminus) and carboxyl (C-terminus) ends and start/stop codons, if present, as appropriate. 5'- ATGTACCTCGACGATCAAGGCAA -3'