. A self-locking C-clamp is used to hold a workpiece with a clamping force of 5000 lb. The screw has a mean radius of 0.5 in and a lead of 0.18 in. If the screw has a coefficient of friction of 0.15, the moment needed to unclamp the workpiece is best given by m'=r wtan (+Øs) M = (0.5) (5000) ton (8.53-3.27) M = 230ft 16 a. 43.6 ft-lb 6.230 ft-lb- 523 ft-lb 19.1 ft-lb =tan (0.15) healt

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.2.4P: Repeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.
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Please solve the problem in a handwritten format only with the correct answer. it would be well and good if you include a free body diagram.
8
6. A self-locking C-clamp is used to hold a workpiece with a clamping force of 5000 lb. The screw
has a mean radius of 0.5 in and a lead of 0.18 in. If the screw has a coefficient of friction of 0.15,
the moment needed to unclamp the workpiece is best given by
M'=r wtan (+Øs)
M = (0.5) (5000) tan (8.53-3.27)
M = 230 ft·16
a. 43.6 ft-lb
6.230 ft-lb-
523 ft·lb
19.1 ft-lb
=tan(0.15)
Ps= 8,53
= tail (2005)
8 = 3.27
C
Workpiece
500015
Transcribed Image Text:8 6. A self-locking C-clamp is used to hold a workpiece with a clamping force of 5000 lb. The screw has a mean radius of 0.5 in and a lead of 0.18 in. If the screw has a coefficient of friction of 0.15, the moment needed to unclamp the workpiece is best given by M'=r wtan (+Øs) M = (0.5) (5000) tan (8.53-3.27) M = 230 ft·16 a. 43.6 ft-lb 6.230 ft-lb- 523 ft·lb 19.1 ft-lb =tan(0.15) Ps= 8,53 = tail (2005) 8 = 3.27 C Workpiece 500015
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