In an L-R-C series ac circuit, the source has a voltage amplitude of 240 V, R = 90.0 Ω, and the reactance of the inductor is 320 Ω. The voltage amplitude across the resistor is 135 V. (a) What is the current amplitude in the circuit? (b) What is the voltage amplitude across the inductor? (c) What two values can the reactance of the capacitor have? (d) For which of the two values found in part (c) is the angular frequency less than the resonance angular frequency? Explain.
Want to see the full answer?
Check out a sample textbook solutionChapter 31 Solutions
University Physics (14th Edition)
Additional Science Textbook Solutions
Introduction to Electrodynamics
Conceptual Physical Science (6th Edition)
Physics for Scientists and Engineers with Modern Physics
Essential University Physics: Volume 1 (3rd Edition)
Lecture- Tutorials for Introductory Astronomy
College Physics: A Strategic Approach (4th Edition)
- An ac source of voltage amplitude 10 V delivers electric energy at a rate of 0.80 W when its current output is 2.5 A. What is the phase angle between the emf and the current?arrow_forwardFor an RLC series circuit, the voltage amplitude and frequency of the source are 100 V and 500 Hz, respectively; R=500 ; and L = 0.20H . Find the average power dissipated in the resistor for the following values for the capacitance: (a) C=2.0F and (b) C=2.0F .arrow_forwardIn the AC circuit shown in Figure P32.3, R = 70.0 and the output voltage of the AC source is Vmax sin t. (a) If VR = 0.250 Vmax for the first time at t = 0.0100 s, what is the angular frequency of the source? (b) What is the next value of t for which VR = 0.250 Vmax? Figure P32.6 Problem 3 and 5.arrow_forward
- A series RLC circuit has resistance R = 50.0 and inductance L. = 0.500 H. (a) Find the circuits capacitance C if the voltage source operates at a frequency of f = 60.0 Hz and the impedance is Z = R = 50.0 . (b) What is the phase angle between the current and the voltage?arrow_forwardIn a purely inductive AC circuit as shown in Figure P21.15, Vmax = 100. V. (a) The maximum current is 7.50 A at 50.0 Hz. Calculate the inductance L. (b) At what angular frequency is the maximum current 2.50A? Figure p21.15arrow_forwardAt 1000 Hz, the reactance of a 5.0-mH inductor is equal to the reactance of a particular capacitor. What is the capacitance of the capacitor?arrow_forward
- A 20-mH inductor is connected across an AC source with a variable frequency and a constant-voltage amplitude of 9.0 V. (a) Determine the reactance of the circuit and the maximum current through the inductor when the frequency Is set at 20 kHz. (b) Do the same calculations for a frequency of 60 Hz.arrow_forwardA 1.5k resistor and 30-mH inductor are connected in series, as below, across a120-V(rms)ac power source oscillating at 60-Hz frequency. (a) Find the current in the circuit. (b) Find the voltage drops across the resistor and inductor. (C) Find the impedance of the circuit. (d) Find the power dissipated in the resistor. (e) Find the power dissipated in the inductor. (1) Find the power produced by the source.arrow_forwardAn PLC series circuit with R=600 , L = 30 mH. and c=0.050F is driven by an ac source whose frequency and voltage amplitude are 500 Hz and 50 V, respectively, (a) What is the impedance of the circuit? (b) What is the amplitude of the current in the circuit? (c) What is the phase angle between the emf of the source and the current?arrow_forward
- Calculate the rms currents for an ac source is given by v(t)=v0sint , where V0=100V and =200rad/s when connected across (a) a 20F capacitor, (b) a 20-mH inductor, and (c) a 50 resistor.arrow_forwardA 700-pF capacitor is connected across an ac source with a voltage amplitude of 160 V and a frequency of 20 kHz. (a) Determine the capacitive reactance of the capacitor and the amplitude of the output current of the source. (b) If the frequency is changed to 60 Hz while keeping the voltage amplitude at 160 V, what are the capacitive reactance and the current amplitude?arrow_forwardIn an RLC series circuit, the voltage amplitude and frequency of the source are 100 V and 500 Hz, respectively, an R = 5O0. L=0.20H, and C=2.0F . (a)What is the impedance of the circuit? (b) What is the amplitude of the current from the source? (C) If the emf of the source Is given by v(tt)=(100V)sin , how does the current vary with time? (d) Repeat the calculations with C changed to 0.20F .arrow_forward
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning