For the battery of bulbs (purely resistive) appearing in Fig. 20.48 :
a. Determine the total power dissipation.
b. Calculate the total reactive and apparent power.
c. Find the source current Is.
d. Calculate the resistance of each bulb for the specified operating conditions.
e. Determine the currents I1 and I2.
(a)
The total power dissipation.
Answer to Problem 1P
The total power dissipated is
Explanation of Solution
Calculation:
The given circuit diagram is shown in Figure 1.
The power dissipated in bulb 1 is
The total power dissipation is given by the sum of power dissipated in individual bulbs, that is,
Here,
Substitute
Conclusion:
Therefore, the total power dissipated is
(b)
The total reactive and apparent power.
Answer to Problem 1P
The reactive power dissipated in the bulbs is
Explanation of Solution
Calculation:
As the bulbs are purely resistive in nature therefore, the reactive power dissipated in bulb is zero that is,
The apparent power is given by,
Substitute
Conclusion:
Therefore, the reactive power dissipated in bulb is
(c)
The source current
Answer to Problem 1P
The source current
Explanation of Solution
Calculation:
The source voltage
The apparent power is given by,
Substitute
Conclusion:
Therefore, the source current
(d)
The resistance of each bulb.
Answer to Problem 1P
The resistance of bulb 1 is
Explanation of Solution
Calculation:
The power dissipated in first bulb is given by,
Substitute
The voltage
Substitute
From the figure 1 it can be seen that voltage
Substitute
The power dissipated in bulb 2 is given by,
Substitute
The power dissipated in bulb 3 is given by,
Substitute
Conclusion:
Therefore, the resistance of bulb 1 is
(e)
The current
Answer to Problem 1P
The current
Explanation of Solution
Calculation:
The value of current
Substitute
The current
Substitute
Conclusion:
Therefore, the current
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