For the zero-order decomposition of HI on a gold surface HI (g) →Au1/2 H2 (g) + 1/2 I2(g)  it takes 16.0 s for the pressure of HI to drop from 1.00 atm to 0.200 atm. (a) What is the rate constant for the reaction?(b) How long will it take for the pressure to drop from 0.150 atm to 0.0432 atm?(c) What is the half-life of HI at a pressure of 0.500 atm?

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Q: in a study of the decomposition of hydrogen iodide on a gold surface at 150 °C HI(g)% H2(g) +½ I½(g)…

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Q: At 330.OC, the rate constant for the second order decomposition of NO2 is 0.775M-1s-1 if the initial…

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Q: The reaction rate (k) for a zeroth order decomposition reaction is 0.050. If the initial…

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Q: What is the rate law for the reaction A → B if the rate constant, k, is 0.25 M-1 s-1 at 75°C?

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A: The details solution for this is provided below in attach image.

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