You may need to use the appropriate appendix table or technology to answer this question. Given are five observations for two variables, x and y. (Round your answers to two decimal places.) Y₁ (a) Use Sp-V 2. -xj² to estimate the standard deviation of 9 when x 5 (b) Use 9/2³ to develop a 95% confidence interval for the expected value of y when x = 5. (c) Use Spred 5√¹+ (x-x) to estimate the standard deviation of an individual value of y when x = 5. (d) Use ±₁/2³ pred to develop a 95% prediction interval for y when x = 5. to
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- The Cadet is a popular model of sport utility vehicle, known for its relatively high resale value. The bivariate data given below were taken from a sample of fifteen Cadets, each bought "new" two years ago and each sold "used" within the past month. For each Cadet in the sample, we have listed both the mileage, x (in thousands), that the Cadet had on its odometer at the time it was sold used, and the price, y (in thousands of dollars), at which the Cadet was sold used. These data are shown graphically in the scatter plot in Figure 1. Mileage, x(in thousands) Used selling price, y(in thousands of dollars) 21.1 31.2 34.2 25.8 23.3 34.1 37.5 22.8 29.1 27.1 24.2 29.7 23.7 28.0 27.7 25.1 24.1 27.6 23.2 30.9 26.7 31.7 28.1 30.0 20.9 31.6 15.2 34.6 25.7 26.6 The least-squares regression line for these data has a slope of approximately −0.5. Answer the following. Carry your intermediate computations to at least four decimal places, and round your answers as…The Cadet is a popular model of sport utility vehicle, known for its relatively high resale value. The bivariate data given below were taken from a sample of sixteen Cadets, each bought "new" two years ago and each sold "used" within the past month. For each Cadet in the sample, we have listed both the mileage, x (in thousands), that the Cadet had on its odometer at the time it was sold used, and the price, y (in thousands of dollars), at which the Cadet was sold used. These data are shown graphically in the scatter plot in Figure 1. Also given is the product of the mileage and the used selling price for each of the sixteen Cadets. (These products, written in the column labelled "xy", may aid in calculations.) Mileage, x (in thousands) 20.8 23.3 29.6 38.8 34.4 24.0 23.7 26.0 28.0 15.2 26.7 22.8 21.0 27.9 37.8 24.4 Used selling price, y (in thousands of dollars) 31.8 33.1 28.3 21.3 26.0 27.8 27.2 27.9 29.9 33.6 31.6 31.9 31.2 25.9 23.7 30.1 Send data to calculator xy 661.44 771.23…The Cadet is a popular model of sport utility vehicle, known for its relatively high resale value. The bivariate data given below were taken from a sample of sixteen Cadets, each bought "new" two years ago and each sold "used" within the past month. For each Cadet in the sample, we have listed both the mileage, x (in thousands), that the Cadet had on its odometer at the time it was sold used, and the price, y (in thousands of dollars), at which the Cadet was sold used. These data are shown graphically in the scatter plot in Figure 1. Also given is the product of the mileage and the used selling price for each of the sixteen Cadets. (These products, written in the column labelled "xy", may aid in calculations.)
- A manufacturer of a new medication on the market for Parkinson's disease makes a claim that the medication is effective in 75% of people who have the disease. One hundred fifty individuals with Parkinson's disease are given the medication, and 100 of them note the medication was effective. Does this finding provide statistical evidence at the 0.05 level that the effectiveness is less than the 75% claim the company made? Make sure to include parameter, conditions, calculations, and a conclusion in your answer.In simple linear regression, at what value of the independent variable, X, will the 95% confidence interval for the average value of Y be narrowest? At what value will the 95% prediction interval for the value of Y for a sin gle new observation be narrowest?A statistics teacher taught a large introductory statistics class, with 500 students having enrolled over many years. The mean score over all those students on the first midterm was u = 88 with standard deviation o = 10. One year, the teacher taught a %3D much smaller class of only 25 students. The teacher wanted to know if teaching a smaller class was more effective and students performed better. We can consider the small class as an SRS of the students who took the large class over the years. The average midterm score was = 78. The hypothesis should be: a. Ho: H = 78 vs. Ha: H = 88. %3D O b. Ho: µ = 88 vs. Ha: µ 78 %3D Ο d. Ho: μ-88 νs. Ha: μ >88. %3D
- The World Health Organization keeps a record of many statistics thought to be social, economic and political indicators. One of these is the number of physicians practicing in that particular country. You are given the data from 2017 and 1990. Is there evidence to support the fact that the number of physicians is increasing over time? Please state your hypotheses and assumptions. You must validate your assumptions and then use an appropriate test. Use α =0.05You are performing a right-tailed matched-pairs test with 9 pairs of data.If α=.005α=.005, find the critical value, to two decimal places.Asset W has expected return of 11.6% and a beta of 1.23. If the risk free rate is 3.15%, complete the following table for portfolios of asset W, and a risk free asset. Illustrate the relationship between portfolio, expected return and portfolio beta by plotting the expected returns against the betas in a graph. What is the slope of the line that results? Results are in the table I just need the excel graph!!!! Percentage of portfolio asset in W. Portfolio expected return. Portfolio beta. 0% = (0 x 0.116) + (1 x 0.0315) = 3.15% 0 25% = (0.25 x 0.116) + (0.75 x 0.0315) = 5.26% = 1.23 x 0.25 = 0.3075 50% = (0.50 x 0.116) + (0.50 x 0.0315) = 7.37% = 1.23 x 0.50 = 0.615 75% = (0.75 x 0.116) + (0.25 x 0.0315) = 9.48% = 1.23 x 0.75 = 0.9225 100% = (1 x 0.116) + (0 x 0.0315) = 11.6% = 1.23 x 1 = 1.23 125% = (1.25 x 0.116) + (-0.25 x 0.0315) = 13.71% = 1.23 x 1.25 = 1.5375 150% = (1.50 x 0.116) + (-0.50 x 0.0315) = 15.82% = 1.23 x…
- The table below lists measured amounts of redshift and the distances (billions of light-years) to randomly selected astronomical objects. Find the (a) explained variation, (b) unexplained variation, and (c) indicated prediction interval. There is sufficient evidence to support a claim of a linear correlation, so it is reasonable to use he regression equation when making predictions. For the prediction interval, use a 90% confidence level with a redshift of 0.0126. Redshift 0.0233 0.0543 0.0716 0.0396 0.0436 0.0107 Distance 0.34 0.74 0.99 0.56 0.62 0.12 a. Find the explained variation. Round to six decimal places as needed.)The data from a simple random sample with 25 observations was used to construct the plots given below. The normal probability plot that was constructed has a correlation coefficient of 0.947. Judge whether a t-interval could be constructed using the data in the sample. Click here to view the normal probabilty plot and the boxplot Click here to view the table of critical values of the correlation coefficient. The normal probability plot does not suggest the data could come from a normal population because 0.947 and the boxplot shows outliers, so a t-interval could not be constructed. (Round to three decimal places as needed.)The table below lists measured amounts of redshift and the distances (billions of light-years) to randomly selected astronomical objects. Find the (a) explained variation, (b) unexplained variation, and (c) indicated prediction interval. There is sufficient evidence to support a claim of a linear correlation, so it is reasonable to use the regression equation when making predictions. For the prediction interval, use a 90% confidence level with a redshift of 0.0126. D Redshift Distance 0.0237 0.32 0.0545 0.75 0.0724 1.02 0.0397 0.56 0.0442 0.61 0.0103 0.16 a. Find the explained variation. (Round to six decimal places as needed.) b. Find the unexplained variation. (Round to six decimal places as needed.) c. Find the indicated prediction interval. billion light-yearsSEE MORE QUESTIONS