y 30 kPael. 30 malcoholFrom the figure shown,the alcoholsurface is subjected topressureaCompute the pressurep = 774 m3of30kPa.atthe elevations given below:1. 6 m2. 12 mel.16 moll3.3 mp = 890el.8 mwaterel.5 mglycerink9/mp = 1235el. 0 m

Answered: Image /qna-images/answer/7d91024e-9398-45ea-abee-2d348e1ffa44.jpg

y 30 kPa el.30 m alcohol From the figure shown, the alcohol surface is subjected to of 30 kPa. Compute the pressure at the elevations given below: 1. 6 m a pressure p = 774 m3 el.16 m 2.12 m oll p= 890 m³ 3.3 m el.8 m water el.5 m glycerin p= 1235 el. 0 m

y 30 kPa el.30 m alcohol From the figure shown, the alcohol surface is subjected to of 30 kPa. Compute the pressure at the elevations given below: 1. 6 m a pressure p = 774 m3 el.16 m 2.12 m oll p= 890 m³ 3.3 m el.8 m water el.5 m glycerin p= 1235 el. 0 m

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter10: Oxidation, Degradation, Corrosion, Electroprocessing, Batteries, And Fuel Cells

Section: Chapter Questions

Problem 10.1P

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Question

y 30 kPa
el. 30 m
alcohol
From the figure shown,
the alcohol
surface is subjected to
pressure
a
Compute the pressure
p = 774 m3
of
30
kPa.
at
the elevations given below:
1. 6 m
2. 12 m
el.16 m
oll
3.3 m
p = 890
el.8 m
water
el.5 m
glycerin
k9/m
p = 1235
el. 0 m

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