Write code so that you make another image below the image currently in the code so that they are next to each other but not touching each other. And Translate - A function that moves the graphic according to the given input . Grow - a function that increases the size of the graphic according to the given input public class BasicGraphicViewer {
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Write code so that you make another image below the image currently in the code so that they are next to each other but not touching each other. And Translate - A function that moves the graphic according to the given input . Grow - a function that increases the size of the graphic according to the given input
public class BasicGraphicViewer
{
public static void main (String[] args)
{
Rectangle r1 = new Rectangle(100,10,20,30);
r1.draw();
Picture p1 = new Picture();
p1.load(“someimageurl”); // you can put any image link here.
p1.draw();
}
}
Step by step
Solved in 2 steps
- Transcribed Image Text Python Development Lab In Merworld there exists 2 coins of different denominations types 5-peso coins and 10- peso coins, both having two faces with image of – Elon Musk and a dog. You are assigned a task to find out the number of ways to arrange these coins so that their sum is N pesos. Arrangement should be done in such a way that the first coin in the arrangement should always have Elon Musk image up. Other coins could have any image. Input Output 1 60 5 LODouble any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner (System.in); final int NUM_POINTS = 4; int [] dataPoints new int [NUM_POINTS]; int controlValue; int i; controlValue = scnr. nextInt (); for (i = 0; i < dataPoints.length; ++i) { = scnr.nextInt (); dataPoints [i] } /* Your solution goes here * / for (i = 0; i < dataPoints.length; ++i) { System.out.print (dataPoints[i] + %3D " ") ; } System.out.println ();#this is a python programtopic: operation overloading, Encapsulation please find the attached image
- 1. Given a string of at least 3 characters as input, if the length of the string is odd return the character in the middle as a string. If the string is even return the two characters at the midpoint. public class Class1 { public static String midString(String str) { //Enter code here } } ----------- 2. Given an array of integers return the sum of the values stored in the first and last index of the array. The array will have at least 2 elements in it public class Class1 { public static int endSum(int[] values) { //Enter code here } } ----------- 3. The method takes a string as a parameter. The method prints treat if the string is candy or chocolate (of any case, such as CaNdY) Otherwise print trick import java.util.Scanner; public class Class1 { public static void trickOrTreat(String str) { //Enter code here } public static void main(String[] args) { Scanner s = new Scanner(System.in); trickOrTreat(s.nextLine()); } }Java Program - Functions with 2D Arrays Write a function named displayElements that takes a two-dimensional array, the size of its rows and columns, then prints every element of a two-dimensional array. Separate every row by a new line and every column by a space. In the main function, write a program that asks for integer input to be assigned on a 3 x 3 array and call the function displayElements to print the contents on the next line. Input 1. Multiple lines containing integer each line Output R1C1: 1 R1C2: 2 R1C3: 3 R2C1: 4 R2C2: 5 R2C3: 6 R3C1: 7 R3C2: 8 R3C3: 9 1 2 3 4 5 6 7 8 92. drawShape(Turtle, sides, length): Draws the polygon based on the user input of # of sides and lenght of the side.
- There may be extra spaces or formatting characters at the start or end of a string when interacting with a string object. Spaces and other characters can be taken out of either end of a string using the Trim and TrimEnd methods. You can provide a character or an array of characters to cut. If you give an array of characters, the string will be cut if any of the characters are found in the array.To remove spaces from the start and end of a group of string values, write a C# programme:Palindromes - “A palindrome” is a string that reads the same from both directions. For example: the word "mom" is a palindrome. Also, the string "Murder for a jar of red rum" is a palindrome. - So, you need to implement a Boolean function that takes as input a string and its return is true (1) in case the string is a palindrome and false (0) otherwise. - There are many ways to detect if a phrase is a palindrome. The method that you will implement in this task is by using two stacks. This works as follows. Push the left half of the characters to one stack (from left to right) and push the second half of the characters (from right to left) to another stack. Pop from both stacks and return false if at any time the two popped characters are different. Otherwise, you return true after comparing all the elements. Phrases of odd length have to be treated by skipping the middle element like the word "mom", your halves are "m" and "m". - Hint: (without using STL)please code in python You place a pawn at the top left corner of an n-by-n chess board, labeled (0,0). For each move, you have a choice: move the pawn down a single space, or move the pawn down one space and right one space. That is, if the pawn is at position (i,j), you can move the pawn to (i+1,j) or (i+1, j+1). Ask the user for the size of a chessboard, n (integer). Find the number of different paths starting from (0,0) that the pawn could take to reach each position on the chess board. For example, there are two different paths the pawn can take to reach (2,1). Look at the diagrams below to convince yourself of this. You can see the four paths that you can take by move 2. Start -> Move 1 -> Move 2 (0,0) -> (1,0) -> (2,1) (0,0) -> (1,0) -> (2,0) (0,0) -> (1,1) -> (2,1) (0,0) -> (1,1) -> (2,2) Print the board with the number of ways to reach each square labeled as shown below. For example: Enter a board size: 4 1 0 0 0 1 1 0 0 1 2 1 0 1 3 3 1
- Practice / Frequency of Characters Write a method that returns the frequency of each characters of a given String parameter. If the given String is null, then return null If the given String is empty return an empty map Example input: output: empty map explanation: input is empty Example input: null output: null explanation: input is null. Since problem output is focused on the frequency we can comfortably use Map data structure. Because we can use characters as key and the occurrences of them as value. Example input: responsible output: {r=1, e=2, s=2, p=1, o=1, n=1, i=1, b=1, l=1} explanation: characters are keys and oc values ences areThe Huntington High School basketball team has five players named Art, Bob, Cal, Dan, and Eli. Accept the number of points scored by each player in a game and create a bar chart that illustrates the points scored by displaying an asterisk for each point. The output looks similar to the chart in Figure 6-34. import java.util.Scanner; public class BarChart { public static void main (String[] args) { Scanner input = new Scanner(System.in); int artPoints; int bobPoints; int calPoints; int danPoints; int eliPoints; System.out.print("Enter points earned by Art >> "); artPoints = input.nextInt(); System.out.print("Enter points earned by Bob >> "); bobPoints = input.nextInt(); System.out.print("Enter points earned by Cal >> "); calPoints = input.nextInt(); System.out.print("Enter points earned by Dan >> "); danPoints = input.nextInt();…Assuming that you have the functions "drawPolygon(int[] x, int[] y, int n)" for drawing polygon, "drawRectangle(int x, int y, int width, int height)" for drawing rectangle and "drawCircle(int xc, intyc, int radius)" for drawing circle; draw the given shape. Where: R(300,250), T1(325,275), T2(475,275), T3(400,400), Pı(285.250), P2(225.275), P3(200,450), P4(285, 300), Q1(515,250), Q2(575,275), Q3(600,450), Q4(515,300) C6: (300,75), R=50 C7: (500,75), R=50 C1: (400,150), R=100 С4: (350,150), R-10 C5: (450,150), R=10 C2: (400,195), R=50 C3: (400,175), R=30 C8: (400,225), R=15 P1 R P2, T2 P4 Q2 Q4 T3 Pa 200