Write a function that will calculate the sum of all the numbers multiple of 3 from N down to 1 using recursion. HINT: SAMPLE ALGORITHM int computeTotal(int n) { /1. declare a variable sum and initialize it to 0 to add all nos that are multiple l/of 3 1/2. test if n is equal to 0 I/ if true return n 1/3. else { //tests if n is divisible by 3 //if true test if(sum==0) sum=n; return sum+= computeTotal(n-1);
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- (Numerical) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters to 0, and then generate a large number of pseudorandom integers between 0 and 9. Each time a 0 occurs, increment the variable you have designated as the zero counter; when a 1 occurs, increment the counter variable that’s keeping count of the 1s that occur; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of the time they occurred.Write a function that takes in an integer n and computes n!. Do this without recursion. In [ ]: deffactorial_iter(n):"""Takes in an integer n>0 and returns the product of all integers from 1 to n."""# YOUR CODE HEREraiseNotImplementedError() In [ ]: In [ ]: assert factorial_iter(6) == 720 assert factorial_iter(7) == 5040 assert factorial_iter(10) == 3628800Given a string str and number n, write a program that recursively appends a copy of string str n times and returns the resulting string. For example: RecuriveCopy("a", 10) // -> "aaaaaaaaaaa" RecursiveCopy("blah", 5) // -> "blahblahblahblahblahblah" For this exercise, complete the following function. n is the number of copies to add to str: function RecursiveCopy(str, n) { // your code here } Part 2: Call RecursiveCopy Write another function that calls RecursiveCopy() and returns the following string output: "The resulting string [x] has [y] characters". [x] should be replaced by the result from RecursiveCopy) and [y] should be replaced by the number of characters in the resulting string. You may pick the arguments to RecursiveCopy in CountChars or have the user provide input. I will leave this up to you. function CountChars() { } // your code here // call RecursiveCopy(..) // returns a formatted string For example: console.log(CountChars()) // -> "The resulting string blahblahblahblah…
- CodeW X b For func x C Solved X b Answer X https://codeworkou... CodeWorkout X270: Recursion Programming Exercise: Count Characters For function countChr() write the missing part of the recursive call. This function should return the number of times that the letter "A" appears in string "str". Recall that str.substring(a) will return the substring of str from position a to the end of str, while str.substring (a, b) will return the substring of str starting at position a and continuing to (but not including) the character at position b. Examples: countChr ("ctcoWCAt") -> 1 Your AnsSwer: 1 public int countChr(String str) { 2. if (str.length() return 0; } (0 4. { int count = 0; www. 5. 9. if (str.substring(0, 1).equals("A")) { count = 1 7. { 9. return count + > 1:10 AM 50°F Clear 12/4/2021 呼CodeW X bFor fun X C Solved x b Answer + x https://codeworko... CodeWorkout X265: Recursion Programmlng Exercise: GCD The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD , write the missing base case condition and action. This function will compute the greatest common divisor of x and y.You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows: = x and GCD(x, y) = GCD(y, x % y). Examples: GCD (6, 4) -> 2 Your An swer: 1 public int GCD(int x, int y) { if > { 2. > 3. } else { 4. return GCD(y, x % y); 9. { 7. 1:09 AM 50°F Clear 1V 1. 12/4/2021 甲Write the definition of a recursive function int simpleSqrt(int n) The function returns the integer square root of n, meaning the biggest integer whose square is less than or equal to n. You may assume that the function is always called with a nonnegative value for n. Use the following algorithm: If n is 0 then return 0. Otherwise, call the function recursively with n-1 as the argument to get a number t. Check whether or not t+1 squared is strictly greater than n. Based on that test, return the correct result. For example, a call to simpleSqrt(8) would recursively call simpleSqrt(7) and get back 2 as the answer. Then we would square (2+1) = 3 to get 9. Since 9 is bigger than 8, we know that 3 is too big, so return 2 in this case. On the other hand a call to simpleSqrt(9) would recursively call simpleSqrt(8) and get back 2 as the answer. Again we would square (2+1) = 3 to get back 9. So 3 is the correct return value in this case.
- CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021Fibonacci numbers are a sequence of integers, starting with 1, where the value of each number is the sum of the two previous numbers, e.g. 1, 1, 2, 3, 5, 8, etc. Write a function called fibonacci that takes a parameter, n, which contains an integer value, and have it return the nth Fibonacci number. (There are two ways to do this: one with recursion, and one without.)4. CodeW. X b For fun X Solved x b Answer x+ Ohttps://codeworko... CodeWorkout X264: Recursion Programming Exercise: Multiply For function multiply,write the missing base case condition and action. This function will multiply two numbers x and y.You can assume that both x and y are positive. Examples: multiply(2, 3) -> 6 Your Answer: 1 public int multiply(int x, int y) { 2. if > { > } else { return multiply(x 1, y) + y; 3. 5. { 7. 1:08 AM 50°F Clear 日
- Recursive Copy Function Given a string str and number n, write a program that recursively appends a copy of string str n times and returns the resulting string. Please complete the following function. n is the number of copies to add to str: function RecursiveCopy(str, n) {// your code here} The problem must satisfy the following: You must use recursion. You should end up with n+1 copies of the str total in the output because you are appending additional str copies. Use string literal formatting for the output.The following function f uses recursion:def f(n):if n <= 1return nelse return f(n-1) + f(n-2)Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion?a) def f(n):a <- 0b <- 1 if n = 0return aelsif n = 1 return belsefor i in 1..nc <- a + b a <- b b <- c return bb) def f(n):a <- 0i <- n while i > 0 a <- a + i + (i-1) return ac) def f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1return arr[n]elsefor i in 2..n arr[i] <- arr[i-1] + arr[i-2]return arr[n]d) def f(n): arr[0..n] <- [0, ..., n] if n <= 1return arr[n]elsea <- 0 for i in 0..n a <- a + arr[i]return aplease code in python Write a recursive function to add a positive integer b to another number a, add(a, b), where only the unit 1 can be added, For example add(5, 9) will return 14. The pseudocode is: # Base case: if b is 1, you can just return a + 1 # General case: otherwise, return the sum of 1 and what is returned by adding a and b - 1.