What is the value of reverse recovery charge dev which is having the rate of fall of diode current 3 equal to 5.6 us. O a. 1088.19 µC O b. 971.60 µC O c. 313.60 µC O d. 544.10 µC
What is the value of reverse recovery charge dev which is having the rate of fall of diode current 3 equal to 5.6 us. O a. 1088.19 µC O b. 971.60 µC O c. 313.60 µC O d. 544.10 µC
Chapter59: Motor Startup And Troubleshooting Basics
Section: Chapter Questions
Problem 12SQ: How is a solid-state diode tested? Explain.
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![What is the value of reverse recovery charge developed in diode
which is having the rate of fall of diode current 34.7 A/us and t, is
equal to 5.6 ps.
O a. 1088.19 µC
O b. 971.60 µC
O c. 313.60 µC
O d. 544.10 µC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F55bf8002-9013-4482-b44e-46d0ce6cbe62%2F063ec440-21c8-4f75-a424-c13927f66027%2Fpmyt71g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What is the value of reverse recovery charge developed in diode
which is having the rate of fall of diode current 34.7 A/us and t, is
equal to 5.6 ps.
O a. 1088.19 µC
O b. 971.60 µC
O c. 313.60 µC
O d. 544.10 µC
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