What are the main limiting factors to battery improvements?
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What are the main limiting factors to battery improvements?
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- For the full wave rectifier circuit shown in Figure 1, calculate: 1) The maximum current through the load. 2) The average current through the load. 3) The average voltage across the load. 4) The rms value of the current. 5) The rectification efficiency. Vms = 280V Vin RL= 12ks2 Vrms = 280V Figure 1Given the zener voltage at 9V and the zener power at 1W, what is the range of allowable values of Iz (operating values). a) 0.11A b) 22mA to 89mA c) 9A d) 0.11A to 9APt A 6v battery, delivrers lomA to three resistors in paralkel, R, 21kr, R2=2K2,R3%3DRX. Calculate: a) Current in b) Power dissipatid by Rx and R,-[Anss 6mw,36mm. C) Resistance ratio Rx/R--(Ans: 615). ) Cnrrent ratio It/Ix Ans: 6/]. Rx sthat is In-[Anss I mA)-
- Which of the following statements about bridge tip rectifiers is false? A) If the 1-phase type has source inductance, the average value of the output voltage is lower than in the absence of the inductance. B) The average output voltage value of the 1-phase type is 0.9 times the peak voltage of the network. C) none D) There are only odd harmonics in the current drawn by the 1-phase type from the mains. E) The average value of the output voltage of the 3-phase type is larger as the 3-phase and 1-phase types are compared3-3 rectification? A d'Arsonval meter movement with a full-scale deflection current rating of 1 mA and an internal resistance of 500 2 is to be used in a half-wave rectifier ac voltmeter. Calculate the ac and dc sensitivity and the value of the multiplier resistor for a 30-V rms range.vcC R1 RC 68K 1.2K C2 HH Vịn C1 Q1 100µ 2N5089 100p vs C3 RL RE R2 13K SINE(0 10m 1k) 100p 750 16k
- 2. In the previous diagram for an LED circuit, the power supply is a 9V battery and we are using a Red LED whose voltage drop is 2V. The specification sheet for the LED recommends that the "ON" current should be 10 milliamps. a. What series resistor will give the specified LED current? 7737-1 C. b. What is the power dissipated by the resistor you selected in part a? A 70 2 What is the power dissipated in the LED?Ex. 94. See Figure 94. Challenging exercise? Given a 8.00 kOhm potentiometer, V_AC=100.0 volts, V_BC= 10.0 volts and load current is 3.000 mAmps. Determine R_AB Ohms, R_BC Ohms, and power (watts) dissipated by the potentiometer. ans:3Which change to the circuit will not extend the charging time of one time constant.a. Increasing the value of the capacitorb. Increasing the value of the resistorc. Increasing the voltage from 15 to 20 volts
- a) Explain the operation of the controlled full-wave bridge rectifier shown in figure 3. b) The controlled full-wave bridge rectifier shown in figure 3 has a source 120 V rms at 60 Hz, R = 1092, L=20 mH, and a = 60°. Determine: i. An expression for the load current. ii. The average load current. iii. The power absorbed by the load. iv. Sketch the graph of the output waveform. Vs S₁ S4 Figure $3 $₂ Lo VoIs Bridge Full Wave Rectifier only working with Transformers or can we use it with AC source as well? If you are agree with this then provide any advantage of this rectifier circuit without using the transformers OR if you are disagree then provide justification of your answer.A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%