C Get Homework Help With Chegg XC What Are The Expected Readings XA HW-CH27 - (Spring_2021_PHYS1 XO em SA Al-Marri - Outlook - I Xb My Questions | bartleby+i webassign.net/web/Student/Assignment-Responses/submit?dep=26379090&tags=autosave#question4268373_5What are the expected readings of the following in the figure below? (R = 5.60 N, AV = 6.30 V)ARAV10.0 N+V5.00 N+R4.50 V(a) ideal ammeter (Give your answer in mA.)105(b)ideal voltmeter (Give your answer in volts.)1.8V(c)What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was tothe right?ideal ammeter580ideal voltmeter-3.25X VNeed Help?Read ItMaster ItHW pic5.jpgHW pic4.jpgShow all7:59 PMO Type here to search^ E O ENG3/13/20214

Given: The resistance R=5.6 Ω The voltage ∆V=6.3 volt

What are the expected readings of the following in the figure below? (R = 5.60 N, AV = 6.30 V) R AV 10.0 N V 5.00 N R 4.50 V (a) ideal ammeter (Give your answer in mA.) 105 x mA (b) ideal voltmeter (Give your answer in volts.) 1.8 V (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter 580 X mA ideal voltmeter -3.25 x V Need Help? Read It Master It

What are the expected readings of the following in the figure below? (R = 5.60 N, AV = 6.30 V) R AV 10.0 N V 5.00 N R 4.50 V (a) ideal ammeter (Give your answer in mA.) 105 x mA (b) ideal voltmeter (Give your answer in volts.) 1.8 V (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter 580 X mA ideal voltmeter -3.25 x V Need Help? Read It Master It

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter1: Getting Started

Section: Chapter Questions

Problem 39PQ

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The first atomic bomb was detonated on July 16, 1945, at the Trinity test site about 200 mi south of Los Alamos. In 1947, the U.S. government declassified a film reel of the explosion. From this film reel, British physicist G.I. Taylor was able to determine the rate at which the radius of the fireball from the blast grew. Using dimensional analysis, he was then able to deduce the amount of energy released in the explosion, which was a closely guarded secret at the time. Because of this, Taylor did not publish his results until 1950. This problem challenges you to recreate this famous calculation. (a) Using keen physical insight developed from years of experience, Taylor decided the radius rof the fireball should depend only on time since the explosion, t, the density of the air, , and the energy of the initial explosion, E. Thus, he made the educated guess that r=kEabtcfor some dimensionless constant kand some unknown exponents a,b, and c. Given that [E]=ML2T-2 , determine the values of the exponents necessary to make this equation dimensionally consistent. (Hint: Notice the equation implies that k=rEabtcand that [k]=1 ). (b) By analyzing data from high-energy conventional explosives, Taylor found the formula he derived seemed to be valid as long as the constant khad the value 1.03. From the film reel, he was able to determine many values of rand the corresponding values of t. For example, he found that after 25.0 ms, the fireball had a radius of 130.0 m. Use these values, along with an average air density of 1.25kg/m3 , to calculate the initial energy release of the Trinity detonation in joules (J). (Hint: To get energy in joules, you need to make sure all the numbers you substitute in are expressed in terms of SI base units.) (c) The energy released in large explosions is often cited in units of “tons of TNT” (abbreviated “t TNT”), where 1 t TNT is about 4.2 GJ. Convert yow answer to (b) into kilotons of TNT (that is, kt TNT). Compare your answer with the quick-and-duty estimate of 10 kt TNT made by physicist Enrico Fermi shortly after witnessing the explosion from what was thought to be a safe distance. (Reportedly, Fermi made his estimate by dropping some shredded bits of paper right before the remnants of the shock wave hit him and looked to see how far they were carried by it.)
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