VER AS REQUIRED A. DESCRIBE THE PREPARATION OF THE FOLLOWING SOLUTIONS. Show all pertinent calculations:, 1. 2. 50 ml of 0.5 N NaOH 50 ml of 0.5 N HCI from 37% by wt HCI (D = 1.19 g/ mL) B. DETERMINE CONCENTRATION RATIO. Show all pertinent calculations. Final Rdg HCI, mL 26.5 29.2 Initial Rdg HCI, mL 0.9 0.5 Final Rdg NAOH, mL 20.3 24.4 Initial Rdg NaOH, mL 0.8 0.3 1 ml HCI mL NaOH mL NaOH 1 mL NaOH mL HCI Mean Values: 1 mL HCI = mL HCI mL NaOH 1 ml NaOH = ml HCI

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.102QE
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ANSWER AS REQUIRED:
A. DESCRIBE THE PREPARATION OF THE FOLLOWING SOLUTIONS. Show all pertinent
calculations:
1.
50 ml of 0.5 N NaOH
2.
50 ml of 0.5 N HCI from 37% by wt HCI (D = 1.19 g/ mL)
B. DETERMINE CcONCENTRATION RATIO. Show all pertinent calculations.
Final Rdg HCI, mL
26.5
29.2
Initial Rdg HCI, mL
0.9
0.5
Final Rdg NAOH, mL
20.3
24.4
Initial Rdg NaOH, mL
0.8
0.3
1 ml HCI
mL NaOH
mL NaOH
1 mL NAOH
mL HCI
Mean Values: 1 mL HCI =
mL HCI
mL NaOH
mL NaOH =
ml HCI
Transcribed Image Text:ANSWER AS REQUIRED: A. DESCRIBE THE PREPARATION OF THE FOLLOWING SOLUTIONS. Show all pertinent calculations: 1. 50 ml of 0.5 N NaOH 2. 50 ml of 0.5 N HCI from 37% by wt HCI (D = 1.19 g/ mL) B. DETERMINE CcONCENTRATION RATIO. Show all pertinent calculations. Final Rdg HCI, mL 26.5 29.2 Initial Rdg HCI, mL 0.9 0.5 Final Rdg NAOH, mL 20.3 24.4 Initial Rdg NaOH, mL 0.8 0.3 1 ml HCI mL NaOH mL NaOH 1 mL NAOH mL HCI Mean Values: 1 mL HCI = mL HCI mL NaOH mL NaOH = ml HCI
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