Using the below enthalpy of formation values, determine the enthalpy for dissolution (dissolving) of ammonium nitrate in water: NH4NO3(s) → NH4NO3(aq) NH4NO3 (aq) AH = -339.9 kJ/mol NH4NO3 (s) AH = -365.6 kJ/mol O 705.5 kJ O -705.5 kJ 25.7 kJ O -25.7 kJ O 64.1 kJ

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 69E: Using the data in Appendix G, calculate the standard enthalpy change for each of the following...
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Using the below enthalpy of formation values, determine the enthalpy for dissolution
(dissolving) of ammonium nitrate in water:
NH4NO3(s) →NH4NO3 (aq)
NH4NO3 (aq) AH = -339.9 kJ/mol
NH4NO3 (s) AH = -365.6 kJ/mol
O 705.5 kJ
O -705.5 kJ
25.7 kJ
-25.7 kJ
O 64.1 kJ
Transcribed Image Text:Using the below enthalpy of formation values, determine the enthalpy for dissolution (dissolving) of ammonium nitrate in water: NH4NO3(s) →NH4NO3 (aq) NH4NO3 (aq) AH = -339.9 kJ/mol NH4NO3 (s) AH = -365.6 kJ/mol O 705.5 kJ O -705.5 kJ 25.7 kJ -25.7 kJ O 64.1 kJ
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