Use the graph you drew for NH4Cl to determine the amount of salt needed to make a chemical cold pack. Assume using 100 g (100 mL) of water. The temperature should go down to 3.0 °C from a room temperature of 25 °C. Show all calculations. for the slope from graph: y=0.4327x-10.859

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Section13.7: Colligative Properties Of Solutions
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Use the graph you drew for NH4Cl to determine the amount of salt needed to make a chemical cold pack. Assume using 100 g (100 mL) of water. The temperature should go down to 3.0 °C from a room temperature of 25 °C. Show all calculations.

for the slope from graph: y=0.4327x-10.859 

 

Mass of water
Mass of salt
Moles of salt
Initial
Temperature
Final
Temperature
Change in
Temperature
Heat
released/absorb
ed by water
Heat
released/absorb
ed by the
calorimeter
5g
CaCl2
100.0g
10g
CaCl2
100.0g
13°C
5.06g
10.06g 15.0g
0.045m 0.091m 0.135m
ol
ol
ol
13°C℃
20.2°C 24.9°C
15g
CaCl2
100.0g
13°C
-30.1J -49.7J
26.5°C
5g
NH4CI
100.0g
5.10g
0.09534m
ol
13°C
10.1°C
7.2°C 11.9°C 13.5°C -2.9°C
-3009.6J -4974.2J -5643.0J 1212.2J
-56.43J 12.12J
10g
NH4CI
100.0g
10.08g
0.188mol 0.281mol
13°C
7°C
-6°C
15g
NH4CI
100.0g
15.04g
25.1J
13°C
8.4°C
-4.6°C
2508J 1922.8J
19.23J
Transcribed Image Text:Mass of water Mass of salt Moles of salt Initial Temperature Final Temperature Change in Temperature Heat released/absorb ed by water Heat released/absorb ed by the calorimeter 5g CaCl2 100.0g 10g CaCl2 100.0g 13°C 5.06g 10.06g 15.0g 0.045m 0.091m 0.135m ol ol ol 13°C℃ 20.2°C 24.9°C 15g CaCl2 100.0g 13°C -30.1J -49.7J 26.5°C 5g NH4CI 100.0g 5.10g 0.09534m ol 13°C 10.1°C 7.2°C 11.9°C 13.5°C -2.9°C -3009.6J -4974.2J -5643.0J 1212.2J -56.43J 12.12J 10g NH4CI 100.0g 10.08g 0.188mol 0.281mol 13°C 7°C -6°C 15g NH4CI 100.0g 15.04g 25.1J 13°C 8.4°C -4.6°C 2508J 1922.8J 19.23J
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