Two charges of 91 = 1.9 μC and 92 = -2.5 μC are d = 0.52 m apart at two vertices of an equilateral triangle as in Figure P16.56. 91 P d d d 92 Figure P16.56 (a) What is the electric potential due to the 1.9 μC charge at the third vertex, point P? V (b) What is the electric potential due to the -2.5 μC charge at P? V (c) Find the total electric potential at P. V (d) What is the work required to move a 3.2 μC charge from infinity to point P? J Submit Answer ASK YOUR TEACHER PRACTICE ANOTHER
Two charges of 91 = 1.9 μC and 92 = -2.5 μC are d = 0.52 m apart at two vertices of an equilateral triangle as in Figure P16.56. 91 P d d d 92 Figure P16.56 (a) What is the electric potential due to the 1.9 μC charge at the third vertex, point P? V (b) What is the electric potential due to the -2.5 μC charge at P? V (c) Find the total electric potential at P. V (d) What is the work required to move a 3.2 μC charge from infinity to point P? J Submit Answer ASK YOUR TEACHER PRACTICE ANOTHER
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Transcribed Image Text:Two charges of 91
=
1.9 μC and 92
=
-2.5 μC are d = 0.52 m apart at two vertices of an equilateral triangle as in Figure P16.56.
91
P
d
d
d
92
Figure P16.56
(a) What is the electric potential due to the 1.9 μC charge at the third vertex, point P?
V
(b) What is the electric potential due to the -2.5 μC charge at P?
V
(c) Find the total electric potential at P.
V
(d) What is the work required to move a 3.2 μC charge from infinity to point P?
J
Submit Answer
ASK YOUR TEACHER
PRACTICE ANOTHER
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