This exercise calls on the data set "analgesics d". The data set contains the following variables: Gender: male or female Drug: which of three drugs was administered, A, B, or C Pain: the patient's level of pain, with a higher value representing greater pain. You first create a table showing the average level of pain for each drug/gender combination. Put "Gender" in the rows of the table and "Drug" in the Columns. After making observation on differences in the effectiveness of the three drugs based on your table, you decide to conduct a one-way ANOVA analysis to test whether the average level of pain differs by gender. Use a 5% significance level.
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- Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1048 and x = 568 who said "yes." Use a 95% confidence level. Click the icon to view a table of z scores. Standard Normal (z) Distribution a) Find the best point estimate of the population proportion p. .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 (Round to three decimal places as needed.) 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 0.0 0.1 .5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.1 0.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 0.2 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.3 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.4 0.5 .6915 .6950 .6985 7019 .7054 .7088 .7123 .7157 .7190 .7224 0.5 0.6 .7257 .7291 7324 7357 .7389 .7422 .7454 .7486 .7517 .7549 0.6 0.7 .7580 .7611 .7642 7673 7704 .7734 .7764 .7794…Date DJIA S&P 500 Day 1 35405.24 4536.54 Day 2 35629.33 4579.38 Day 3 35111.16 4467.44 Day 4 35089.74 4510.53 Day 5 35091.13 4493.87 Day 6 35462.78 4511.54 Day 7 35768.06 4577.18 Day 8 35241.59 4514.08 Day 9 34738.06 4408.64 Day 10 34566.17 4411.67 Day 11 34988.84 4461.07 Day 12 34934.27 4485.01 Day 13 34312.03 4390.26 Day 14 34079.18 4358.87 Day 15 33596.61 4314.76 Day 16 33131.76 4235.50 Day 17 33223.83 4278.70 Day 18 34058.75 4394.65 Day 19 33892.60 4363.94 Day 20 33294.95 4316.26 Day 21 33891.35 4396.54 Day 22 33794.66 4353.49 Day 23 33614.80 4318.87 Day 24 32817.38 4211.09 Day 25 32632.64 4180.70 Day 26 33286.25 4287.88 Day 27 33174.07 4249.52 Day 28 32944.19 4194.31 Day 29 32945.24 4183.11 Day 30 33544.34 4252.45 Day 31 34063.10 4367.86 Day 32 34480.76 4421.67 Day 33 34754.93 4473.12 Day 34 34552.99 4471.18 Day 35 34807.46 4521.61 Day 36 34358.50 4466.24 Day 37 34707.94 4510.16 Day 38 34861.24 4553.06…1.542 1.585 1.532 1.466 1.499 1.611 1.598 1.498 1.6 1.504 1.545 1.558 1.622 1.466 1.546 1.494 1.548 1.626 1.555 1.712 1.442 1.443 1.699 1.701 1.44 1.608 1.52 1.478 1.542 1.511 1.698 1.88 1.11 1.21 1.987 1.39 1.459 1.533 1.532 1.523 1.397 1.487 Find a 99% CI on the mean tar content. Find the upper and lower limits.(Do not round off the values until you get the final answer)
- Calculate the point prevalence for Alzheimer’s disease among individuals 65 years of age or older in a county that has 200,000 individuals who are 65 years of age or older, if 22,223 individuals who are 65 years of age or older have the disease. 0.0111 0.1111 0.8889 0.9889S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with Alzheimer's. She obtains a sample of n% = 30 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 26.2 with a standard deviation of s = 2.97. In the general population of Alzheimer's patients, the standardized test is known to have a population mean of p= 28.1. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following,…19 1.328 1,/29 2.093 2.539 2.86T 19 20 1.325 1.725 2,086 2.528 2.845 20 21 1.323 1.721 2.080 2.518 2.831 21 22 1.321 1.717 2.074 2.508 2.819 22 23 1.319 1.714 2,069 2.500 2.807 23 24 1.318 1.711 2.064 2.492 2.797 24 25 1.316 1.708 2.060 2.485 2.787 25 26 1.315 1.706 2.056 2.479 2,779 26 27 1.314 1.703 2.052 2.473 2.771 27 28 1.313 1.701 2.048 2.467 2.763 28 29 1.311 1.699 2.045 2.462 2.756 29 30 1.310 1.697 2.042 2.457 2.750 30 31 1.309 1.696 2.040 2.453 2.744 31 32 1.309 1.694 2.037 2.449 2.738 32 33 1.308 1.692 2.035 2.445 2.733 33 34 1.307 1.691 2.032 2.441 2.728 34 35 1.306 1.690 2.030 2.438 2.724 35 36 1.306 1.688 2.028 2.434 2.719 36 37 1.305 1.687 2.026 2.431 2.715 37 38 1.304 1.686 2.024 2.429 2.712 38 39 1.304 1.685 2.023 2.426 2.708 39 40 1.303 1.684 2.021 2.423 2.704 40 45 1.301 1.679 2.014 2.412 2.690 45 50 1.299 1.676 2.009 2.403 2.678 50 60 1.296 1.671 2.000 2,390 2.660 60 70 1.294 1.667 1.994 2.381 2.648 70 80 1.292 1.664 1.990 2.374 2.639 80 90 1.291 1.662 1,987 2.368…
- 20171.18 46831.5 21789.85 4828.121 14684.72 -12813.6 24519.65 73135.66 29135.23 42180.99 2261.035 52749.12 41403.37 26760.47 32546.79 17728.36 -2407.25 39998.17 9780.605 45741.21 37178.78 33696.61 43259.29 26814.31 31291.52 37175.38 50136.51 55886.29 8696.373 30507.27 69778.96 52346.39 -13641.8 24661.96 9746.476 50024.07 78575.84 26692.57 38463.91 30145.11 40459.87 10816.03 14662.31 44380.93 34686.81 30315.94 18222.65 39422.52 43345.67 -2355.16 49109.01 21361.93 32708.77 50170.42 11337.63 36858.01 19704.15 34739.6 10822.38 -1332.56 70582.65 45813.68 27238.56 36232.78 29583.19 51432.22 70353.96 49991.42 37953.37 24107.22 19944.66 22744.9 31955.78 53442.8 36301.04 Spreadsheet 2determine the inequ4.764.724.744.554.914.744.784.714.804.784.784.754.794.824.914.834.684.744.704.804.704.764.704.834.934.744.844.824.764.774.724.784.834.754.744.684.844.714.714.764.664.784.734.744.924.774.804.794.864.644.784.704.754.784.764.834.664.774.834.784.694.814.684.784.884.724.854.854.814.744.804.824.844.704.854.704.814.724.794.63 What is the mean, median, and mode? (you may want to use your calculator or the average and median functions in Excel!) What could be some reasons for variation in the weights of the Kisses®? Note: Take time answering this one. There are lots of things to consider here and I'll be looking for a well thought out answer with several given reasons contributing to the variation. Of course, the wrappers and tags could vary but what about the drops of chocolate themselves? Why aren't they all the same? Would you say that there are any two Kisses that have exactly the same weight? (I mean exactly the same weight!) Explain why or why not. How many Kisses® were there in the…
- The term "snowstorms of note" applies to all snowfalls over 16 6 inches. The snowfall amounts for snowstorms of note in Utica, New York, over a four-year period are as follows: 7.1, 9.2, 8.0, 6.1, 14.4, 8.5, 6.1, 6.8, 7.7, 21.5, 6.7, 9.0, 8.4, 7.0, 11.5, 14.1, 9.5, 8.6 What are the mean and population standard deviation for these data, to the nearest hundredth? A mean = 9.46; standard deviation 3.74 B mean = 9.46; standard deviation = 3.85 C mean = 9.45; standard deviation =D3.74 D mean = 9.45; standard deviation 3.85 021 EducAide Sofware Inc. All rights reserved.Site 2 Site 4 Site 5 Deciduous 12.625 1.272727 1.4 1.40625 7.666667 Evergreen 28.45455 36.91304 3.954545 71.78571 61.03226 SD Site 1 Site 3 Site 1 Site 2 Site 3 Site 4 Site 5 Deciduous 17.03725 1.420627 1.505545 2.698379 7.348469 Evergreen 32.80355 23.91446 6.328148 103.3323 63.3848 Averages per site (+/-SD) 200 180 160 140 120 100 80 60 40 20 0 Bagworms in Evergreen & Deciduous Trees Site 1 Site 2 Site 3 Per Site Site 4 Deciduous Evergreen Site S 5How many digits should be removed from a 1000-digit number 2008... 2008 such that the sum of remaining digits is 2008?