The trihybrid e+f+g+/efg is test crossed to thể triplể lečessive elgle ollowing genotypes were obtained in the progeny: e*fg = 10; efg* = 2; ef g 103; efg = 28; e*fg* = 9; e'rg = 32; efg 7; e'rg = 2; "The odd gene is The gene order is The gene distance between e-f is The gene distance between f-g is The gene distance between e-g is
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- Consider the following dihybrid testcross: B/b • E/e × b/b • e/e For the progeny from this testcross, determine the relative proportions (from 0% to 100%) of each genotype if the two genes: a) are linked (dominant alleles in cis conformation) with no crossing over: Be/be: be/be: BE/be: bE/be: b) assort independently. B/b; E/e: B/b; e/e: b/b; E/e: b/b; e/e: c) are linked (dominant alleles in cis conformation) and 20 map units apart. Be/be: be/be: BE/be: bE/be:Mice of the genotypes A/A ; B/B ; C/C ; D/D ; S/S anda/a ; b/b ; c/c ; d/d ; s/s are crossed. The progeny are intercrossed. What phenotypes will be produced in the F2 andin what proportions? [The allele symbols stand for thefollowing: A = agouti, a = solid (nonagouti); B = blackpigment, b = brown; C = pigmented, c = albino; D =nondilution, d = dilution (milky color); S = unspotted,s = pigmented spots on white background.]A purple flowering, smooth seed dihybrid plant (genotype PpSs) is test crossed with a white flowering, wrinkled seed plant (genotype ppss). These produce progeny in the following numbers of four phenotypes: 24:76:74:26 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat). a) What is the genotype of the original dihybrid plant? Specify which alleles are on each chromosome of the purple flowering, smooth seed plant (i.e. AB/ab or Ab/aB). b) How many map units separate the colour and seed coat genes? Show your calculations.
- The e-gram (graph to the right of allelic ladder image) and above is from a woman. She has variations 14 and 15 at STR D3S1358. If she has children with a man who has variations 12 and 19 at the same STR, what are the possible combinations of variations that their children would have?In this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…The pedigree below shows the phenotypes of the ABO blood groups and Rhesus factors [positive (+) and negative (-)] for several members of a family. I (B+ AB- 1 2 3 4 II O- A+ В- B- AB+ A+ 1 2 4 5 6 a. What are the ABO blood group genotypes of individuals I-1 and I-2? b. Which child/ren of individual I-4 can donate blood to him? c. Which individual in the pedigree can donate blood to all the other individuals in the pedigree?
- (a) DdGGww x DDGgWw ow being (b) ddggWw x DdGgww (c) DdGgWw x DdggWw (d) DdGgWW x DdGgWW de 10. What phenotypes are expected and in what proportion from each of the following crosses? (Assume D, G and Ware dominant over d, g and w, respectively.) mo to esc Ils ovit 101 SUO hamnow brid Jesus 1860 88 HOW bildicion baild am lemon a Bal 101 mem nem lemonThe mother of a family with 10 children has blood typeRh+. She also has a very rare condition (elliptocytosis,phenotype E) that causes red blood cells to be oval rather than round in shape but that produces no adverseclinical effects. The father is Rh− (lacks the Rh+ antigen)and has normal red blood cells (phenotype e). The children are 1 Rh+ e, 4 Rh+ E, and 5 Rh− e. Information isavailable on the mother’s parents, who are Rh+ E andRh− e. One of the 10 children (who is Rh+ E) marriessomeone who is Rh+ e, and they have an Rh+ E child.a. Draw the pedigree of this whole family.b. Is the pedigree in agreement with the hypothesisthat the Rh+ allele is dominant and Rh− is recessive?c. What is the mechanism of transmission ofelliptocytosis?d. Could the genes governing the E and Rh phenotypesbe on the same chromosome? If so, estimate the mapdistance between them, and comment on your resultAssume that the trihybrid cross AABBrr x aabbRR is made in a plant species. Assume that A and B are dominant alleles, but there is no dominance effect of alleles at the R locus. a) How many different gametes are possible in the F1generation? What are the genotypes of these gametes? b) What is the probability of the parental aabbRR genotype in the F2 progeny? c) What proportion of the F2 progeny would be expected to be homozygous for all three genes?
- Radishes may be long, round, or oval, and they may bered, white, or purple. You cross a long, white variety witha round, red one and obtain an oval, purple F1. TheF2 shows nine phenotypic classes as follows: 9 long, red;15 long, purple; 19 oval, red; 32 oval, purple; 8 long,white; 16 round, purple; 8 round, white; 16 oval, white;and 9 round, red.a. Provide a genetic explanation of these results. Besure to define the genotypes and show the constitutionof the parents, the F1, and the F2.b. Predict the genotypic and phenotypic proportionsin the progeny of a cross between a long, purple radishand an oval, purple one.This pedigree consist of cystic fibrosis that is an inherited disease caused by f a recessive allele. Find the genotypes of X and M? Given: O normal female □ normal male ◍ cystic fibrosis female ▨ cystic fibrosis male A) M= Ff X=Ff B) M=Ff X=ff C) M=ff X=ff D) M=ff X=FFRadishes may be round, oval and lomg. Aside from this, they may be red, purple or white in color. Red x white produces progeny, all of which are purple. If purple oval will becrossed with purple oval, how many types of phenotypes will appear and If purple oval are crossed with white, long radishes, then what genotypic and phenotypicratios exist in the progeny? Indicate the phenotypes of the offspring.