The tower of Hanoi puzzle: B. Peg1 peg2 peg3 Initial state Peg1 peg2 peg3 goal state Objective: moving the disks (A, B, C) from peg1 to peg3 using peg2. - one disk can be moved at one time - Cannot put a disk on a smaller one Rules: Finda heuristic function for the above puzzle. Using the suggested heuristic function, show how the state space would look like. i. ii.

The tower of Hanoi puzzle: B. Peg1 peg2 peg3 Initial state Peg1 peg2 peg3 goal state Objective: moving the disks (A, B, C) from peg1 to peg3 using peg2. - one disk can be moved at one time - Cannot put a disk on a smaller one Rules: Finda heuristic function for the above puzzle. Using the suggested heuristic function, show how the state space would look like. i. ii.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Computer science. Correct answer will be upvoted else downvoted. Think about a n by n chessboard. Its columns are numbered from 1 to n from the top to the base. Its sections are numbered from 1 to n from the passed on to one side. A cell on a convergence of x-th line and y-th section is indicated (x,y). The fundamental corner to corner of the chessboard is cells (x,x) for all 1≤x≤n. A stage of {1,2,3,… ,n} is composed on the fundamental slanting of the chessboard. There is actually one number composed on every one of the cells. The issue is to segment the cells under and on the principle askew (there are by and large 1+2+… +n such cells) into n associated areas fulfilling the accompanying imperatives: Each district ought to be associated. That implies that we can move from any cell of a locale to some other cell of a similar area visiting just cells of a similar district and moving from a cell to a neighboring cell. The x-th area ought to contain cell on the fundamental…
业 In the 8 queens problem, you are to place 8 queens on the chessboard in such a way that no two queens attack each other. That is, there are no two queens on the same row, column, or diagonal. The picture above shows a near solution--the top left and bottom right queens attack each other. We want to solve this problem using the techniques of symbolic Al. First, we need states. What would the best choice be for states? Each queen and its position x Michigan, Illinois, Indiana, etc. How many queens we have placed so far A board with the positions of all the queens that have been placed so far 00 What would the start state be? A single queen's position Crouched, with fingers on the starting line Placing the first queen x An empty board What would the goal state be? CA board with 8 queens placed Ball in the back of the net The positions of all 8 queens A board with 8 queens placed, none attacking each otherv What would the best choice for "edges" or "moves" be? Tiktok Moving a queen from…
The DFA M = ({qo,, 95}, E, 6, 90, 91, 95}) with = {0, 1} is given by this table for the transition function 8. 80 90 * 91 92 90 95 92 92 94 91 93 93 94 94 94 91 *95 95 94 (a) Draw a transition diagram of M. Cross out any state(s) that we don't need. Now partition the set of states into two parts such that it is immediately clear that no state in the first set is equivalent to a state in the second set. (b) Find a minimum DFA equivalent to M.
The rook is a chess piece that may move any number of spaces either horizontally or vertically. Consider the “rooks problem” where we try to place 8 rooks on an 8x8 chess board in such a way that no pair attacks each other. a. How many different solutions are there to this?b. Suppose we place the rooks on the board one by one, and we care about the order in which we put them on the board. We still cannot place them in ways that attack each other. How many different full sequences of placing the rooks (ending in one of the solutions from a) are there?
Correct answer will be upvoted else downvoted. Computer science. Vasya concentrates on the properties of right triangles, and he utilizes a recipe that decides whether some triple of integers is Pythagorean. Lamentably, he has failed to remember the specific recipe; he recalls just that the recipe was some condition with squares. Along these lines, he concocted the accompanying equation: c=a2−b. Clearly, this isn't the right recipe to check if a triple of numbers is Pythagorean. Yet, amazingly, it really dealt with the triple (3,4,5): 5=32−4, thus, as indicated by Vasya's equation, it is a Pythagorean triple. When Vasya tracked down the right recipe (and comprehended that his equation is off-base), he pondered: what number of are there triples of integers (a,b,c) with 1≤a≤b≤c≤n to such an extent that they are Pythagorean both as per his equation and the genuine definition? He requested that you count these triples. Input The principal line contains one integer t…
Correct answer will be upvoted else downvoted. Computer science. in case there are two planes and a molecule is shot with rot age 3 (towards the right), the cycle is as per the following: (here, D(x) alludes to a solitary molecule with rot age x) the primary plane delivers a D(2) to the left and lets D(3) progress forward to the right; the subsequent plane delivers a D(2) to the left and lets D(3) progress forward to the right; the primary plane lets D(2) forge ahead to the left and creates a D(1) to the right; the subsequent plane lets D(1) progress forward to one side (D(1) can't create any duplicates). Altogether, the last multiset S of particles is {D(3),D(2),D(2),D(1)}. (See notes for visual clarification of this experiment.) Gaurang can't adapt up to the intricacy of the present circumstance when the number of planes is excessively huge. Help Gaurang find the size of the multiset S, given n and k. Since the size of the multiset can be extremely huge, you…
Correct answer will be upvoted else downvoted. Computer science. Positive integer x is called divisor of positive integer y, in case y is distinguishable by x without remaining portion. For instance, 1 is a divisor of 7 and 3 isn't divisor of 8. We gave you an integer d and requested that you track down the littlest positive integer a, to such an extent that a has no less than 4 divisors; contrast between any two divisors of an is essentially d. Input The primary line contains a solitary integer t (1≤t≤3000) — the number of experiments. The primary line of each experiment contains a solitary integer d (1≤d≤10000). Output For each experiment print one integer a — the response for this experiment.
Remaining Time: 2 hours, 27 minutes, 02 seconds. Duestion Completion Status: Y=A'. B' + (AOB) b. Using Karnaugh map, simplify the following Boolean function F (show your grouping): [2 Marks] A B C F 1 1 1 1 1 1 1 1 1 0. 1 1 1 1 1 1 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All A O Type here to search DLL FS F9 F10 F11 9 3 r 7 Y 8 W E R = G i JJ 立

Correct answer will be upvoted else downvoted. Computer science. There are n urban areas and m bidirectional streets in the country. The streets in the nation structure an undirected weighted chart. The diagram isn't destined to be associated. Every street has it's own boundary w. You can go through the streets, however the public authority made another law: you can just go through two streets all at once (go from city a to city b and afterward from city b to city c) and you should pay (wab+wbc)2 cash to go through those streets. See if it is feasible to go from city 1 to each and every other city t and what's the base measure of cash you really want to get from 1 to t. Input First line contains two integers n, m (2≤n≤105, 1≤m≤min(n⋅(n−1)2,2⋅105)). Next m lines each contain three integers vi, ui, wi (1≤vi,ui≤n, 1≤wi≤50, ui≠vi). It's dependable that there are no numerous edges, for example for any edge (ui,vi) there could be no different edges (ui,vi) or (vi,ui). Output…
Correct answer will be upvoted else Multiple Downvoted. Computer science. You are given an arrangement an of length n comprising of integers from 1 to n. The grouping may contain duplicates (for example a few components can be equal). Track down the number of tuples of m=3 components with the end goal that the maximum number in the tuple varies from the base by close to k=2. Formally, you want to view as the number of triples of lists i<j<z with the end goal that max(ai,aj,az)−min(ai,aj,az)≤2. For example, on the off chance that n=4 and a=[1,2,4,3], there are two such triples (i=1,j=2,z=4 and i=2,j=3,z=4). In the event that n=4 and a=[1,1,1,1], all four potential triples are suitable. Input The principal line contains a solitary integer t (1≤t≤2⋅105) — the number of experiments. Then, at that point, t experiments follow. The principal line of each experiment contains an integer n (1≤n≤2⋅105) — the length of the succession a. The following line contains n…
Newton is a brilliant mathematician and solving triangles problems fascinates him. Today he is given a sequence of positive integers V1, V2, .., VN. You must choose three elements Vx, Vy, Vz (x, y, z is vertices) such that the triangle formed have these properties: |XY|= Vz, |XZ|=Vy, |YZ|=Vx and the angle |ZYXZ|= 0 satisfies cose2P/Q, where 0 should be maximum possible. Find any such triangle or determine that it does not exist. Develop a python code which prints the value of x, y, z in a single line and print "Invalid" if not possible. Test Case: 412 5872 Result: 321
Correct answer will be upvoted else downvoted. Computer science. You are given three positive (more prominent than nothing) integers c, d and x. You need to track down the number of sets of positive integers (a,b) with the end goal that balance c⋅lcm(a,b)−d⋅gcd(a,b)=x holds. Where lcm(a,b) is the most un-normal various of an and b and gcd(a,b) is the best normal divisor of an and b. Input The primary line contains one integer t (1≤t≤104) — the number of experiments. Each experiment comprises of one line containing three integer c, d and x (1≤c,d,x≤107). Output For each experiment, print one integer — the number of sets (a,b) to such an extent that the above uniformity holds.