The index of refraction for material 1 is 1.36; for material 2 it is 1.66. Light travels 1.5 m in the firstmaterial before hitting the second material, where it travels another 1.5 m. What is the total timetaken for the light to travel the total distance? Speed of light c = 2.998 x 108 m/sTotal time in the two materials =SReflect on the order of magntitude of this time. Is this a perceptible time delay?

Answered: The index of refraction for material 1…

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter1: The Nature Of Light

Section: Chapter Questions

Problem 86AP: Unreasonable results Light traveling from water to a gemstone strikes the surface at an angle of...

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Similar questions

In what substance in Table 1.1 is the speed of light 2.290108 m/s?
Light passes from a material with index of refraction 1.3 into one with index of refraction 1.2. Compared with the incident ray, what happens to the refracted ray? (a) It bends toward the normal. (b) It is undeflected. (c) It bends away from the normal.
A light ray initially in water enters a transparent substance at an angle of incidence of 37.0, and the transmitted ray is refracted at an angle of 25.0. Calculate the speed of light in the transparent substance.
Light traveling in a medium of index of refraction n1 is incident on another medium having an index of refraction n2. Under which of the following conditions can total internal reflection occur at the interface of the two media? (a) The indices of refraction have the relation n2 n1. (b) The indices of refraction have the relation n1 n2. (c) Light travels slower in the second medium than in the first. (d) The angle of incidence is less than the critical angle. (e) The angle of incidence must equal the angle of refraction.
A light ray travels from vacuum into a slab of material with index of refraction n1 at incident angle θ with respect to the surface. It subsequently passes into a second slab of material with index of refraction n2 before passing back into vacuum again. The surfaces of the different materials are all parallel to one another. As the light exits the second slab, what can be said of the final angle ϕ that the outgoing light makes with the normal? (a) ϕ > θ (b) ϕ < θ (c) ϕ = θ (d) The angle depends on the magnitudes of n1 and n2. (e) The angle depends on the wavelength of the light.
A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.50) at ail angle of 30.0 with respect to the normal (Fig. P22.18). (a) Find the angle of refraction at the lop surface. (b) Find the angle of incidence at the bottom surface and the refracted angle. (c) Find the lateral distance d by which the light beam is shifted. (d) Calculate the speed of light in the glass and (e) the time required for the light to pass through the glass block. (f) Is the travel time through the block affected by the angle of incidence? Explain.
Consider a beam of light from the left entering a prism of apex angle as shown in Figure P34.34. Two angles of incidence, 1, and 3, are shown as Hell as two angles of refraction, 2 and 4. Show that = 1 + 3. Figure P34.34
Light is incident on a prism as shown in Figure P38.31. The prism, an equilateral triangle, is made of plastic with an index of refraction of 1.46 for red light and 1.49 for blue light. Assume the apex angle of the prism is 60.00. a. Sketch the approximate paths of the rays for red and blue light as they travel through and then exit the prism. b. Determine the measure of dispersion, the angle between the red and blue rays that exit the prism. Figure P38.31
Unreasonable results Light traveling from water to a gemstone strikes the surface at an angle of 80.00 and has an angle of refraction of 15.2°. (a) What is the speed of light in the gemstone? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?
Pierre de Fermat (16011665) showed that whenever light travels from one point to another, its actual path is the path that requires the smallest time interval. This statement is known as Fermats principle. The simplest example is for light propagating in a homogeneous medium. It moves in a straight line because a straight line is the shortest distance between two points. Derive Snells law of refraction from Fermats principle. Proceed as follows. In Figure P34.54, a light ray travels from point P in medium 1 to point Q in medium 2. The two points are, respectively, at perpendicular distances a and b from the interface. The displacement from P to Q has the component d parallel to the interface, and we let x represent the coordinate of the point where the ray enters the second medium. Let t = 0 be the instant the light starts from P. (a) Show that the time at which the light arrives at Q is t=r1v1+r2v2=n1a2+x2c+n2b2+(dx)2c (b) To obtain the value of x for which t has its minimum value, differentiate t with respect to x and set the derivative equal to zero. Show that the result implies n1xa2+x2=n2(dx)b2+(dx)2 (c) Show that this expression in turn gives Snells law. n1sin1=n2sin2 Figure P34.54 Problems 54 and 55.
How many times will the incident beam in Figure P34.33 (page 922) be reflected by each of the parallel mirrors? Figure P34.33
For specular reflection, what is the situation with an angle of incidence of (a) 0 and (b) 90?

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