The homogeneous box has mass m. The magnitude of force P is slowly increased until motion occurs. Motion could Occur as slipping or tipping and you must decide which occurs first. Find the value of P which first causes motion. A 30° (Hs= 0.40 B 2.2 d Answer: P = i mg
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- The block of weight W is pulled by the force P inclined at the angle to the horizontal. Find the smallest force P and the corresponding angle that would cause impending sliding of the block. The angle of static friction between the block and the ground is s.The uniform 240-lb bar AB is held in the position shown by the cable AC. Compute the tension in the cable.Draw the FBD for the bar described in Prob. 5.1 if the bar is homogeneous of mass 50 kg. Count the unknowns.
- The homogeneous plate of weight W is suspended from two cables. Determine the force P that is necessary to keep the plate in the position shown.The 40-kghomogeneous disk is placed on a frictionless inclined surface and held in equilibrium by the horizontal force P and a couple C (C is not shown on the figure). Find P and C.If PCD=6000lb and PGD=1000lb (both compression), find P and Q.
- The bar ABC is supported by three identical, ideal springs. Note that the springs are always vertical because the collars to which they are attached are free to slide on the horizontal rail. Find the angle at equilibrium if W = kL. Neglect the weight of the bar.The center of gravity of the 3000-lb car is at G. The car is parked on an incline with the parking brake engaged, which locks the rear wheels. Find (a) the normal forces (perpendicular to the incline) acting under the front and rear pairs of wheels; and (b) the friction force (parallel to the incline) under the rear pair of wheels.The homogeneous box has mass m. The magnitude of force P is slowly increased until motion occurs. Motion could occur as slipping or tipping and you must decide which occurs first. Find the value of P which first causes motion. A 26° d He= 0.53 B 1.6 d Answer: P = i mg
- Two bodies is connected in point C, are supported by rigid underlay at an angle α. F is the force acting on right body. We are considering the weight of bodies G and the friction between the bodies and the underlay. Length of bodies l=2000mm. G1= 160 N, G2= 180 N, α = 30° Find: 1.) Find the magnitude of the force so that it slips on the underlay 2.) Draw the dependence of the force F as a function of the coefficient of friction f (in the range 0-0.5)The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. Response